For each reaction, identify the Bronsted-Lowry acid, the Bronsted-Lowry base, the conjugate acid, and the conjugate base.<\/p>\n\n\n\n
HBr(aq) + H2O(l) \u2192 H3O+(aq) + Br\u2212(aq)<\/p>\n\n\n\n
NH3(aq) + H2O(l) \u2192 NH4+(aq) + OH\u2212(aq)<\/p>\n\n\n\n
HNO3(aq) + H2O(l) \u2192 H3O+(aq) + NO3\u2212(aq)<\/p>\n\n\n\n
C5H5N(aq) + H2O(l) \u2192 C5H5NH+(aq) + OH\u2212(aq)<\/p>\n\n\n\n
Express your answers as chemical expressions. Enter your answers in order given in the question separated by commas.<\/p>\n\n\n\n
The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n Answer for reaction 1<\/strong>: HBr, H2O, H3O\u207a, Br\u207b<\/p>\n\n\n\n Answer for reaction 2<\/strong>: H2O, NH3, NH4\u207a, OH\u2212<\/p>\n\n\n\n Answer for reaction 3<\/strong>: HNO3, H2O, H3O\u207a, NO3\u2212<\/p>\n\n\n\n Answer for reaction 4<\/strong>: H2O, C5H5N, C5H5NH+, OH\u2212<\/p>\n\n\n\n In each of these reactions, the acid donates a proton (H\u207a), and the base accepts the proton. The conjugate acid is formed when the base accepts the proton, while the conjugate base is formed when the acid donates the proton. The Bronsted-Lowry theory focuses on proton transfer between molecules, helping to classify substances as acids or bases based on their behavior in reactions.<\/p>\n","protected":false},"excerpt":{"rendered":" For each reaction, identify the Bronsted-Lowry acid, the Bronsted-Lowry base, the conjugate acid, and the conjugate base. HBr(aq) + H2O(l) \u2192 H3O+(aq) + Br\u2212(aq) NH3(aq) + H2O(l) \u2192 NH4+(aq) + OH\u2212(aq) HNO3(aq) + H2O(l) \u2192 H3O+(aq) + NO3\u2212(aq) C5H5N(aq) + H2O(l) \u2192 C5H5NH+(aq) + OH\u2212(aq) Express your answers as chemical expressions. Enter your answers in […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-202242","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/202242","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=202242"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/202242\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=202242"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=202242"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=202242"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}Reaction 1: HBr(aq) + H2O(l) \u2192 H3O+(aq) + Br\u2212(aq)<\/h3>\n\n\n\n
\n
An acid is a proton (H\u207a) donor. In this reaction, HBr donates a proton to H2O.<\/li>\n\n\n\n
A base is a proton (H\u207a) acceptor. In this reaction, H2O accepts a proton from HBr.<\/li>\n\n\n\n
After H2O accepts the proton, it becomes H3O\u207a, which is the conjugate acid of H2O.<\/li>\n\n\n\n
After HBr donates the proton, it becomes Br\u207b, which is the conjugate base of HBr.<\/li>\n<\/ul>\n\n\n\n
\n\n\n\nReaction 2: NH3(aq) + H2O(l) \u2192 NH4+(aq) + OH\u2212(aq)<\/h3>\n\n\n\n
\n
In this case, water donates a proton to NH3, so water is acting as the acid.<\/li>\n\n\n\n
NH3 accepts the proton from H2O, making it the base in this reaction.<\/li>\n\n\n\n
After NH3 accepts the proton, it becomes NH4\u207a, which is the conjugate acid of NH3.<\/li>\n\n\n\n
After H2O donates the proton, it becomes OH\u2212, which is the conjugate base of H2O.<\/li>\n<\/ul>\n\n\n\n
\n\n\n\nReaction 3: HNO3(aq) + H2O(l) \u2192 H3O+(aq) + NO3\u2212(aq)<\/h3>\n\n\n\n
\n
In this case, HNO3 donates a proton to H2O, so HNO3 is the acid.<\/li>\n\n\n\n
Water accepts the proton from HNO3, making it the base in this reaction.<\/li>\n\n\n\n
After H2O accepts the proton, it becomes H3O\u207a, which is the conjugate acid of H2O.<\/li>\n\n\n\n
After HNO3 donates the proton, it becomes NO3\u2212, which is the conjugate base of HNO3.<\/li>\n<\/ul>\n\n\n\n
\n\n\n\nReaction 4: C5H5N(aq) + H2O(l) \u2192 C5H5NH+(aq) + OH\u2212(aq)<\/h3>\n\n\n\n
\n
In this case, water donates a proton to C5H5N, so water is acting as the acid.<\/li>\n\n\n\n
C5H5N (pyridine) accepts the proton from water, making it the base.<\/li>\n\n\n\n
After C5H5N accepts the proton, it becomes C5H5NH+, which is the conjugate acid of C5H5N.<\/li>\n\n\n\n
After H2O donates the proton, it becomes OH\u2212, which is the conjugate base of H2O.<\/li>\n<\/ul>\n\n\n\n
\n\n\n\nSummary of Answers:<\/h3>\n\n\n\n
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Explanation:<\/h3>\n\n\n\n