{"id":196786,"date":"2025-03-05T20:38:14","date_gmt":"2025-03-05T20:38:14","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=196786"},"modified":"2025-03-05T20:38:25","modified_gmt":"2025-03-05T20:38:25","slug":"using-64-x-8-rom-chips-with-an-enable-input","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/05\/using-64-x-8-rom-chips-with-an-enable-input\/","title":{"rendered":"Using 64 \u00d7 8 ROM chips with an enable input"},"content":{"rendered":"\n<p>Using 64 \u00d7 8 ROM chips with an enable input, construct a 512 \u00d7 8 ROM with eight chips and a decoder.<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Constructing a 512 \u00d7 8 ROM Using 64 \u00d7 8 ROM Chips and a Decoder<\/strong><\/h3>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Solution<\/strong><\/h4>\n\n\n\n<p>To construct a <strong>512 \u00d7 8 ROM<\/strong> using <strong>64 \u00d7 8 ROM<\/strong> chips, we need to meet the requirement of storing <strong>512 words<\/strong> of <strong>8-bit<\/strong> data.<\/p>\n\n\n\n<p>Each <strong>64 \u00d7 8 ROM<\/strong> chip can store <strong>64 words<\/strong> (or addresses), each being <strong>8 bits wide<\/strong>. To reach <strong>512 words<\/strong>, we divide:<\/p>\n\n\n\n<p>[<br>512 \\div 64 = 8<br>]<\/p>\n\n\n\n<p>Thus, <strong>eight (8) ROM chips<\/strong> are required.<\/p>\n\n\n\n<p>To select one of the eight chips at a time, we need a <strong>3-to-8 decoder<\/strong> since:<\/p>\n\n\n\n<p>[<br>2^3 = 8<br>]<\/p>\n\n\n\n<p>The three <strong>most significant address lines (A6, A7, A8)<\/strong> from the 9-bit address bus (since ( 2^9 = 512 )) are used as inputs to this <strong>3-to-8 decoder<\/strong>. The decoder activates exactly <strong>one of the eight ROM chips<\/strong> at a time through its <strong>chip enable (CE) input<\/strong>.<\/p>\n\n\n\n<p>Each ROM chip receives the <strong>lower six address lines (A0 &#8211; A5)<\/strong> as input to access one of its <strong>64 memory locations<\/strong>. The <strong>output data buses of all ROM chips<\/strong> are <strong>connected together<\/strong> in a shared <strong>tri-state<\/strong> configuration, meaning only the selected ROM will place data on the bus.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Connections:<\/strong><\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Address Bus (9-bit)<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>A0 &#8211; A5<\/strong> go to all ROM chips.<\/li>\n\n\n\n<li><strong>A6 &#8211; A8<\/strong> go to the 3-to-8 decoder.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Decoder<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Takes A6, A7, A8 as inputs.<\/li>\n\n\n\n<li>Outputs are connected to the <strong>chip enable (CE)<\/strong> of each ROM chip.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Data Bus (8-bit)<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Outputs of all ROM chips are tied together in tri-state mode.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Control Lines<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Common read and write control lines.<\/li>\n<\/ul>\n\n\n\n<p>This setup ensures that at any moment, <strong>only one ROM chip is active<\/strong>, enabling access to the full <strong>512 \u00d7 8 memory<\/strong>.<\/p>\n\n\n\n<p>Now, I will generate an image illustrating this configuration.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/03\/image-295.png\" alt=\"\" class=\"wp-image-196794\"\/><\/figure>\n\n\n\n<p>Here is the digital circuit diagram illustrating the construction of a 512 \u00d7 8 ROM using eight 64 \u00d7 8 ROM chips and a 3-to-8 decoder.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Using 64 \u00d7 8 ROM chips with an enable input, construct a 512 \u00d7 8 ROM with eight chips and a decoder. The correct answer and explanation is : Constructing a 512 \u00d7 8 ROM Using 64 \u00d7 8 ROM Chips and a Decoder Solution To construct a 512 \u00d7 8 ROM using 64 \u00d7 [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-196786","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/196786","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=196786"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/196786\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=196786"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=196786"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=196786"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}