{"id":199495,"date":"2025-03-12T02:24:43","date_gmt":"2025-03-12T02:24:43","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=199495"},"modified":"2025-03-12T02:24:45","modified_gmt":"2025-03-12T02:24:45","slug":"chemistry-a-kinetic-study-of-an-intestinal-peptidase-using-glycylglycine-as-the-substrate-produced-the-experimental-data-shown-in-the-table","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/12\/chemistry-a-kinetic-study-of-an-intestinal-peptidase-using-glycylglycine-as-the-substrate-produced-the-experimental-data-shown-in-the-table\/","title":{"rendered":"Chemistry A kinetic study of an intestinal peptidase using glycylglycine as the substrate produced the experimental data shown in the table"},"content":{"rendered":"\n<p>Chemistry:<\/p>\n\n\n\n<p>A kinetic study of an intestinal peptidase using glycylglycine as the substrate produced the experimental data shown in the table.<br>glycylglycine&nbsp;<img decoding=\"async\" src=\"https:\/\/files.transtutors.com\/book\/qimg\/990a9c78-4caf-4fd3-b6b8-e76616962651.png\">&nbsp;glycine<\/p>\n\n\n\n<figure class=\"wp-block-table\"><table class=\"has-fixed-layout\"><tbody><tr><td>[S]&nbsp;<img decoding=\"async\" src=\"https:\/\/files.transtutors.com\/book\/qimg\/8a3fc7da-e377-4341-96c4-0f19329d3420.png\"><\/td><td>Product formed&nbsp;<img decoding=\"async\" src=\"https:\/\/files.transtutors.com\/book\/qimg\/60bf9421-be65-482d-9403-395112971135.png\"><\/td><\/tr><tr><td>1.5<\/td><td>0.21<\/td><\/tr><tr><td>2.0<\/td><td>0.24<\/td><\/tr><tr><td>3.0<\/td><td>0.28<\/td><\/tr><tr><td>4.0<\/td><td>0.33<\/td><\/tr><tr><td>8.0<\/td><td>0.40<\/td><\/tr><tr><td>16.0<\/td><td>0.45<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n<p>Use the Lineweaver-Burk equation to determine the&nbsp;<img decoding=\"async\" src=\"https:\/\/files.transtutors.com\/book\/qimg\/30b1f26f-c612-41a5-af15-d061bfde6db0.png\">&nbsp;and&nbsp;<img decoding=\"async\" src=\"https:\/\/files.transtutors.com\/book\/qimg\/915262a2-4c78-41a8-979e-a1b06d9f943d.png\">&nbsp;for this enzyme preparation and substrate.<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/files.transtutors.com\/book\/qimg\/0f41a879-1c73-4143-8735-145ba291e9b4.png\" alt=\"\"\/><\/figure>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\">The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The calculated values for the enzyme kinetics using the Lineweaver-Burk plot are:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>KmK_m (Michaelis constant) = 2.14 mM<\/strong><\/li>\n\n\n\n<li><strong>VmaxV_{max} (Maximum reaction velocity) = 0.50 units<\/strong><\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>The Lineweaver-Burk equation is derived from the Michaelis-Menten equation: 1V=KmVmax\u22c5[S]+1Vmax\\frac{1}{V} = \\frac{K_m}{V_{max} \\cdot [S]} + \\frac{1}{V_{max}}<\/p>\n\n\n\n<p>where:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>VV is the reaction velocity,<\/li>\n\n\n\n<li>[S][S] is the substrate concentration,<\/li>\n\n\n\n<li>VmaxV_{max} is the maximum velocity,<\/li>\n\n\n\n<li>KmK_m is the Michaelis constant.<\/li>\n<\/ul>\n\n\n\n<p>By plotting 1\/V1\/V against 1\/[S]1\/[S], we obtain a straight line where:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The <strong>slope<\/strong> is Km\/VmaxK_m \/ V_{max},<\/li>\n\n\n\n<li>The <strong>y-intercept<\/strong> is 1\/Vmax1\/V_{max}.<\/li>\n<\/ul>\n\n\n\n<p>From the experimental data, we calculated the reciprocals of substrate concentration and reaction velocity. Using linear regression, we obtained the equation of the line: y=4.27x+1.997y = 4.27x + 1.997<\/p>\n\n\n\n<p>From the intercept (1\/Vmax=1.9971\/V_{max} = 1.997), we calculate: Vmax=11.997=0.50V_{max} = \\frac{1}{1.997} = 0.50<\/p>\n\n\n\n<p>From the slope (Km\/Vmax=4.27K_m \/ V_{max} = 4.27), we calculate: Km=4.27\u00d70.50=2.14&nbsp;mMK_m = 4.27 \\times 0.50 = 2.14 \\text{ mM}<\/p>\n\n\n\n<p>These values describe the enzyme&#8217;s efficiency in catalyzing the reaction. The <strong>KmK_m<\/strong> value indicates the substrate concentration at which the enzyme operates at half its maximum velocity. A lower KmK_m means higher affinity, while VmaxV_{max} represents the enzyme\u2019s full catalytic potential.<\/p>\n\n\n\n<p>The Lineweaver-Burk plot provides a clear method to determine these kinetic parameters and analyze enzyme efficiency.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Chemistry: A kinetic study of an intestinal peptidase using glycylglycine as the substrate produced the experimental data shown in the table.glycylglycine&nbsp;&nbsp;glycine [S]&nbsp; Product formed&nbsp; 1.5 0.21 2.0 0.24 3.0 0.28 4.0 0.33 8.0 0.40 16.0 0.45 Use the Lineweaver-Burk equation to determine the&nbsp;&nbsp;and&nbsp;&nbsp;for this enzyme preparation and substrate. The correct answer and explanation is: The [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-199495","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/199495","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=199495"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/199495\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=199495"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=199495"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=199495"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}