{"id":197717,"date":"2025-03-07T14:32:55","date_gmt":"2025-03-07T14:32:55","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=197717"},"modified":"2025-03-07T14:32:57","modified_gmt":"2025-03-07T14:32:57","slug":"what-is-the-molecular-shape-of-a-silicon-dioxide-molecule","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/07\/what-is-the-molecular-shape-of-a-silicon-dioxide-molecule\/","title":{"rendered":"What is the molecular shape of a silicon dioxide molecule"},"content":{"rendered":"\n

What is the molecular shape of a silicon dioxide molecule, SiO2? Select one: a. tetrahedral b. linear c. trigonal pyramidal d. trigonal planar e. bent<\/p>\n\n\n\n

The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n

The correct answer is b. linear<\/strong>.<\/p>\n\n\n\n

Explanation:<\/h3>\n\n\n\n

Silicon dioxide (SiO\u2082) is a molecule consisting of silicon (Si) atoms covalently bonded to oxygen (O) atoms. The molecular shape of SiO\u2082 is determined by the arrangement of atoms in the molecule and the bonding between them.<\/p>\n\n\n\n

SiO\u2082 is often found in a network structure, such as in quartz, where each silicon atom is bonded to four oxygen atoms in a tetrahedral arrangement. However, when we refer to a “SiO\u2082 molecule,” particularly in terms of molecular geometry, we consider the simplest representation of the molecule, which is a dimeric unit consisting of two silicon atoms bonded to two oxygen atoms.<\/p>\n\n\n\n

Key Points in the Structure of SiO\u2082:<\/h3>\n\n\n\n
    \n
  1. Bonding<\/strong>: In the simplest molecular form, SiO\u2082 can be thought of as having a linear structure. Each silicon atom is bonded to two oxygen atoms, with the oxygen atoms also being bonded to one another. The Si-O-Si bond angle in this arrangement is 180\u00b0, giving the molecule a linear geometry.<\/li>\n\n\n\n
  2. Electron Domains and Geometry<\/strong>: Each silicon atom in SiO\u2082 typically forms two sigma bonds with oxygen atoms and has no lone pairs, making the geometry around each silicon atom linear according to VSEPR (Valence Shell Electron Pair Repulsion) theory. Oxygen atoms in SiO\u2082, on the other hand, form bonds but do not have lone pairs contributing to the molecular geometry.<\/li>\n\n\n\n
  3. Network vs Molecular Form<\/strong>: While SiO\u2082 is commonly seen in a network (like in quartz), which has a three-dimensional tetrahedral structure, when considering the molecular form of SiO\u2082, it adopts a linear shape as a molecule.<\/li>\n<\/ol>\n\n\n\n

    In summary, when you consider the molecule SiO\u2082, the simplest molecular shape is linear<\/strong>, and this choice corresponds to the correct answer.<\/p>\n","protected":false},"excerpt":{"rendered":"

    What is the molecular shape of a silicon dioxide molecule, SiO2? Select one: a. tetrahedral b. linear c. trigonal pyramidal d. trigonal planar e. bent The correct answer and explanation is : The correct answer is b. linear. Explanation: Silicon dioxide (SiO\u2082) is a molecule consisting of silicon (Si) atoms covalently bonded to oxygen (O) […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-197717","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/197717","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=197717"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/197717\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=197717"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=197717"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=197717"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}