{"id":201252,"date":"2025-03-15T06:56:36","date_gmt":"2025-03-15T06:56:36","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=201252"},"modified":"2025-03-15T06:56:38","modified_gmt":"2025-03-15T06:56:38","slug":"identify-the-correct-net-ionic-equation-for-the-reaction-that-occurs-when-solutions-of-hno3-and-koh-are-mixed","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/15\/identify-the-correct-net-ionic-equation-for-the-reaction-that-occurs-when-solutions-of-hno3-and-koh-are-mixed\/","title":{"rendered":"Identify the correct net ionic equation for the reaction that occurs when solutions of HNO3 and KOH are mixed"},"content":{"rendered":"\n

Identify the correct net ionic equation for the reaction that occurs when solutions of HNO3 and KOH are mixed? <\/p>\n\n\n\n

A. HNO3(aq) + KOH(aq) + H2O(l) + KNO3(s) <\/p>\n\n\n\n

B. K+(aq) + NO3(aq) ? KNO3(aq) <\/p>\n\n\n\n

C. H3O+(aq) + OH-(aq) ? 2H2O(l)<\/p>\n\n\n\n

D. HNO3(aq) + KOH(aq) + H2O(l) + KNO3(aq) E. HNO3(aq) + OH-(aq) + H2O(l) + NO3-(aq)<\/p>\n\n\n\n

The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n

The correct net ionic equation for the reaction that occurs when solutions of HNO3 and KOH are mixed is:<\/p>\n\n\n\n

C. H\u2083O\u207a(aq) + OH\u207b(aq) \u2192 2H\u2082O(l)<\/strong><\/p>\n\n\n\n

Explanation:<\/h3>\n\n\n\n

When HNO\u2083 (nitric acid) and KOH (potassium hydroxide) are mixed in water, they undergo a neutralization reaction. Let’s break down the process step by step:<\/p>\n\n\n\n

    \n
  1. Dissociation of HNO\u2083<\/strong>: Nitric acid is a strong acid, meaning it dissociates completely in water. The dissociation equation is:
    [ \\text{HNO}_3 (aq) \\rightarrow \\text{H}^+ (aq) + \\text{NO}_3^- (aq) ]
    However, the hydrogen ion (H\u207a) from this dissociation will quickly associate with water molecules to form hydronium ions (H\u2083O\u207a), which is the actual form of H\u207a in aqueous solutions:
    [ \\text{H}^+ (aq) + \\text{H}_2\\text{O} (l) \\rightarrow \\text{H}_3\\text{O}^+ (aq) ]<\/li>\n\n\n\n
  2. Dissociation of KOH<\/strong>: Potassium hydroxide is a strong base, so it also dissociates completely in water:
    [ \\text{KOH} (aq) \\rightarrow \\text{K}^+ (aq) + \\text{OH}^- (aq) ]<\/li>\n\n\n\n
  3. Neutralization Reaction<\/strong>: The hydronium ion (H\u2083O\u207a) from HNO\u2083 and the hydroxide ion (OH\u207b) from KOH react to form water:
    [ \\text{H}_3\\text{O}^+ (aq) + \\text{OH}^- (aq) \\rightarrow 2 \\text{H}_2\\text{O} (l) ]
    This is the net ionic equation for the neutralization reaction, where the hydrogen ions from the acid neutralize the hydroxide ions from the base, forming water.<\/li>\n\n\n\n
  4. Spectator Ions<\/strong>: The potassium ions (K\u207a) and nitrate ions (NO\u2083\u207b) do not participate in the reaction and are considered spectator ions. They remain in solution and do not change during the reaction.<\/li>\n<\/ol>\n\n\n\n

    Now, let’s analyze the options:<\/p>\n\n\n\n

      \n
    • Option A<\/strong>: This is incorrect because it includes KNO\u2083 as a solid (KNO\u2083(s)), but KNO\u2083 is highly soluble in water, so it should be aqueous (KNO\u2083(aq)).<\/li>\n\n\n\n
    • Option B<\/strong>: This represents the dissociation of KNO\u2083, which is not relevant in the net ionic equation of the neutralization reaction.<\/li>\n\n\n\n
    • Option C<\/strong>: This is the correct net ionic equation for the neutralization reaction.<\/li>\n\n\n\n
    • Option D<\/strong>: This includes all species in their full forms and is not the net ionic equation because it includes spectator ions.<\/li>\n\n\n\n
    • Option E<\/strong>: This includes OH\u207b and HNO\u2083 as reactants, but it doesn’t correctly represent the complete neutralization.<\/li>\n<\/ul>\n\n\n\n

      Thus, C<\/strong> is the correct answer.<\/p>\n","protected":false},"excerpt":{"rendered":"

      Identify the correct net ionic equation for the reaction that occurs when solutions of HNO3 and KOH are mixed? A. HNO3(aq) + KOH(aq) + H2O(l) + KNO3(s) B. K+(aq) + NO3(aq) ? KNO3(aq) C. H3O+(aq) + OH-(aq) ? 2H2O(l) D. HNO3(aq) + KOH(aq) + H2O(l) + KNO3(aq) E. HNO3(aq) + OH-(aq) + H2O(l) + NO3-(aq) […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-201252","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/201252","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=201252"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/201252\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=201252"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=201252"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=201252"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}