{"id":199605,"date":"2025-03-12T07:24:28","date_gmt":"2025-03-12T07:24:28","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=199605"},"modified":"2025-03-12T07:24:32","modified_gmt":"2025-03-12T07:24:32","slug":"using-the-vsepr-model-the-molecular-geometry-of-the-central-atom-in-h2s-is","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/12\/using-the-vsepr-model-the-molecular-geometry-of-the-central-atom-in-h2s-is\/","title":{"rendered":"Using the VSEPR model, the molecular geometry of the central atom in H2S is"},"content":{"rendered":"\n<p>Using the VSEPR model, the molecular geometry of the central atom in H2S is<\/p>\n\n\n\n<p>A) trigonal pyramid<br>B) trigonal planar<br>C) tetrahedral<br>D) linear<br>E) bent<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>The correct answer is:<br><strong>E) Bent<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>To determine the molecular geometry of <strong>H\u2082S (hydrogen sulfide)<\/strong> using the <strong>Valence Shell Electron Pair Repulsion (VSEPR) model<\/strong>, follow these steps:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Determine the Lewis Structure:<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Sulfur (<strong>S<\/strong>) is the central atom and has <strong>6 valence electrons<\/strong> (Group 16).<\/li>\n\n\n\n<li>Each hydrogen (<strong>H<\/strong>) contributes <strong>1 valence electron<\/strong> (total of 2 electrons from two H atoms).<\/li>\n\n\n\n<li>The total valence electrons in H\u2082S = 6 (S) + 2(1) = <strong>8 electrons<\/strong>.<\/li>\n\n\n\n<li>Sulfur forms single bonds with each hydrogen, using <strong>4 electrons<\/strong> (or 2 pairs), leaving <strong>4 nonbonding electrons<\/strong> (or <strong>2 lone pairs<\/strong>) on sulfur.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Predict the Electron Geometry:<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The steric number (number of bonding pairs + lone pairs) around sulfur is <strong>4<\/strong> (2 bonds + 2 lone pairs).<\/li>\n\n\n\n<li>According to the VSEPR model, a steric number of 4 corresponds to a <strong>tetrahedral<\/strong> electron geometry.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Determine the Molecular Geometry:<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The molecular geometry is determined by the positions of atoms, not lone pairs.<\/li>\n\n\n\n<li>Since sulfur has <strong>two lone pairs<\/strong>, they repel the bonding pairs, pushing the <strong>H-S-H<\/strong> bonds closer together.<\/li>\n\n\n\n<li>This distortion results in a <strong>bent<\/strong> molecular shape (not tetrahedral, because lone pairs are not counted in molecular geometry).<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Bond Angle Consideration:<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>In a perfect tetrahedral arrangement, bond angles are <strong>109.5\u00b0<\/strong>.<\/li>\n\n\n\n<li>However, lone pairs exert greater repulsion than bonding pairs, reducing the <strong>H-S-H bond angle<\/strong> to approximately <strong>104-105\u00b0<\/strong>, similar to water (<strong>H\u2082O<\/strong>).<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Conclusion:<\/h3>\n\n\n\n<p>The <strong>molecular geometry<\/strong> of <strong>H\u2082S<\/strong> is <strong>bent<\/strong>, making option <strong>E) Bent<\/strong> the correct answer.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Using the VSEPR model, the molecular geometry of the central atom in H2S is A) trigonal pyramidB) trigonal planarC) tetrahedralD) linearE) bent The correct answer and explanation is : The correct answer is:E) Bent Explanation: To determine the molecular geometry of H\u2082S (hydrogen sulfide) using the Valence Shell Electron Pair Repulsion (VSEPR) model, follow these [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center 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