{"id":199203,"date":"2025-03-10T20:16:53","date_gmt":"2025-03-10T20:16:53","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=199203"},"modified":"2025-03-10T20:16:55","modified_gmt":"2025-03-10T20:16:55","slug":"what-is-the-electron-domain-geometry-of-ses2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/10\/what-is-the-electron-domain-geometry-of-ses2\/","title":{"rendered":"What is the Electron Domain Geometry of SeS2"},"content":{"rendered":"\n<p>What is the Electron Domain Geometry of SeS<sub>2<\/sub><\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Electron Domain Geometry of SeS\u2082:<\/strong><\/h3>\n\n\n\n<p>The <strong>electron domain geometry<\/strong> of <strong>selenium disulfide (SeS\u2082)<\/strong> is <strong>trigonal planar<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation:<\/strong><\/h3>\n\n\n\n<p>To determine the <strong>electron domain geometry<\/strong> of <strong>SeS\u2082<\/strong>, we follow these steps:<\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Step 1: Determine the Valence Electrons of Selenium (Se)<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Selenium (<strong>Se<\/strong>) is in <strong>Group 16<\/strong> of the periodic table, so it has <strong>6 valence electrons<\/strong>.<\/li>\n\n\n\n<li>Sulfur (<strong>S<\/strong>) is also in <strong>Group 16<\/strong>, and each sulfur atom has <strong>6 valence electrons<\/strong>.<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Step 2: Draw the Lewis Structure<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Selenium (Se) is the <strong>central atom<\/strong> because it is less electronegative than sulfur.<\/li>\n\n\n\n<li>Sulfur (S) atoms will bond to selenium via <strong>single bonds<\/strong>.<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Step 3: Count Electron Domains<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Selenium forms <strong>two single bonds<\/strong> with two sulfur atoms.<\/li>\n\n\n\n<li>The selenium atom also has <strong>one lone pair<\/strong> of electrons.<\/li>\n\n\n\n<li>In total, there are <strong>three electron domains<\/strong> around selenium:<\/li>\n\n\n\n<li><strong>Two bonding domains<\/strong> (from the Se-S bonds).<\/li>\n\n\n\n<li><strong>One lone pair<\/strong> (from selenium&#8217;s non-bonding electrons).<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Step 4: Determine the Electron Domain Geometry<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The <strong>electron domain geometry<\/strong> is determined by the total number of electron domains.<\/li>\n\n\n\n<li><strong>Three electron domains<\/strong> result in a <strong>trigonal planar<\/strong> geometry according to <strong>VSEPR (Valence Shell Electron Pair Repulsion) theory<\/strong>.<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Step 5: Determine the Molecular Geometry<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Since one of the domains is a <strong>lone pair<\/strong>, the <strong>molecular geometry<\/strong> is <strong>bent (V-shaped)<\/strong> rather than trigonal planar.<\/li>\n\n\n\n<li>However, the <strong>electron domain geometry<\/strong> is still <strong>trigonal planar<\/strong> because it considers both bonding and non-bonding electron pairs.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Conclusion<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The <strong>electron domain geometry<\/strong> of <strong>SeS\u2082<\/strong> is <strong>trigonal planar<\/strong>.<\/li>\n\n\n\n<li>The <strong>molecular geometry<\/strong> is <strong>bent (V-shaped)<\/strong> due to the lone pair on selenium, which repels the bonding pairs and reduces the bond angle.<\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>What is the Electron Domain Geometry of SeS2 The correct answer and explanation is : Electron Domain Geometry of SeS\u2082: The electron domain geometry of selenium disulfide (SeS\u2082) is trigonal planar. Explanation: To determine the electron domain geometry of SeS\u2082, we follow these steps: Step 1: Determine the Valence Electrons of Selenium (Se) Step 2: [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-199203","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/199203","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=199203"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/199203\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=199203"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=199203"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=199203"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}