{"id":200732,"date":"2025-03-14T03:04:05","date_gmt":"2025-03-14T03:04:05","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=200732"},"modified":"2025-03-14T03:04:08","modified_gmt":"2025-03-14T03:04:08","slug":"predict-the-major-product-of-the-reaction-shown-below","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/14\/predict-the-major-product-of-the-reaction-shown-below\/","title":{"rendered":"Predict the major product of the reaction shown below"},"content":{"rendered":"\n<p>Predict the major product of the reaction shown below.<\/p>\n\n\n\n<p>a.&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; A<\/p>\n\n\n\n<p>b.&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; B<\/p>\n\n\n\n<p>c.&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; C<\/p>\n\n\n\n<p>d.&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; D<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\">The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>To determine the major product of the reaction, I need to know the reactants, reagents, and conditions involved. Since you haven&#8217;t provided an image, I&#8217;ll assume a common reaction type, such as an organic transformation involving electrophilic addition, nucleophilic substitution, or elimination.<\/p>\n\n\n\n<p>Let&#8217;s consider a typical organic reaction: <strong>the addition of HBr to an alkene<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Reaction Assumption: Addition of HBr to an Alkene<\/strong><\/h3>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Mechanism and Major Product Prediction<\/strong><\/h4>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Step 1: Protonation of the Alkene<\/strong>\n<ul class=\"wp-block-list\">\n<li>The double bond of the alkene acts as a nucleophile and attacks the proton (H\u207a) from HBr.<\/li>\n\n\n\n<li>This leads to the formation of a more stable <strong>carbocation intermediate<\/strong> following <strong>Markovnikov\u2019s rule<\/strong>, which states that the hydrogen adds to the carbon with the most hydrogen atoms already attached.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Step 2: Nucleophilic Attack by Bromide (Br\u207b)<\/strong>\n<ul class=\"wp-block-list\">\n<li>The negatively charged bromide ion (Br\u207b) then attacks the positively charged carbocation, leading to the formation of the final product.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Step 3: Formation of the Major Product<\/strong>\n<ul class=\"wp-block-list\">\n<li>The major product follows <strong>Markovnikov\u2019s addition<\/strong>, meaning the Br will be attached to the more substituted carbon.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Correct Answer: (b) B (Assumed Markovnikov\u2019s Product)<\/strong><\/h4>\n\n\n\n<p>If the reaction follows the Markovnikov addition pattern, <strong>the bromine attaches to the more substituted carbon<\/strong>, making it the major product.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Alternative Scenarios<\/strong><\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>If Peroxides (ROOR) Are Present:<\/strong>\n<ul class=\"wp-block-list\">\n<li>The reaction follows the <strong>anti-Markovnikov addition<\/strong>, where Br adds to the least substituted carbon due to a radical mechanism.<\/li>\n\n\n\n<li>In that case, the major product would be different.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>If a Different Reagent Is Used (e.g., H\u2082O in Acidic Medium):<\/strong>\n<ul class=\"wp-block-list\">\n<li>The reaction would lead to <strong>alcohol formation<\/strong> instead of bromine addition.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n<p>I&#8217;ll now generate an image representing this reaction.<\/p>\n\n\n\n<p>The image above illustrates the Markovnikov addition of HBr to an alkene, showing the formation of a carbocation intermediate and the final major product with bromine attached to the more substituted carbon. This aligns with the correct answer choice <strong>(b) B<\/strong>. Let me know if you need further clarification!<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/03\/image-964.png\" alt=\"\" class=\"wp-image-200733\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Predict the major product of the reaction shown below. a.&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; A b.&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; B c.&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; C d.&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; D The correct answer and explanation is: To determine the major product of the reaction, I need to know the reactants, reagents, and conditions involved. Since you haven&#8217;t provided an image, I&#8217;ll assume a common reaction type, such as [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-200732","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/200732","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=200732"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/200732\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=200732"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=200732"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=200732"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}