{"id":197593,"date":"2025-03-07T12:31:29","date_gmt":"2025-03-07T12:31:29","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=197593"},"modified":"2025-03-07T12:31:32","modified_gmt":"2025-03-07T12:31:32","slug":"what-is-the-hybridization-of-the-central-atom-in-nocl-5","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/07\/what-is-the-hybridization-of-the-central-atom-in-nocl-5\/","title":{"rendered":"What is the hybridization of the central atom in NOCl"},"content":{"rendered":"\n<p>What is the hybridization of the central atom in NOCl? Hybridization =<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>The hybridization of the central atom in NOCl (Nitrosyl chloride) is <strong>sp\u00b2<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>In NOCl, the central atom is <strong>nitrogen (N)<\/strong>. To determine its hybridization, we need to look at the number of bonding regions and lone pairs around nitrogen.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Electron Domain Count<\/strong>:<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Nitrogen is bonded to one oxygen (O) atom through a double bond and one chlorine (Cl) atom through a single bond. These two bonds count as two electron domains around nitrogen.<\/li>\n\n\n\n<li>Nitrogen also has one lone pair of electrons. This lone pair also counts as an electron domain.<\/li>\n<\/ul>\n\n\n\n<p>So, nitrogen has <strong>3 regions of electron density<\/strong> around it (2 bonds + 1 lone pair).<\/p>\n\n\n\n<ol start=\"2\" class=\"wp-block-list\">\n<li><strong>Hybridization<\/strong>:<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>When there are three regions of electron density, the hybridization of the central atom is <strong>sp\u00b2<\/strong>. This means nitrogen will have three sp\u00b2 hybrid orbitals: two of these orbitals form sigma bonds (one with oxygen and one with chlorine), and the third orbital holds the lone pair of electrons.<\/li>\n\n\n\n<li>The remaining p orbital (which is unhybridized) participates in the formation of a \u03c0 bond with oxygen.<\/li>\n<\/ul>\n\n\n\n<ol start=\"2\" class=\"wp-block-list\">\n<li><strong>Geometry<\/strong>:<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>With sp\u00b2 hybridization, the geometry around nitrogen is <strong>trigonal planar<\/strong>, which means the bond angles between the atoms are approximately 120\u00b0.<\/li>\n<\/ul>\n\n\n\n<p>Thus, the nitrogen atom in NOCl adopts sp\u00b2 hybridization due to its three electron domains, and this gives it a trigonal planar geometry.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/03\/image-518.png\" alt=\"\" class=\"wp-image-197594\"\/><\/figure>\n\n\n\n<p>Here is the image illustrating the molecular structure of Nitrosyl chloride (NOCl) with the central nitrogen atom&#8217;s sp\u00b2 hybridization. The structure shows nitrogen bonded to oxygen with a double bond, chlorine with a single bond, and a lone pair on nitrogen. The geometry is trigonal planar, as expected for sp\u00b2 hybridized atoms.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>What is the hybridization of the central atom in NOCl? Hybridization = The correct answer and explanation is : The hybridization of the central atom in NOCl (Nitrosyl chloride) is sp\u00b2. Explanation: In NOCl, the central atom is nitrogen (N). To determine its hybridization, we need to look at the number of bonding regions and [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-197593","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/197593","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=197593"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/197593\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=197593"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=197593"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=197593"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}