propynefrom ethyne Propene from propyne 1-bromopropene from propyn Propanone from propyne<\/p>\n\n\n\n
The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n The following transformations can be made step by step starting from ethyne (acetylene), and through various intermediate compounds leading to propanone. Let’s go through each transformation one by one.<\/p>\n\n\n\n Ethyne (C\u2082H\u2082), also known as acetylene, is a simple alkyne with a triple bond between two carbon atoms. To convert ethyne to propyne (C\u2083H\u2084), we typically add a methyl group (-CH\u2083) to ethyne. This can be done by a methylation reaction<\/strong>, such as:<\/p>\n\n\n\n Ethyne (C\u2082H\u2082) + CH\u2083MgBr \u2192 Propyne (C\u2083H\u2084)<\/strong><\/p>\n\n\n\n The Grignard reagent (CH\u2083MgBr) adds a methyl group to the triple-bonded carbon in ethyne, resulting in propyne (methylacetylene).<\/p>\n\n\n\n Propyne (C\u2083H\u2084) is an alkyne with a triple bond. To reduce this triple bond to a double bond and form propene (C\u2083H\u2086), we use a hydrogenation reaction<\/strong>. This is done using a catalyst like palladium (Pd) or platinum (Pt), which adds hydrogen across the triple bond, converting propyne into propene.<\/p>\n\n\n\n Propyne (C\u2083H\u2084) + H\u2082 (with Pd or Pt catalyst) \u2192 Propene (C\u2083H\u2086)<\/strong><\/p>\n\n\n\n The conversion of propene (C\u2083H\u2086) to 1-bromopropene (C\u2083H\u2085Br) can be achieved by an electrophilic addition<\/strong> of HBr. The double bond in propene undergoes addition with HBr to form the bromoalkene. Since HBr adds to the more substituted carbon in propene (Markovnikov’s rule), the product will be 1-bromopropene.<\/p>\n\n\n\n Propene (C\u2083H\u2086) + HBr \u2192 1-Bromopropene (C\u2083H\u2085Br)<\/strong><\/p>\n\n\n\n Propene (C\u2083H\u2086) can be oxidized to propanone (C\u2083H\u2086O) using an oxidation reaction<\/strong>. This typically involves a reaction with ozone (O\u2083) followed by mild hydrolysis or using other reagents like potassium permanganate (KMnO\u2084) under oxidative conditions. The oxidation breaks the double bond and introduces a carbonyl group, forming propanone.<\/p>\n\n\n\n Propene (C\u2083H\u2086) + O\u2083 \u2192 Propanone (C\u2083H\u2086O)<\/strong><\/p>\n\n\n\n These reactions involve common organic reactions such as addition, reduction, and oxidation. The transformation from ethyne to propyne requires a methylation step. Propyne can be hydrogenated to form propene, a simple alkene, and the addition of HBr to propene follows Markovnikov’s rule to form 1-bromopropene. Finally, propene undergoes oxidation to form propanone, which is a ketone with a carbonyl group (C=O). These steps illustrate the versatility of alkynes and alkenes in organic synthesis.<\/p>\n","protected":false},"excerpt":{"rendered":" propynefrom ethyne Propene from propyne 1-bromopropene from propyn Propanone from propyne The correct answer and explanation is : The following transformations can be made step by step starting from ethyne (acetylene), and through various intermediate compounds leading to propanone. Let’s go through each transformation one by one. 1. From Ethyne to Propyne: Ethyne (C\u2082H\u2082), also […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-197959","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/197959","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=197959"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/197959\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=197959"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=197959"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=197959"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}1. From Ethyne to Propyne:<\/strong><\/h3>\n\n\n\n
2. From Propyne to Propene:<\/strong><\/h3>\n\n\n\n
3. From Propene to 1-Bromopropene:<\/strong><\/h3>\n\n\n\n
4. From Propene to Propanone:<\/strong><\/h3>\n\n\n\n
Explanation:<\/h3>\n\n\n\n