{"id":201150,"date":"2025-03-15T03:17:03","date_gmt":"2025-03-15T03:17:03","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=201150"},"modified":"2025-03-15T03:17:05","modified_gmt":"2025-03-15T03:17:05","slug":"bromine-br-is-atomic-number-35-4","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/15\/bromine-br-is-atomic-number-35-4\/","title":{"rendered":"Bromine (Br) is atomic number 35"},"content":{"rendered":"\n<p>Bromine (Br) is atomic number 35. How many protons, neutrons, and electrons in a negative ion of Bromine-79 (Br&#8221; -79)?<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>OA.<\/li>\n\n\n\n<li>OB. 35p, 44n, 36e<\/li>\n\n\n\n<li>OC. 35p, 79, 36e<\/li>\n\n\n\n<li>OD.<\/li>\n\n\n\n<li>OE 79p, 35, 36e<\/li>\n<\/ul>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\">The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The correct answer is:<\/p>\n\n\n\n<p><strong>OB. 35p, 44n, 36e<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p>To determine the number of protons, neutrons, and electrons in a <strong>negative ion of Bromine-79 (Br\u207b-79)<\/strong>, let&#8217;s analyze each part:<\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>1. Protons (p)<\/strong><\/h4>\n\n\n\n<p>The number of protons in an atom is always equal to its atomic number. Since bromine has an <strong>atomic number of 35<\/strong>, it has <strong>35 protons<\/strong> in its nucleus.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>2. Neutrons (n)<\/strong><\/h4>\n\n\n\n<p>The number of neutrons in an isotope is determined by subtracting the atomic number from the atomic mass: Neutrons=Mass&nbsp;Number\u2212Atomic&nbsp;Number\\text{Neutrons} = \\text{Mass Number} &#8211; \\text{Atomic Number}<\/p>\n\n\n\n<p>For <strong>Bromine-79<\/strong>: 79\u221235=44&nbsp;neutrons79 &#8211; 35 = 44 \\text{ neutrons}<\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>3. Electrons (e)<\/strong><\/h4>\n\n\n\n<p>A neutral bromine atom has <strong>35 electrons<\/strong> because the number of electrons is equal to the number of protons. However, since we are dealing with a <strong>negative ion (Br\u207b)<\/strong>, this means the atom has <strong>gained one extra electron<\/strong>: 35+1=36&nbsp;electrons35 + 1 = 36 \\text{ electrons}<\/p>\n\n\n\n<p>Thus, the <strong>correct answer is 35 protons, 44 neutrons, and 36 electrons<\/strong>, which matches <strong>Option B (35p, 44n, 36e)<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Why is Bromine-79 a Negative Ion?<\/strong><\/h3>\n\n\n\n<p>When bromine forms an anion (<strong>Br\u207b<\/strong>), it gains an electron to achieve a stable electron configuration, similar to that of a noble gas (<strong>Krypton, Kr<\/strong>). This makes it more stable, as elements tend to gain or lose electrons to reach a full outer shell.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Final Answer:<\/strong><\/h3>\n\n\n\n<p>\u2714 <strong>Option B: 35p, 44n, 36e<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p>Now, I will generate an image to visually represent the atomic structure of <strong>Br\u207b-79<\/strong>, including the number of protons, neutrons, and electrons.<\/p>\n\n\n\n<p>Here is the educational diagram of the <strong>Bromine-79 negative ion (Br\u207b)<\/strong>, showing its <strong>35 protons, 44 neutrons, and 36 electrons<\/strong> arranged in electron shells. Let me know if you need any modifications or additional explanations!<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/03\/image-1000.png\" alt=\"\" class=\"wp-image-201151\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>Bromine (Br) is atomic number 35. How many protons, neutrons, and electrons in a negative ion of Bromine-79 (Br&#8221; -79)? The correct answer and explanation is: The correct answer is: OB. 35p, 44n, 36e Explanation: To determine the number of protons, neutrons, and electrons in a negative ion of Bromine-79 (Br\u207b-79), let&#8217;s analyze each part: [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-201150","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/201150","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=201150"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/201150\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=201150"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=201150"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=201150"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}