{"id":195978,"date":"2025-03-01T17:19:21","date_gmt":"2025-03-01T17:19:21","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=195978"},"modified":"2025-03-01T17:20:23","modified_gmt":"2025-03-01T17:20:23","slug":"the-correct-molar-mass-for-nitrous-oxide","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/01\/the-correct-molar-mass-for-nitrous-oxide\/","title":{"rendered":"The Correct Molar Mass For Nitrous Oxide"},"content":{"rendered":"\n<p>The Correct Molar Mass For Nitrous Oxide, N2O Is Given By: A. 44.02 G\/Mole B. 30.01 G\/Mole C. 60.02 G\/Mole 40 D .02 G\/Mole E .46.01 G\/Mole<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The Correct Answer and Explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>The correct molar mass for Nitrous Oxide (N\u2082O) is <strong>A. 44.02 g\/mol<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>The molar mass of a compound is determined by adding the atomic masses of the elements that make up the compound. In the case of Nitrous Oxide (N\u2082O), it consists of two nitrogen (N) atoms and one oxygen (O) atom.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Atomic Mass of Nitrogen (N)<\/strong>: The atomic mass of nitrogen is approximately <strong>14.01 g\/mol<\/strong>.<\/li>\n\n\n\n<li><strong>Atomic Mass of Oxygen (O)<\/strong>: The atomic mass of oxygen is approximately <strong>16.00 g\/mol<\/strong>.<\/li>\n<\/ol>\n\n\n\n<p>Now, let&#8217;s calculate the molar mass of N\u2082O:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Since there are two nitrogen atoms, their combined mass is:<br>[<br>2 \\times 14.01 = 28.02 \\, \\text{g\/mol}<br>]<\/li>\n\n\n\n<li>The mass of the single oxygen atom is:<br>[<br>16.00 \\, \\text{g\/mol}<br>]<\/li>\n\n\n\n<li>Adding these together gives the molar mass of Nitrous Oxide (N\u2082O):<br>[<br>28.02 \\, \\text{g\/mol} + 16.00 \\, \\text{g\/mol} = 44.02 \\, \\text{g\/mol}<br>]<\/li>\n<\/ul>\n\n\n\n<p>Thus, the molar mass of N\u2082O is <strong>44.02 g\/mol<\/strong>, which corresponds to <strong>Option A<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Why Other Options are Incorrect:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Option B (30.01 g\/mol)<\/strong>: This value would correspond to a compound with a different atomic composition than N\u2082O.<\/li>\n\n\n\n<li><strong>Option C (60.02 g\/mol)<\/strong>: This mass would be too high for N\u2082O, suggesting a compound with more atoms of nitrogen or oxygen.<\/li>\n\n\n\n<li><strong>Option D (40.02 g\/mol)<\/strong>: This value is close, but slightly lower than the actual molar mass of N\u2082O.<\/li>\n\n\n\n<li><strong>Option E (46.01 g\/mol)<\/strong>: This value is slightly higher than the actual molar mass of N\u2082O, indicating an incorrect atomic combination.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Final Answer:<\/h3>\n\n\n\n<p>Therefore, the correct answer is <strong>A. 44.02 g\/mol<\/strong>.<\/p>\n\n\n\n<p>Now, I will generate an image to visually represent this calculation.<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img decoding=\"async\" src=\"https:\/\/files.oaiusercontent.com\/file-2sLw4xXsD8rK3aFVrySUpX?se=2025-03-01T17%3A19%3A52Z&amp;sp=r&amp;sv=2024-08-04&amp;sr=b&amp;rscc=max-age%3D604800%2C%20immutable%2C%20private&amp;rscd=attachment%3B%20filename%3Db8a358f6-5de2-44c6-9699-c77c4e1a7f34.webp&amp;sig=nQtWfZRya9Hci7klOBxdPhk6VTX1ZuWng\/842FHKMuI%3D\" alt=\"\"\/><\/figure>\n\n\n\n<p>Here is the image showing the calculation of the molar mass of Nitrous Oxide (N\u2082O). It includes the molecular formula, atomic masses, and a step-by-step breakdown of the calculation, leading to the correct molar mass of <strong>44.02 g\/mol<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>The Correct Molar Mass For Nitrous Oxide, N2O Is Given By: A. 44.02 G\/Mole B. 30.01 G\/Mole C. 60.02 G\/Mole 40 D .02 G\/Mole E .46.01 G\/Mole The Correct Answer and Explanation is : The correct molar mass for Nitrous Oxide (N\u2082O) is A. 44.02 g\/mol. Explanation: The molar mass of a compound is determined [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-195978","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/195978","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=195978"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/195978\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=195978"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=195978"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=195978"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}