{"id":202548,"date":"2025-03-17T16:04:33","date_gmt":"2025-03-17T16:04:33","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=202548"},"modified":"2025-03-17T16:04:36","modified_gmt":"2025-03-17T16:04:36","slug":"draw-the-structure-of-an-eight-carbon-alkene-that-would-yield-the-following-compound-and-no-others-after-treatment-with-ozone-followed-by-dimethyl-sulfide-6","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/17\/draw-the-structure-of-an-eight-carbon-alkene-that-would-yield-the-following-compound-and-no-others-after-treatment-with-ozone-followed-by-dimethyl-sulfide-6\/","title":{"rendered":"Draw the structure of an eight-carbon alkene that would yield the following compound (and no others) after treatment with ozone followed by dimethyl sulfide"},"content":{"rendered":"\n

Draw the structure of an eight-carbon alkene that would yield the following compound (and no others) after treatment with ozone followed by dimethyl sulfide.<\/p>\n\n\n\n

The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n

To solve this problem, let’s break down the reaction and deduce the structure of the eight-carbon alkene.<\/p>\n\n\n\n

Step 1: Understanding the Reaction<\/h3>\n\n\n\n

When an alkene is treated with ozone ((O_3)) followed by dimethyl sulfide ((DMS), ( (CH_3O)_2S )), it undergoes ozonolysis<\/strong>, which cleaves the carbon-carbon double bond and forms two carbonyl compounds, which could be either aldehydes or ketones depending on the alkene\u2019s structure.<\/p>\n\n\n\n

The ozonolysis mechanism<\/strong> is as follows:<\/p>\n\n\n\n

    \n
  1. The alkene reacts with ozone, breaking the double bond.<\/li>\n\n\n\n
  2. This results in the formation of an unstable ozonide<\/strong>, which is then reduced by dimethyl sulfide to yield two carbonyl compounds.<\/li>\n<\/ol>\n\n\n\n

    Step 2: Identifying the Product Structure<\/h3>\n\n\n\n

    You mentioned that only one product would be formed after ozonolysis. This suggests that the initial alkene must be symmetric, meaning it must have two identical fragments after cleavage.<\/p>\n\n\n\n

    Step 3: Identifying the Eight-Carbon Alkene<\/h3>\n\n\n\n

    The compound should be an alkene with eight carbon atoms<\/strong>. The simplest symmetric structure for this alkene would be a compound like 4-octene<\/strong>, which has the following structure:<\/p>\n\n\n\n

      \n
    • Structure of 4-octene<\/strong>:
      CH\u2083-CH\u2082-CH\u2082-CH=CH-CH\u2082-CH\u2082-CH\u2083<\/li>\n<\/ul>\n\n\n\n

      When this is subjected to ozonolysis, the double bond breaks and the resulting fragments would be two identical 4-carbon aldehydes<\/strong> (butanal):<\/p>\n\n\n\n

      Butanal<\/strong> (CH\u2083CH\u2082CHO) is the product of the ozonolysis of 4-octene.<\/p>\n\n\n\n

      Step 4: The Ozonolysis Result<\/h3>\n\n\n\n

      When 4-octene undergoes ozonolysis, the double bond between the 4th and 5th carbon atoms breaks, forming two butanal<\/strong> molecules:<\/p>\n\n\n\n

      Reaction<\/strong>:
      CH\u2083-CH\u2082-CH\u2082-CH=CH-CH\u2082-CH\u2082-CH\u2083 + O\u2083 \u2192 2 CH\u2083CH\u2082CHO (butanal)<\/p>\n\n\n\n

      Step 5: Conclusion<\/h3>\n\n\n\n

      Thus, the structure of the eight-carbon alkene is 4-octene<\/strong>, and the product after ozonolysis with dimethyl sulfide would be butanal<\/strong>.<\/p>\n\n\n\n

      Here is the structure of 4-octene<\/strong> and its ozonolysis product:<\/p>\n\n\n\n

        \n
      • 4-Octene<\/strong>: CH\u2083-CH\u2082-CH\u2082-CH=CH-CH\u2082-CH\u2082-CH\u2083<\/li>\n\n\n\n
      • Butanal<\/strong> (Product): CH\u2083CH\u2082CHO<\/li>\n<\/ul>\n\n\n\n
        \"\"<\/figure>\n\n\n\n

        Here is the image showing the structure of 4-octene<\/strong> and its product after ozonolysis, which results in two molecules of butanal<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"

        Draw the structure of an eight-carbon alkene that would yield the following compound (and no others) after treatment with ozone followed by dimethyl sulfide. The correct answer and explanation is : To solve this problem, let’s break down the reaction and deduce the structure of the eight-carbon alkene. Step 1: Understanding the Reaction When an […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-202548","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/202548","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=202548"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/202548\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=202548"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=202548"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=202548"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}