{"id":199277,"date":"2025-03-11T03:37:03","date_gmt":"2025-03-11T03:37:03","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=199277"},"modified":"2025-03-11T03:37:23","modified_gmt":"2025-03-11T03:37:23","slug":"a-toy-car-is-released-from-rest-it-accelerates-at-0-40-m-s2-until-it-reaches-a-speed-of-1-8-m-s","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/11\/a-toy-car-is-released-from-rest-it-accelerates-at-0-40-m-s2-until-it-reaches-a-speed-of-1-8-m-s\/","title":{"rendered":"A toy car is released from rest"},"content":{"rendered":"\n<p>A toy car is released from rest. It accelerates at 0.40 m\/s2 until it reaches a speed of 1.8 m\/s. How far does it travel in this time?<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>To find the distance traveled by the toy car, we can use kinematic equations. Given:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Initial velocity, ( u = 0 ) m\/s (since it starts from rest)<\/li>\n\n\n\n<li>Final velocity, ( v = 1.8 ) m\/s<\/li>\n\n\n\n<li>Acceleration, ( a = 0.40 ) m\/s\u00b2<\/li>\n\n\n\n<li>Distance, ( s ) (to be found)<\/li>\n<\/ul>\n\n\n\n<p>We use the kinematic equation:<\/p>\n\n\n\n<p>[<br>v^2 = u^2 + 2as<br>]<\/p>\n\n\n\n<p>Substituting the given values:<\/p>\n\n\n\n<p>[<br>(1.8)^2 = (0)^2 + 2(0.40)s<br>]<\/p>\n\n\n\n<p>[<br>3.24 = 0.8s<br>]<\/p>\n\n\n\n<p>[<br>s = \\frac{3.24}{0.8}<br>]<\/p>\n\n\n\n<p>[<br>s = 4.05 \\text{ m}<br>]<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation (300 words)<\/h3>\n\n\n\n<p>To solve this problem, we applied the kinematic equation that relates velocity, acceleration, and displacement. The equation:<\/p>\n\n\n\n<p>[<br>v^2 = u^2 + 2as<br>]<\/p>\n\n\n\n<p>is useful when time is not given but we know acceleration and velocities.<\/p>\n\n\n\n<p>Since the toy car starts from rest (( u = 0 )), the equation simplifies to:<\/p>\n\n\n\n<p>[<br>v^2 = 2as<br>]<\/p>\n\n\n\n<p>Rearranging for ( s ):<\/p>\n\n\n\n<p>[<br>s = \\frac{v^2}{2a}<br>]<\/p>\n\n\n\n<p>This formula gives us the total distance traveled during the acceleration phase.<\/p>\n\n\n\n<p>By substituting the given values, we found that the car travels <strong>4.05 meters<\/strong> before reaching its maximum speed of <strong>1.8 m\/s<\/strong>.<\/p>\n\n\n\n<p>Physically, this means that while the toy car accelerates at a rate of <strong>0.40 m\/s\u00b2<\/strong>, it covers this distance before reaching the given speed. The acceleration is relatively small, so the car takes some distance to build up speed.<\/p>\n\n\n\n<p>This concept is commonly seen in physics problems involving motion with constant acceleration. Similar calculations apply to real-world scenarios like cars accelerating from a stoplight or objects rolling down an incline under gravity.<\/p>\n\n\n\n<p>Thus, the car moves <strong>4.05 meters<\/strong> before reaching the final velocity of <strong>1.8 m\/s<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>A toy car is released from rest. It accelerates at 0.40 m\/s2 until it reaches a speed of 1.8 m\/s. How far does it travel in this time? The correct answer and explanation is : To find the distance traveled by the toy car, we can use kinematic equations. Given: We use the kinematic equation: [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-199277","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/199277","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=199277"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/199277\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=199277"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=199277"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=199277"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}