{"id":196578,"date":"2025-03-05T13:22:49","date_gmt":"2025-03-05T13:22:49","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=196578"},"modified":"2025-03-05T13:22:52","modified_gmt":"2025-03-05T13:22:52","slug":"complete-the-statement-about-the-redox-reaction","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/05\/complete-the-statement-about-the-redox-reaction\/","title":{"rendered":"complete the statement about the redox reaction"},"content":{"rendered":"\n<p>complete the statement about the redox reaction below: Al3+(aq)+2Ag(s)+CL-(aq)&#8212;-Al(s)+3AgCl(s)<\/p>\n\n\n\n<p>_is being oxidized. ___ is being reduced. <em>is acting as an reducing agent.<\/em> is acting as an oxidizing agent. _________moles of electrons are transferred. the reaction is an _________cell<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Complete the statement:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Silver (Ag)<\/strong> is being <strong>oxidized<\/strong>.<\/li>\n\n\n\n<li><strong>Aluminum ion (Al\u00b3\u207a)<\/strong> is being <strong>reduced<\/strong>.<\/li>\n\n\n\n<li><strong>Silver (Ag)<\/strong> is acting as a <strong>reducing agent<\/strong>.<\/li>\n\n\n\n<li><strong>Aluminum ion (Al\u00b3\u207a)<\/strong> is acting as an <strong>oxidizing agent<\/strong>.<\/li>\n\n\n\n<li><strong>3 moles<\/strong> of electrons are transferred.<\/li>\n\n\n\n<li>The reaction is an <strong>electrochemical cell (galvanic or voltaic cell)<\/strong>.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>A redox (reduction-oxidation) reaction involves the transfer of electrons from one species to another. In this reaction:<\/p>\n\n\n\n<p>[<br>\\text{Al}^{3+}(aq) + 2Ag(s) + Cl^-(aq) \\rightarrow \\text{Al}(s) + 3AgCl(s)<br>]<\/p>\n\n\n\n<p>we analyze the oxidation states of each species:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Al\u00b3\u207a (aq)<\/strong>: The aluminum ion has a <strong>+3 oxidation state<\/strong>.<\/li>\n\n\n\n<li><strong>Ag (s)<\/strong>: Silver is in its elemental form, so its oxidation state is <strong>0<\/strong>.<\/li>\n\n\n\n<li><strong>Cl\u207b (aq)<\/strong>: Chloride ion remains <strong>-1<\/strong> in the reaction.<\/li>\n\n\n\n<li><strong>Al (s)<\/strong>: Aluminum in solid form has an oxidation state of <strong>0<\/strong>.<\/li>\n\n\n\n<li><strong>AgCl (s)<\/strong>: Silver chloride consists of <strong>Ag\u207a<\/strong> and <strong>Cl\u207b<\/strong>, where silver has an oxidation state of <strong>+1<\/strong>.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Identifying Oxidation and Reduction:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Oxidation<\/strong> is the <strong>loss of electrons<\/strong>. In this reaction, <strong>silver (Ag) is oxidized<\/strong> as it goes from <strong>Ag (0) \u2192 Ag\u207a (+1)<\/strong> in AgCl.<\/li>\n\n\n\n<li><strong>Reduction<\/strong> is the <strong>gain of electrons<\/strong>. <strong>Al\u00b3\u207a gains electrons<\/strong> to become <strong>Al (0)<\/strong>, meaning aluminum ions are reduced.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Agents:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The <strong>reducing agent<\/strong> is the substance that <strong>loses electrons<\/strong>. Here, <strong>Ag (silver) loses electrons<\/strong>, making it the <strong>reducing agent<\/strong>.<\/li>\n\n\n\n<li>The <strong>oxidizing agent<\/strong> is the substance that <strong>gains electrons<\/strong>. Here, <strong>Al\u00b3\u207a gains electrons<\/strong>, making it the <strong>oxidizing agent<\/strong>.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Number of Electrons Transferred:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Since Al\u00b3\u207a is reduced by gaining <strong>3 electrons<\/strong> to become Al(s), and each Ag atom loses <strong>1 electron<\/strong>, a total of <strong>3 moles of electrons<\/strong> are transferred.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Type of Electrochemical Cell:<\/h3>\n\n\n\n<p>This is an <strong>electrochemical (galvanic) cell<\/strong> because it is a <strong>spontaneous reaction<\/strong>, generating electrical energy.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p>Now, I will generate an image representing this redox reaction.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/03\/image-231.png\" alt=\"\" class=\"wp-image-196579\"\/><\/figure>\n\n\n\n<p>Here is an illustrated diagram of the redox reaction, showing the oxidation and reduction processes, electron transfer, and the roles of the oxidizing and reducing agents. Let me know if you need any modifications or further explanations!<\/p>\n","protected":false},"excerpt":{"rendered":"<p>complete the statement about the redox reaction below: Al3+(aq)+2Ag(s)+CL-(aq)&#8212;-Al(s)+3AgCl(s) _is being oxidized. ___ is being reduced. is acting as an reducing agent. is acting as an oxidizing agent. _________moles of electrons are transferred. the reaction is an _________cell The correct answer and explanation is : Complete the statement: Explanation: A redox (reduction-oxidation) reaction involves the [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-196578","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/196578","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=196578"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/196578\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=196578"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=196578"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=196578"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}