{"id":202732,"date":"2025-03-18T04:57:10","date_gmt":"2025-03-18T04:57:10","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=202732"},"modified":"2025-03-18T04:57:12","modified_gmt":"2025-03-18T04:57:12","slug":"arrange-the-following-molecules-in-order-of-increasing-dipole-moment","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/18\/arrange-the-following-molecules-in-order-of-increasing-dipole-moment\/","title":{"rendered":"Arrange the following molecules in order of increasing dipole moment"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">Arrange the following molecules in order of increasing dipole moment:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">H2O<br>H2S<br>CBr4<br>NH3<br>CO2<br>HF<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">The correct order of increasing dipole moment is:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>CBr\u2084 &lt; CO\u2082 &lt; H\u2082S &lt; NH\u2083 &lt; H\u2082O &lt; HF<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">The dipole moment ((\\mu)) of a molecule depends on:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Electronegativity Difference<\/strong>: The greater the difference in electronegativity between atoms, the larger the dipole moment.<\/li>\n\n\n\n<li><strong>Molecular Geometry<\/strong>: The shape of the molecule determines whether individual bond dipoles cancel out or add up to create a net dipole.<\/li>\n<\/ol>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>Analysis of Each Molecule:<\/strong><\/h4>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>CBr\u2084 (Carbon Tetrabromide) \u2013 \u03bc = 0 D<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Reason<\/strong>: It has a <strong>tetrahedral<\/strong> structure with <strong>four C\u2013Br bonds<\/strong> that are symmetrically arranged. The individual bond dipoles cancel out, making it a <strong>nonpolar<\/strong> molecule with <strong>zero dipole moment<\/strong>.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>CO\u2082 (Carbon Dioxide) \u2013 \u03bc = 0 D<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Reason<\/strong>: It has a <strong>linear<\/strong> structure, and the two <strong>polar C=O bonds<\/strong> cancel each other out, making CO\u2082 a <strong>nonpolar<\/strong> molecule.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>H\u2082S (Hydrogen Sulfide) \u2013 \u03bc \u2248 0.95 D<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Reason<\/strong>: H\u2082S is <strong>bent<\/strong> like H\u2082O, but <strong>sulfur is less electronegative than oxygen<\/strong> (O = 3.5, S = 2.5), so its dipole moment is smaller than that of H\u2082O.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>NH\u2083 (Ammonia) \u2013 \u03bc \u2248 1.47 D<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Reason<\/strong>: NH\u2083 has a <strong>trigonal pyramidal<\/strong> structure due to <strong>lone pair repulsion<\/strong>. The N-H bonds do not cancel out, resulting in a net dipole.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>H\u2082O (Water) \u2013 \u03bc \u2248 1.85 D<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Reason<\/strong>: H\u2082O has a <strong>bent shape<\/strong> and a large electronegativity difference (O = 3.5, H = 2.1), leading to a higher dipole moment than NH\u2083.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>HF (Hydrogen Fluoride) \u2013 \u03bc \u2248 1.91 D<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Reason<\/strong>: HF has the <strong>largest electronegativity difference<\/strong> (F = 4.0, H = 2.1), resulting in the <strong>highest dipole moment<\/strong> among these molecules.<\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>Arrange the following molecules in order of increasing dipole moment: H2OH2SCBr4NH3CO2HF The correct answer and explanation is : The correct order of increasing dipole moment is: CBr\u2084 &lt; CO\u2082 &lt; H\u2082S &lt; NH\u2083 &lt; H\u2082O &lt; HF Explanation: The dipole moment ((\\mu)) of a molecule depends on: Analysis of Each Molecule:<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-202732","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/202732","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=202732"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/202732\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=202732"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=202732"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=202732"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}