{"id":202238,"date":"2025-03-17T09:45:08","date_gmt":"2025-03-17T09:45:08","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=202238"},"modified":"2025-03-17T09:45:10","modified_gmt":"2025-03-17T09:45:10","slug":"give-correct-iupac-names-for-the-compounds-below","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/17\/give-correct-iupac-names-for-the-compounds-below\/","title":{"rendered":"Give correct IUPAC names for the compounds below"},"content":{"rendered":"\n

Give correct IUPAC names for the compounds below: Explain<\/p>\n\n\n\n

(1) K3 [Fe(C2O4)3]-3H20<\/p>\n\n\n\n

(2) K[Cu(C2O4)2]\u00b72H2O<\/p>\n\n\n\n

(3) K3[Cr(C2O4)3]-3H20<\/p>\n\n\n\n

(4) K[Al(C2O4)3]-3H20<\/p>\n\n\n\n

(5a) cis-K[Cr(C204)2(H2O)2]-2H2O<\/p>\n\n\n\n

(5b) trans-K[Cr(C2O4)2(H20)2]\u00b72H20<\/p>\n\n\n\n

The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n

Correct IUPAC Names and Explanation<\/h3>\n\n\n\n
    \n
  1. Potassium tris(oxalato)ferrate(III) trihydrate<\/strong>
    Formula:<\/strong> K\u2083[Fe(C\u2082O\u2084)\u2083]\u00b73H\u2082O<\/li>\n<\/ol>\n\n\n\n
      \n
    • The central metal ion is iron (Fe\u00b3\u207a)<\/strong>.<\/li>\n\n\n\n
    • Oxalate (C\u2082O\u2084\u00b2\u207b)<\/strong> is a bidentate ligand.<\/li>\n\n\n\n
    • The oxidation state of Fe is +3<\/strong>, determined by:
      [
      3K^+ + \\text{Fe} + 3(C_2O_4^{2-}) = 0
      ]
      Solving for Fe: Fe\u00b3\u207a<\/strong>.<\/li>\n\n\n\n
    • Since the complex is an anion<\/strong>, it ends with “-ate”<\/strong>, hence ferrate(III)<\/strong>.<\/li>\n<\/ul>\n\n\n\n
        \n
      1. Potassium bis(oxalato)cuprate(II) dihydrate<\/strong>
        Formula:<\/strong> K[Cu(C\u2082O\u2084)\u2082]\u00b72H\u2082O<\/li>\n<\/ol>\n\n\n\n
          \n
        • Copper (Cu\u00b2\u207a)<\/strong> has an oxidation state of +2<\/strong>.<\/li>\n\n\n\n
        • Since the complex is anionic<\/strong>, “-ate”<\/strong> is used for the metal, forming cuprate(II)<\/strong>.<\/li>\n<\/ul>\n\n\n\n
            \n
          1. Potassium tris(oxalato)chromate(III) trihydrate<\/strong>
            Formula:<\/strong> K\u2083[Cr(C\u2082O\u2084)\u2083]\u00b73H\u2082O<\/li>\n<\/ol>\n\n\n\n
              \n
            • Chromium (Cr\u00b3\u207a)<\/strong> has an oxidation state of +3<\/strong>.<\/li>\n\n\n\n
            • The complex is anionic<\/strong>, so chromate(III)<\/strong> is used.<\/li>\n<\/ul>\n\n\n\n
                \n
              1. Potassium tris(oxalato)aluminate(III) trihydrate<\/strong>
                Formula:<\/strong> K\u2083[Al(C\u2082O\u2084)\u2083]\u00b73H\u2082O<\/li>\n<\/ol>\n\n\n\n
                  \n
                • Aluminum (Al\u00b3\u207a)<\/strong> oxidation state is +3<\/strong>.<\/li>\n\n\n\n
                • The complex is anionic<\/strong>, so aluminate(III)<\/strong> is used.<\/li>\n<\/ul>\n\n\n\n

                  5a. cis-Potassium diaquabis(oxalato)chromate(III) dihydrate<\/strong>
                  Formula:<\/strong> cis-K[Cr(C\u2082O\u2084)\u2082(H\u2082O)\u2082]\u00b72H\u2082O<\/p>\n\n\n\n

                    \n
                  • Chromium (Cr\u00b3\u207a)<\/strong> oxidation state is +3<\/strong>.<\/li>\n\n\n\n
                  • The complex has two oxalate ligands<\/strong> and two water ligands<\/strong> in a cis-configuration<\/strong>.<\/li>\n<\/ul>\n\n\n\n

                    5b. trans-Potassium diaquabis(oxalato)chromate(III) dihydrate<\/strong>
                    Formula:<\/strong> trans-K[Cr(C\u2082O\u2084)\u2082(H\u2082O)\u2082]\u00b72H\u2082O<\/p>\n\n\n\n

                      \n
                    • Chromium (Cr\u00b3\u207a)<\/strong> oxidation state is +3<\/strong>.<\/li>\n\n\n\n
                    • The complex has two oxalate ligands<\/strong> and two water ligands<\/strong> in a trans-configuration<\/strong>.<\/li>\n<\/ul>\n\n\n\n

                      Explanation (300 Words)<\/h3>\n\n\n\n

                      The nomenclature of coordination complexes follows IUPAC rules, where the cation (potassium in this case) is named first, followed by the anionic coordination complex. The ligands<\/strong> are named in alphabetical order<\/strong>, and their quantity is specified using prefixes like bis- (2), tris- (3), tetra- (4), etc.<\/strong>.<\/p>\n\n\n\n

                      Oxalate (C\u2082O\u2084\u00b2\u207b)<\/strong> is a bidentate ligand<\/strong>, meaning it coordinates through two oxygen atoms. Since these complexes are anionic, the metal names end in “-ate”<\/strong> (e.g., ferrate, cuprate, chromate, aluminate). The oxidation state of the metal is determined by balancing the charge of the complex.<\/p>\n\n\n\n

                      For cis-trans isomerism<\/strong> in (5a) and (5b), the cis-form<\/strong> has the two water molecules adjacent, while in the trans-form<\/strong>, they are opposite. This affects properties like stability, reactivity, and color<\/strong>.<\/p>\n\n\n\n

                      The presence of crystal water (trihydrate, dihydrate, etc.)<\/strong> is explicitly stated after the complex name, as it influences solubility and crystal structure.<\/p>\n","protected":false},"excerpt":{"rendered":"

                      Give correct IUPAC names for the compounds below: Explain (1) K3 [Fe(C2O4)3]-3H20 (2) K[Cu(C2O4)2]\u00b72H2O (3) K3[Cr(C2O4)3]-3H20 (4) K[Al(C2O4)3]-3H20 (5a) cis-K[Cr(C204)2(H2O)2]-2H2O (5b) trans-K[Cr(C2O4)2(H20)2]\u00b72H20 The correct answer and explanation is : Correct IUPAC Names and Explanation 5a. cis-Potassium diaquabis(oxalato)chromate(III) dihydrateFormula: cis-K[Cr(C\u2082O\u2084)\u2082(H\u2082O)\u2082]\u00b72H\u2082O 5b. trans-Potassium diaquabis(oxalato)chromate(III) dihydrateFormula: trans-K[Cr(C\u2082O\u2084)\u2082(H\u2082O)\u2082]\u00b72H\u2082O Explanation (300 Words) The nomenclature of coordination complexes follows IUPAC rules, […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-202238","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/202238","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=202238"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/202238\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=202238"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=202238"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=202238"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}