{"id":202795,"date":"2025-03-18T06:11:38","date_gmt":"2025-03-18T06:11:38","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=202795"},"modified":"2025-03-18T06:11:40","modified_gmt":"2025-03-18T06:11:40","slug":"what-is-the-electron-configuration-for-the-cu2-ion","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/18\/what-is-the-electron-configuration-for-the-cu2-ion\/","title":{"rendered":"What Is The Electron Configuration For The Cu2+ Ion"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">What Is The Electron Configuration For The Cu2+ Ion? <\/p>\n\n\n\n<p class=\"wp-block-paragraph\">A) [Ar]4s1, 3d 10 <\/p>\n\n\n\n<p class=\"wp-block-paragraph\">B) [Ar]450, 3d 10 <\/p>\n\n\n\n<p class=\"wp-block-paragraph\">C) [Ar]4s0,3d9 <\/p>\n\n\n\n<p class=\"wp-block-paragraph\">D) [Ar]4s2, 3d9 <\/p>\n\n\n\n<p class=\"wp-block-paragraph\">E) [Ar]450, 3d11<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">The correct answer is:<br><strong>C) [Ar] 4s\u2070 3d\u2079<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation (300 words)<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">To determine the electron configuration of the <strong>Cu\u00b2\u207a (Copper(II) ion)<\/strong>, we first need to know the electron configuration of <strong>neutral copper (Cu)<\/strong>. Copper has an atomic number of <strong>29<\/strong>, and its ground-state electron configuration is:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Cu: [Ar] 4s\u00b9 3d\u00b9\u2070<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">This is an exception to the usual filling order. Normally, we would expect <strong>[Ar] 4s\u00b2 3d\u2079<\/strong>, but copper prefers to have a full <strong>3d<\/strong> subshell by shifting one <strong>4s<\/strong> electron to <strong>3d<\/strong>.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Now, to form the <strong>Cu\u00b2\u207a ion<\/strong>, we remove <strong>two electrons<\/strong> from the neutral Cu atom.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>First electron removal:<\/strong> The <strong>4s<\/strong> electron is removed first because it is higher in energy than the 3d electrons. After this removal, we have:<br><strong>[Ar] 4s\u2070 3d\u00b9\u2070<\/strong><\/li>\n\n\n\n<li><strong>Second electron removal:<\/strong> One electron is then removed from the <strong>3d<\/strong> orbital, since we need to remove two electrons in total:<br><strong>[Ar] 4s\u2070 3d\u2079<\/strong><\/li>\n<\/ol>\n\n\n\n<p class=\"wp-block-paragraph\">Thus, the final electron configuration for <strong>Cu\u00b2\u207a<\/strong> is <strong>[Ar] 4s\u2070 3d\u2079<\/strong>, which corresponds to option <strong>C<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Why Not the Other Choices?<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>A) [Ar] 4s\u00b9 3d\u00b9\u2070<\/strong> \u2192 Incorrect because Cu\u00b2\u207a has no 4s electrons.<\/li>\n\n\n\n<li><strong>B) [Ar] 4s\u2070 3d\u00b9\u2070<\/strong> \u2192 Incorrect because Cu\u00b2\u207a loses one more electron from 3d, leaving 3d\u2079.<\/li>\n\n\n\n<li><strong>D) [Ar] 4s\u00b2 3d\u2079<\/strong> \u2192 Incorrect because Cu does not have 4s\u00b2 in its ground state.<\/li>\n\n\n\n<li><strong>E) [Ar] 4s\u2070 3d\u00b9\u00b9<\/strong> \u2192 Incorrect because Cu has only 10 d-electrons at most.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Conclusion<\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">The correct answer is <strong>C) [Ar] 4s\u2070 3d\u2079<\/strong>, following the correct order of electron removal and considering the unique electron configuration of copper.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>What Is The Electron Configuration For The Cu2+ Ion? A) [Ar]4s1, 3d 10 B) [Ar]450, 3d 10 C) [Ar]4s0,3d9 D) [Ar]4s2, 3d9 E) [Ar]450, 3d11 The correct answer and explanation is : The correct answer is:C) [Ar] 4s\u2070 3d\u2079 Explanation (300 words) To determine the electron configuration of the Cu\u00b2\u207a (Copper(II) ion), we first need [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-202795","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/202795","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=202795"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/202795\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=202795"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=202795"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=202795"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}