{"id":196965,"date":"2025-03-06T10:50:46","date_gmt":"2025-03-06T10:50:46","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=196965"},"modified":"2025-03-06T10:50:48","modified_gmt":"2025-03-06T10:50:48","slug":"what-is-the-hybridization-of-the-central-atom-in-nocl-3","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/06\/what-is-the-hybridization-of-the-central-atom-in-nocl-3\/","title":{"rendered":"What is the hybridization of the central atom in NOCl"},"content":{"rendered":"\n
What is the hybridization of the central atom in NOCl? Hybridization- What are the approximate bond angles in this Bond angles substance<\/p>\n\n\n\n
The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n
Hybridization of the Central Atom in NOCl and Bond Angles<\/strong><\/h3>\n\n\n\n
The hybridization of the central atom (N) in NOCl<\/strong> is sp\u00b2<\/strong>.<\/p>\n\n\n\n
Determine the Central Atom:<\/strong><\/li>\n<\/ol>\n\n\n\n
\n
In NOCl (Nitrosyl chloride)<\/strong>, Nitrogen (N)<\/strong> is the central atom since Oxygen (O) and Chlorine (Cl) are more electronegative.<\/li>\n<\/ul>\n\n\n\n\n
Count the Valence Electrons:<\/strong><\/li>\n<\/ol>\n\n\n\n
Lewis Structure and Lone Pairs:<\/strong><\/li>\n<\/ol>\n\n\n\n
\n
Nitrogen forms a double bond with Oxygen<\/strong> and a single bond with Chlorine<\/strong>.<\/li>\n\n\n\n
Nitrogen has one lone pair<\/strong> of electrons.<\/li>\n<\/ul>\n\n\n\n\n
Steric Number Calculation:<\/strong><\/li>\n<\/ol>\n\n\n\n
\n
Steric number = Number of bonded atoms + Number of lone pairs<\/strong>.<\/li>\n\n\n\n
Nitrogen is bonded to two atoms (O and Cl)<\/strong> and has one lone pair<\/strong>.<\/li>\n\n\n\n
Steric number = 3<\/strong> \u2192 Corresponds to sp\u00b2 hybridization<\/strong>.<\/li>\n<\/ul>\n\n\n\n\n
Bond Angles:<\/strong><\/li>\n<\/ol>\n\n\n\n
\n
In sp\u00b2 hybridization<\/strong>, the ideal bond angle is 120\u00b0<\/strong>.<\/li>\n\n\n\n
However, due to lone pair repulsion<\/strong>, the actual bond angle is slightly less than 120\u00b0<\/strong>.<\/li>\n<\/ul>\n\n\n\n
Final Answer:<\/strong><\/h3>\n\n\n\n
\n
Hybridization of N in NOCl = sp\u00b2<\/strong><\/li>\n\n\n\n
Bond angles \u2248 115\u00b0 – 120\u00b0<\/strong> (due to lone pair repulsion)<\/li>\n<\/ul>\n\n\n\n
Molecular Geometry:<\/strong><\/h4>\n\n\n\n
\n
The shape of NOCl is bent<\/strong> (angular) because of the lone pair on nitrogen.<\/li>\n<\/ul>\n\n\n\n\n\n\n\n
Now, I will generate an image<\/strong> illustrating the hybridization, Lewis structure, and bond angles<\/strong> of NOCl<\/strong>.<\/p>\n\n\n\n<\/figure>\n\n\n\n
Here is the molecular structure diagram of Nitrosyl Chloride (NOCl)<\/strong> showing its sp\u00b2 hybridization, bond angles (~120\u00b0), and lone pairs<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"
What is the hybridization of the central atom in NOCl? Hybridization- What are the approximate bond angles in this Bond angles substance The correct answer and explanation is : Hybridization of the Central Atom in NOCl and Bond Angles The hybridization of the central atom (N) in NOCl is sp\u00b2. Step-by-Step Explanation: Final Answer: Molecular […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-196965","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/196965","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=196965"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/196965\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=196965"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=196965"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=196965"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}
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