{"id":199781,"date":"2025-03-12T15:38:39","date_gmt":"2025-03-12T15:38:39","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=199781"},"modified":"2025-03-12T15:38:41","modified_gmt":"2025-03-12T15:38:41","slug":"write-the-chemical-formulas-for-the-following-ionic-compounds","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/12\/write-the-chemical-formulas-for-the-following-ionic-compounds\/","title":{"rendered":"Write the chemical formulas for the following ionic compounds"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Write the chemical formulas for the following ionic compounds.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">tantalum cyanide<br>potassium iodide<br>radium selenide<br>manganese (IV) nitride<br>calcium fluoride<br>zinc oxide<br>osmium (VIII) carbide<br>cesium silicide<br>cadmium cyanide<br>zinc hydroxide<br>tungsten (IV) oxalate<br>thallium (III) arsenide<br>chromium (VI) sulfide<br>lithium nitrite<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Here are the correct chemical formulas for the given ionic compounds:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Tantalum cyanide<\/strong> \u2013 <strong>Ta(CN)\u2085<\/strong> (assuming tantalum has a +5 oxidation state)<\/li>\n\n\n\n<li><strong>Potassium iodide<\/strong> \u2013 <strong>KI<\/strong><\/li>\n\n\n\n<li><strong>Radium selenide<\/strong> \u2013 <strong>RaSe<\/strong><\/li>\n\n\n\n<li><strong>Manganese (IV) nitride<\/strong> \u2013 <strong>Mn\u2083N\u2084<\/strong><\/li>\n\n\n\n<li><strong>Calcium fluoride<\/strong> \u2013 <strong>CaF\u2082<\/strong><\/li>\n\n\n\n<li><strong>Zinc oxide<\/strong> \u2013 <strong>ZnO<\/strong><\/li>\n\n\n\n<li><strong>Osmium (VIII) carbide<\/strong> \u2013 <strong>OsC\u2084<\/strong> (assuming osmium has a +8 oxidation state and carbide as C\u2074\u207b)<\/li>\n\n\n\n<li><strong>Cesium silicide<\/strong> \u2013 <strong>Cs\u2084Si<\/strong> (assuming silicide as Si\u2074\u207b)<\/li>\n\n\n\n<li><strong>Cadmium cyanide<\/strong> \u2013 <strong>Cd(CN)\u2082<\/strong><\/li>\n\n\n\n<li><strong>Zinc hydroxide<\/strong> \u2013 <strong>Zn(OH)\u2082<\/strong><\/li>\n\n\n\n<li><strong>Tungsten (IV) oxalate<\/strong> \u2013 <strong>W(C\u2082O\u2084)\u2082<\/strong><\/li>\n\n\n\n<li><strong>Thallium (III) arsenide<\/strong> \u2013 <strong>TlAs<\/strong><\/li>\n\n\n\n<li><strong>Chromium (VI) sulfide<\/strong> \u2013 <strong>CrS\u2083<\/strong><\/li>\n\n\n\n<li><strong>Lithium nitrite<\/strong> \u2013 <strong>LiNO\u2082<\/strong><\/li>\n<\/ol>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation (300 words):<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Ionic compounds are formed when metals transfer electrons to nonmetals, creating positively charged cations and negatively charged anions. The formula of an ionic compound must be electrically neutral, meaning the total positive and negative charges must balance.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">For <strong>binary ionic compounds<\/strong> (e.g., potassium iodide, calcium fluoride, zinc oxide), the metal donates electrons to the nonmetal. The charges on the individual ions determine the formula. For example, <strong>CaF\u2082<\/strong> consists of <strong>Ca\u00b2\u207a<\/strong> and <strong>F\u207b<\/strong> ions. Since calcium has a +2 charge and fluoride has a -1 charge, two fluoride ions are required to balance the charge.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">For <strong>compounds with transition metals<\/strong> (e.g., manganese (IV) nitride, chromium (VI) sulfide), the Roman numeral indicates the oxidation state of the metal. In <strong>Mn\u2083N\u2084<\/strong>, manganese (IV) has a +4 charge, and nitride (N\u00b3\u207b) has a -3 charge. The least common multiple of 4 and 3 is 12, requiring three Mn\u2074\u207a and four N\u00b3\u207b to balance.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">For <strong>polyatomic ionic compounds<\/strong> (e.g., tungsten (IV) oxalate, lithium nitrite), polyatomic ions such as oxalate (C\u2082O\u2084\u00b2\u207b) and nitrite (NO\u2082\u207b) must be included in the correct ratio. <strong>W(C\u2082O\u2084)\u2082<\/strong> has tungsten (IV) with a +4 charge and oxalate with a -2 charge, requiring two oxalate ions.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Understanding the charge interactions and oxidation states helps determine the correct formula, ensuring electrical neutrality.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Write the chemical formulas for the following ionic compounds. tantalum cyanidepotassium iodideradium selenidemanganese (IV) nitridecalcium fluoridezinc oxideosmium (VIII) carbidecesium silicidecadmium cyanidezinc hydroxidetungsten (IV) oxalatethallium (III) arsenidechromium (VI) sulfidelithium nitrite The correct answer and explanation is : Here are the correct chemical formulas for the given ionic compounds: Explanation (300 words): Ionic compounds are formed when [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center 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