{"id":199360,"date":"2025-03-11T15:44:32","date_gmt":"2025-03-11T15:44:32","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=199360"},"modified":"2025-03-11T15:44:54","modified_gmt":"2025-03-11T15:44:54","slug":"in-the-best-lewis-structure-for-no-what-is-the-formal-charge-on-the-n-atom","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/11\/in-the-best-lewis-structure-for-no-what-is-the-formal-charge-on-the-n-atom\/","title":{"rendered":"In the best Lewis structure for NO+"},"content":{"rendered":"\n<p>In the best Lewis structure for NO+, what is the formal charge on the N atom?<\/p>\n\n\n\n<p>A) -1<\/p>\n\n\n\n<p>B) 0<\/p>\n\n\n\n<p>C) +1<\/p>\n\n\n\n<p>D) +2<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Correct Answer: <strong>C) +1<\/strong><\/h3>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>To determine the <strong>formal charge<\/strong> on the nitrogen atom in the best Lewis structure for <strong>NO\u207a (nitrosonium ion)<\/strong>, follow these steps:<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 1: Count Valence Electrons<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Nitrogen (N)<\/strong> has <strong>5<\/strong> valence electrons.<\/li>\n\n\n\n<li><strong>Oxygen (O)<\/strong> has <strong>6<\/strong> valence electrons.<\/li>\n\n\n\n<li>Since the molecule has a <strong>+1 charge<\/strong>, we <strong>subtract 1 electron<\/strong> from the total count.<\/li>\n<\/ul>\n\n\n\n<p>[<br>5 (N) + 6 (O) &#8211; 1 = 10 \\text{ total valence electrons}<br>]<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 2: Draw the Skeleton Structure<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>N is less electronegative<\/strong> than O, so it is the <strong>central atom<\/strong>.<\/li>\n\n\n\n<li><strong>Connect N to O with a single bond first<\/strong> and distribute electrons to satisfy the octet rule.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 3: Complete the Octets &amp; Assign Formal Charges<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The best Lewis structure has a <strong>triple bond<\/strong> between <strong>N and O<\/strong> because it allows for the most stable configuration.<\/li>\n\n\n\n<li>This structure ensures <strong>both atoms have an octet<\/strong> and <strong>minimizes formal charges<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p>Formal charge is calculated using:<\/p>\n\n\n\n<p>[<br>\\text{Formal Charge} = \\text{Valence Electrons} &#8211; \\text{Nonbonding Electrons} &#8211; \\frac{\\text{Bonding Electrons}}{2}<br>]<\/p>\n\n\n\n<p>For <strong>Nitrogen (N):<\/strong><br>[<br>\\text{Formal Charge} = 5 &#8211; 0 &#8211; \\frac{6}{2} = 5 &#8211; 3 = +1<br>]<\/p>\n\n\n\n<p>For <strong>Oxygen (O):<\/strong><br>[<br>\\text{Formal Charge} = 6 &#8211; 4 &#8211; \\frac{6}{2} = 6 &#8211; 3 = 0<br>]<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 4: Confirming Stability<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The <strong>best structure<\/strong> has a <strong>triple bond<\/strong> between N and O, and <strong>a +1 formal charge on nitrogen<\/strong>.<\/li>\n\n\n\n<li>This structure obeys the <strong>octet rule<\/strong> and <strong>minimizes formal charges<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p>Thus, the correct answer is <strong>C) +1<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Image Representation of the Lewis Structure:<\/strong><\/h3>\n\n\n\n<p>t<strong>Lewis structure<\/strong> for <strong>NO\u207a<\/strong> <\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/03\/image-845.png\" alt=\"\" class=\"wp-image-199361\"\/><\/figure>\n\n\n\n<p>The image above shows the best <strong>Lewis structure<\/strong> for <strong>NO\u207a (nitrosonium ion)<\/strong>, with a <strong>triple bond<\/strong> between <strong>N and O<\/strong> and a <strong>+1 formal charge on nitrogen<\/strong>, confirming that the correct answer is <strong>C) +1<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>In the best Lewis structure for NO+, what is the formal charge on the N atom? A) -1 B) 0 C) +1 D) +2 The correct answer and explanation is : Correct Answer: C) +1 Explanation: To determine the formal charge on the nitrogen atom in the best Lewis structure for NO\u207a (nitrosonium ion), follow [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-199360","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/199360","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=199360"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/199360\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=199360"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=199360"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=199360"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}