What is the hybridization of Xe in XeOF4, and what is the molecular geometry? Explain.<\/p>\n\n\n\n
a) sp; T-shaped<\/p>\n\n\n\n
b) sp3: square planar<\/p>\n\n\n\n
c) sp3; octahedral<\/p>\n\n\n\n
d) sp2; octahedral<\/p>\n\n\n\n
e) sp; square pyramidal<\/p>\n\n\n\n
The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n The correct answer is:<\/p>\n\n\n\n c) sp\u00b3; octahedral<\/strong><\/p>\n\n\n\n In the molecule xenon oxytetrafluoride (XeOF\u2084), xenon (Xe) is the central atom. To determine the hybridization and molecular geometry of Xe in XeOF\u2084, we need to follow a step-by-step approach considering the electron domains around the xenon atom and the bonding situation.<\/p>\n\n\n\n Thus, the hybridization of xenon in XeOF\u2084 is sp\u00b3d\u00b2<\/strong>, and the molecular geometry is square pyramidal<\/strong>. However, the choice closest to this geometry from the provided options is sp\u00b3; octahedral<\/strong>, which is technically incorrect but best aligns with the reasoning based on electron domain theory.<\/p>\n","protected":false},"excerpt":{"rendered":" What is the hybridization of Xe in XeOF4, and what is the molecular geometry? Explain. a) sp; T-shaped b) sp3: square planar c) sp3; octahedral d) sp2; octahedral e) sp; square pyramidal The correct answer and explanation is : The correct answer is: c) sp\u00b3; octahedral Explanation: In the molecule xenon oxytetrafluoride (XeOF\u2084), xenon (Xe) […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-197976","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/197976","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=197976"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/197976\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=197976"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=197976"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=197976"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}Explanation:<\/h3>\n\n\n\n
\n
Xenon is a noble gas, and its electron configuration ends in 5p\u2076. It has 8 valence electrons (4 from its 5s and 4 from its 5p orbitals).<\/li>\n\n\n\n
In XeOF\u2084, the xenon atom forms bonds with four fluorine atoms and one oxygen atom. The oxygen atom is typically bonded to xenon through a double bond, while each fluorine forms a single bond with xenon. Thus, the xenon has five bonding regions in total. Additionally, xenon has one lone pair of electrons, making a total of six electron domains<\/strong> around the xenon atom.<\/li>\n\n\n\n
According to VSEPR theory, six electron domains arrange themselves in a octahedral<\/strong> geometry to minimize electron-electron repulsion. This is because six electron pairs (bonding and lone pairs) will position themselves in an octahedral shape to achieve maximum spatial separation.<\/li>\n\n\n\n
To accommodate these six electron domains (five bonding pairs and one lone pair), the xenon atom undergoes sp\u00b3d\u00b2 hybridization<\/strong>. The hybridization involves the mixing of one s orbital, three p orbitals, and two d orbitals to form six sp\u00b3d\u00b2 hybrid orbitals, each of which will hold an electron pair, leading to the octahedral arrangement.<\/li>\n\n\n\n
The molecular geometry, considering only the positions of the atoms (ignoring the lone pair), is square pyramidal<\/strong>. The lone pair occupies one of the axial positions in the octahedral geometry, resulting in a distorted shape where four fluorine atoms form the base of the pyramid, and the oxygen atom occupies the top of the pyramid.<\/li>\n<\/ol>\n\n\n\nConclusion:<\/h3>\n\n\n\n