{"id":199705,"date":"2025-03-12T10:39:55","date_gmt":"2025-03-12T10:39:55","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=199705"},"modified":"2025-03-12T10:39:57","modified_gmt":"2025-03-12T10:39:57","slug":"the-balanced-chemical-equation-for-the-combustion-of-methane-is","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/12\/the-balanced-chemical-equation-for-the-combustion-of-methane-is\/","title":{"rendered":"The balanced chemical equation for the combustion of methane is"},"content":{"rendered":"\n

The balanced chemical equation for the combustion of methane is:
CH4(g)+2O2(g) \u2192 CO2(g) + 2H2O(g)
Which of the following statements concerning this chemical equation is\/are correct?
One gram of methane gas reacts with two grams of dioxygen<\/p>\n\n\n\n

    \n
  1. gas, producing one gram of carbon dioxide gas and two grams of gaseous water.
    One mole of methane gas reacts with two moles of dioxygen<\/li>\n\n\n\n
  2. gas, producing one mole of carbon dioxide gas and two moles of gaseous water.
    One molecule of methane gas reacts with two molecules of<\/li>\n\n\n\n
  3. dioxygen gas, producing one molecule of carbon dioxide gas and two molecules of gaseous water.
    Select one:
    a. 2 and 3
    b. I and 3
    c. 1.2 and 3
    d. 2 only
    e. I only<\/li>\n<\/ol>\n\n\n\n

    The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n

    The correct answer is:
    a. 2 and 3<\/strong><\/p>\n\n\n\n

    Explanation:<\/h3>\n\n\n\n

    The balanced chemical equation for the combustion of methane is:
    [
    CH_4(g) + 2O_2(g) \\rightarrow CO_2(g) + 2H_2O(g)
    ]
    This equation tells us that one molecule<\/strong> of methane reacts with two molecules<\/strong> of oxygen to produce one molecule<\/strong> of carbon dioxide and two molecules<\/strong> of water. It also applies on a mole basis: one mole<\/strong> of methane reacts with two moles<\/strong> of oxygen, yielding one mole<\/strong> of carbon dioxide and two moles<\/strong> of water.<\/p>\n\n\n\n

    Statement 1:<\/h4>\n\n\n\n

    “One gram of methane gas reacts with two grams of dioxygen gas, producing one gram of carbon dioxide gas and two grams of gaseous water.”<\/em><\/p>\n\n\n\n

    This statement is incorrect<\/strong> because the mass relationships do not match the molecular weights. The molar masses are:<\/p>\n\n\n\n

      \n
    • Methane (CH\u2084)<\/strong> = 16 g\/mol<\/li>\n\n\n\n
    • Oxygen (O\u2082)<\/strong> = 32 g\/mol<\/li>\n\n\n\n
    • Carbon dioxide (CO\u2082)<\/strong> = 44 g\/mol<\/li>\n\n\n\n
    • Water (H\u2082O)<\/strong> = 18 g\/mol<\/li>\n<\/ul>\n\n\n\n

      Using mass calculations:<\/p>\n\n\n\n

        \n
      • 1 g of CH\u2084 corresponds to 1 g \/ 16 g\/mol = 0.0625 moles<\/strong><\/li>\n\n\n\n
      • From the equation, CH\u2084 reacts with 2 moles of O\u2082 per mole of CH\u2084<\/strong>, so oxygen required would be 0.125 moles<\/strong> of O\u2082. In grams, this is 0.125 \u00d7 32 = 4 g of O\u2082<\/strong><\/li>\n\n\n\n
      • The products formed are 0.0625 moles of CO\u2082 (0.0625 \u00d7 44 = 2.75 g CO\u2082)<\/strong> and 0.125 moles of H\u2082O (0.125 \u00d7 18 = 2.25 g H\u2082O)<\/strong><\/li>\n<\/ul>\n\n\n\n

        Clearly, 1 g CH\u2084 does not react with 2 g O\u2082<\/strong>. The mass ratios in the given statement are incorrect, so Statement 1 is false<\/strong>.<\/p>\n\n\n\n

        Statement 2:<\/h4>\n\n\n\n

        “One mole of methane gas reacts with two moles of dioxygen gas, producing one mole of carbon dioxide gas and two moles of gaseous water.”<\/em><\/p>\n\n\n\n

        This follows directly from the balanced equation. Statement 2 is correct.<\/strong><\/p>\n\n\n\n

        Statement 3:<\/h4>\n\n\n\n

        “One molecule of methane gas reacts with two molecules of dioxygen gas, producing one molecule of carbon dioxide gas and two molecules of gaseous water.”<\/em><\/p>\n\n\n\n

        This also follows directly from the equation at the molecular level. Statement 3 is correct.<\/strong><\/p>\n\n\n\n

        Since statements 2 and 3 are correct<\/strong>, the correct answer is option a (2 and 3).<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"

        The balanced chemical equation for the combustion of methane is:CH4(g)+2O2(g) \u2192 CO2(g) + 2H2O(g)Which of the following statements concerning this chemical equation is\/are correct?One gram of methane gas reacts with two grams of dioxygen The correct answer and explanation is : The correct answer is:a. 2 and 3 Explanation: The balanced chemical equation for the […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-199705","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/199705","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=199705"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/199705\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=199705"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=199705"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=199705"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}