{"id":201513,"date":"2025-03-15T13:45:02","date_gmt":"2025-03-15T13:45:02","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=201513"},"modified":"2025-03-15T13:45:05","modified_gmt":"2025-03-15T13:45:05","slug":"a-1-00-molal-aqueous-solution-of-trichloroacetic-acid-ccl3cooh-is-heated-to-its-boiling-point","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/15\/a-1-00-molal-aqueous-solution-of-trichloroacetic-acid-ccl3cooh-is-heated-to-its-boiling-point\/","title":{"rendered":"A 1.00 molal aqueous solution of trichloroacetic acid (CCl3COOH) is heated to its boiling point"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">A 1.00 molal aqueous solution of trichloroacetic acid (CCl3COOH) is heated to its boiling point. The solution has the boiling point of 100.18 \u00b0C. Determine the van\u2019t Hoff factor for trichloroacetic acid. (Kft for water = 0.512 K kg mol-1)<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">To determine the van&#8217;t Hoff factor ((i)) for trichloroacetic acid (CCl\u2083COOH) in the given aqueous solution, we will use the formula for boiling point elevation:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">[<br>\\Delta T_b = i \\cdot K_b \\cdot m<br>]<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Where:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>(\\Delta T_b) is the change in boiling point,<\/li>\n\n\n\n<li>(i) is the van&#8217;t Hoff factor,<\/li>\n\n\n\n<li>(K_b) is the ebullioscopic constant (boiling point elevation constant) of the solvent,<\/li>\n\n\n\n<li>(m) is the molality of the solution.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Calculate the change in boiling point<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">The boiling point of pure water is 100.00 \u00b0C. The boiling point of the solution is given as 100.18 \u00b0C. Thus, the change in boiling point ((\\Delta T_b)) is:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">[<br>\\Delta T_b = 100.18 \\,^\\circ C &#8211; 100.00 \\,^\\circ C = 0.18 \\,^\\circ C<br>]<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Identify known values<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Molality ((m)) = 1.00 mol\/kg (given in the problem).<\/li>\n\n\n\n<li>(K_b) for water = 0.512 K kg mol(^{-1}) (also given).<\/li>\n\n\n\n<li>The boiling point elevation formula becomes:<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">[<br>0.18 = i \\cdot 0.512 \\cdot 1.00<br>]<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Solve for (i)<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Rearranging the formula to solve for (i):<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">[<br>i = \\frac{0.18}{0.512} = 0.3516<br>]<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Step 4: Interpretation of the van\u2019t Hoff factor<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">The van&#8217;t Hoff factor ((i)) represents the number of particles into which a solute dissociates in a solution. If trichloroacetic acid were a non-electrolyte (not dissociating), (i) would be 1. However, as we are getting a value for (i) that is lower than 1, it suggests that trichloroacetic acid does not dissociate completely in water, or some association might occur between molecules in solution, leading to a smaller-than-expected van&#8217;t Hoff factor.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Conclusion:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">The van&#8217;t Hoff factor ((i)) for trichloroacetic acid is approximately <strong>0.352<\/strong>, indicating partial dissociation or association in water.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>A 1.00 molal aqueous solution of trichloroacetic acid (CCl3COOH) is heated to its boiling point. The solution has the boiling point of 100.18 \u00b0C. Determine the van\u2019t Hoff factor for trichloroacetic acid. (Kft for water = 0.512 K kg mol-1) The correct answer and explanation is : To determine the van&#8217;t Hoff factor ((i)) for [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-201513","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/201513","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=201513"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/201513\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=201513"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=201513"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=201513"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}