{"id":200120,"date":"2025-03-13T08:04:24","date_gmt":"2025-03-13T08:04:24","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=200120"},"modified":"2025-03-13T08:06:32","modified_gmt":"2025-03-13T08:06:32","slug":"choose-the-orbital-diagram-that-represents-the-ground-state-of-n","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/13\/choose-the-orbital-diagram-that-represents-the-ground-state-of-n\/","title":{"rendered":"Choose the orbital diagram that represents the ground state of N"},"content":{"rendered":"\n

Choose the orbital diagram that represents the ground state of N. Give the ground state electron configuration for Se.<\/p>\n\n\n\n

[Ar]4s23d10p4
[Ar]4s24d10p4
[Ar]4s23d10p6
[Ar]4s23d10
[Ar]3d10p4<\/p>\n\n\n\n

The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n

Let’s break this question into two parts.<\/p>\n\n\n\n

1. Orbital Diagram for the Ground State of Nitrogen (N)<\/strong><\/h3>\n\n\n\n

Nitrogen (N) has an atomic number of 7, meaning it has 7 electrons. The ground state electron configuration for nitrogen follows the Aufbau principle, Hund’s rule, and the Pauli exclusion principle.<\/p>\n\n\n\n

    \n
  • Electron Configuration of Nitrogen<\/strong>: 1s\u00b2 2s\u00b2 2p\u00b3.<\/li>\n<\/ul>\n\n\n\n

    This configuration tells us that nitrogen’s electrons fill the orbitals as follows:<\/p>\n\n\n\n

      \n
    • The 1s orbital holds 2 electrons.<\/li>\n\n\n\n
    • The 2s orbital holds 2 electrons.<\/li>\n\n\n\n
    • The 2p orbital holds 3 electrons.<\/li>\n<\/ul>\n\n\n\n

      Thus, for the orbital diagram of nitrogen, it would be represented as:<\/p>\n\n\n\n

      1s: \u2191\u2193  \n2s: \u2191\u2193  \n2p: \u2191 \u2191 \u2191<\/code><\/pre>\n\n\n\n
      This diagram shows that nitrogen has 3 unpaired electrons in the 2p orbital, which is consistent with its chemical properties and position in the periodic table.<\/p>\n\n\n\n
      2. Ground State Electron Configuration for Selenium (Se)<\/strong><\/h3>\n\n\n\n
      Selenium (Se) has an atomic number of 34, so it has 34 electrons. To write the ground state electron configuration for selenium, we follow the same principles.<\/p>\n\n\n\n
        \n
      • The electron configuration of Se is: [Ar] 4s\u00b2 3d\u00b9\u2070 4p\u2074<\/strong>.<\/li>\n<\/ul>\n\n\n\n
        Here’s the breakdown:<\/p>\n\n\n\n
          \n
        • [Ar]<\/strong> refers to the electron configuration of Argon (18 electrons), which covers the first 18 electrons.<\/li>\n\n\n\n
        • After Argon, selenium’s remaining electrons are filled in the 4s, 3d, and 4p orbitals.<\/li>\n\n\n\n
        • The 4s orbital fills first, with 2 electrons.<\/li>\n\n\n\n
        • The 3d orbital then fills with 10 electrons.<\/li>\n\n\n\n
        • Finally, the 4p orbital fills with 4 electrons.<\/li>\n<\/ul>\n\n\n\n
          Thus, the full electron configuration for selenium is [Ar] 4s\u00b2 3d\u00b9\u2070 4p\u2074<\/strong>.<\/p>\n\n\n\n
          Conclusion<\/h3>\n\n\n\n
            \n
          • The orbital diagram for nitrogen (N) would show 3 unpaired electrons in the 2p orbital.<\/li>\n\n\n\n
          • The electron configuration for selenium (Se) is [Ar] 4s\u00b2 3d\u00b9\u2070 4p\u2074<\/strong>, which places selenium in Group 16 of the periodic table, indicating it has 6 valence electrons (2 from 4s and 4 from 4p).<\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"
            Choose the orbital diagram that represents the ground state of N. Give the ground state electron configuration for Se. [Ar]4s23d10p4[Ar]4s24d10p4[Ar]4s23d10p6[Ar]4s23d10[Ar]3d10p4 The correct answer and explanation is : Let’s break this question into two parts. 1. Orbital Diagram for the Ground State of Nitrogen (N) Nitrogen (N) has an atomic number of 7, meaning it has […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-200120","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/200120","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=200120"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/200120\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=200120"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=200120"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=200120"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}