{"id":198719,"date":"2025-03-10T09:17:15","date_gmt":"2025-03-10T09:17:15","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=198719"},"modified":"2025-03-10T09:17:17","modified_gmt":"2025-03-10T09:17:17","slug":"the-carbon-carbon-triple-bond-of-an-alkyne-is-composed-of","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/10\/the-carbon-carbon-triple-bond-of-an-alkyne-is-composed-of\/","title":{"rendered":"The carbon-carbon triple bond of an alkyne is composed of"},"content":{"rendered":"\n<p>The carbon-carbon triple bond of an alkyne is composed of:<\/p>\n\n\n\n<p>a. three sigma (o) bonds<\/p>\n\n\n\n<p>b. three pi (10) bonds<\/p>\n\n\n\n<p>c. two sigma (0) bonds and one pi (re) bond<\/p>\n\n\n\n<p>d. one sigma (0) bond and two pi () bonds<\/p>\n\n\n\n<p>e. none of these; write in the correct answer<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Correct Answer:<\/h3>\n\n\n\n<p><strong>d. one sigma (\u03c3) bond and two pi (\u03c0) bonds<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>Alkynes are hydrocarbons that contain at least one <strong>carbon-carbon triple bond (C\u2261C)<\/strong>. This triple bond consists of <strong>one sigma (\u03c3) bond and two pi (\u03c0) bonds<\/strong>. To understand why, let&#8217;s analyze the bonding in alkynes step by step:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Hybridization of Carbon Atoms in Alkynes<\/strong><br>Each carbon involved in a triple bond undergoes <strong>sp hybridization<\/strong>. This means:<\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The carbon atom uses one <strong>s orbital<\/strong> and one <strong>p orbital<\/strong> to form two <strong>sp hybrid orbitals<\/strong>.<\/li>\n\n\n\n<li>These <strong>sp orbitals<\/strong> form <strong>two sigma bonds<\/strong> (one with the other carbon in the triple bond and one with another atom like hydrogen or carbon).<\/li>\n\n\n\n<li>The remaining two <strong>p orbitals<\/strong> (that are not hybridized) remain as <strong>pure p orbitals<\/strong>.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Formation of the Carbon-Carbon Triple Bond<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>One sigma (\u03c3) bond<\/strong> forms by the <strong>head-on overlap<\/strong> of the two <strong>sp orbitals<\/strong> from each carbon.<\/li>\n\n\n\n<li><strong>Two pi (\u03c0) bonds<\/strong> form by the <strong>sideways overlap<\/strong> of the two <strong>unhybridized p orbitals<\/strong> on each carbon.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Bonding Summary in Alkynes<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>1 sigma (\u03c3) bond<\/strong>: Strongest, formed by head-on overlap.<\/li>\n\n\n\n<li><strong>2 pi (\u03c0) bonds<\/strong>: Weaker, formed by sideways overlap.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Why is This Important?<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The presence of two pi bonds makes the triple bond <strong>shorter and stronger<\/strong> than a double or single bond.<\/li>\n\n\n\n<li>Alkynes show <strong>linear geometry (180\u00b0 bond angles)<\/strong> due to sp hybridization.<\/li>\n\n\n\n<li>These properties contribute to the <strong>high reactivity<\/strong> of alkynes, making them important in organic synthesis.<\/li>\n<\/ul>\n\n\n\n<p>Here is an <strong>illustration of the bonding in an alkyne<\/strong>:<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Image Representation of Alkyne Bonding:<\/strong><\/h4>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/03\/image-773.png\" alt=\"\" class=\"wp-image-198720\"\/><\/figure>\n\n\n\n<p>Here is the scientific diagram showing the bonding structure of an alkyne. It illustrates the <strong>sigma (\u03c3) and pi (\u03c0) bonds<\/strong>, <strong>sp hybridization<\/strong>, and the <strong>linear geometry<\/strong> of the alkyne (ethyne\/acetylene, C\u2082H\u2082). <\/p>\n","protected":false},"excerpt":{"rendered":"<p>The carbon-carbon triple bond of an alkyne is composed of: a. three sigma (o) bonds b. three pi (10) bonds c. two sigma (0) bonds and one pi (re) bond d. one sigma (0) bond and two pi () bonds e. none of these; write in the correct answer The correct answer and explanation is [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-198719","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/198719","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=198719"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/198719\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=198719"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=198719"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=198719"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}