{"id":203078,"date":"2025-03-18T17:50:23","date_gmt":"2025-03-18T17:50:23","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=203078"},"modified":"2025-03-18T17:50:29","modified_gmt":"2025-03-18T17:50:29","slug":"provide-the-reagents-necessary-to-accomplish-the-following-transformatio","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/18\/provide-the-reagents-necessary-to-accomplish-the-following-transformatio\/","title":{"rendered":"Provide the reagents necessary to accomplish the following transformatio"},"content":{"rendered":"\n<p>Provide the reagents necessary to accomplish the following transformation.\u00a0<img decoding=\"async\" src=\"https:\/\/files.transtutors.com\/book\/qimg\/7b89e98d-da4e-483c-a357-cdb31dc1b421.png\" alt=\"Description: 42) Provide the reagents necessary to accomplish the following transformation. methyl benzoate (PhCO2CH3) to benzyl alcohol (PhCH20H) 43) Provide the structure of the major organic product in the reaction shown below. NaBH4 CH3 HOCH3 44) Provide the structure of the major organic product in the reaction below. 0 H2 (excess) Raney Ni 45) Provide the major organic product(s) of the reaction below. ??? CH3 NaBH4, CH OH H3C\"><br><\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\">The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>Let&#8217;s break down the requested transformations and reactions step by step:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">42) <strong>Reagents for the transformation from methyl benzoate (PhCO2CH3) to benzyl alcohol (PhCH2OH)<\/strong><\/h3>\n\n\n\n<p>The transformation of <strong>methyl benzoate<\/strong> (PhCO2CH3) to <strong>benzyl alcohol<\/strong> (PhCH2OH) involves the reduction of the ester group (CO2CH3) to a -CH2OH group. The proper reagent for this reduction is <strong>borane (BH3)<\/strong> or <strong>diborane (B2H6)<\/strong> in tetrahydrofuran (THF), followed by hydrolysis.<\/p>\n\n\n\n<p><strong>Reagents:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Borane (BH3) or Diborane (B2H6)<\/strong>, in <strong>THF<\/strong> (tetrahydrofuran) solvent.<\/li>\n\n\n\n<li><strong>Hydrolysis<\/strong> (usually with water and mild acid or base) to replace the boron atom with a hydroxyl group.<\/li>\n<\/ul>\n\n\n\n<p><strong>Reaction Mechanism:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The borane (BH3) reacts with the ester group of methyl benzoate. It selectively reduces the ester to the corresponding alcohol (benzyl alcohol), breaking the ester bond and forming the -CH2OH group in place of the ester functionality.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">43) <strong>Major Organic Product from the Reaction: NaBH4, CH3OH<\/strong><\/h3>\n\n\n\n<p><strong>Reaction:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The <strong>reduction<\/strong> of a carbonyl compound (likely an aldehyde or ketone) using <strong>sodium borohydride (NaBH4)<\/strong> in <strong>methanol (CH3OH)<\/strong> solvent.<\/li>\n<\/ul>\n\n\n\n<p><strong>Major Product:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Sodium borohydride (NaBH4) reduces <strong>carbonyl compounds<\/strong> (like aldehydes and ketones) to <strong>alcohols<\/strong>. If the starting compound is an aldehyde or ketone, the major product will be the corresponding <strong>primary or secondary alcohol<\/strong>, respectively.<\/li>\n\n\n\n<li>For example, if the starting material is <strong>acetone (CH3COCH3)<\/strong>, the major product would be <strong>isopropyl alcohol (CH3CHOHCH3)<\/strong>.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">44) <strong>Major Organic Product from the Reaction: H2 (excess), Raney Ni<\/strong><\/h3>\n\n\n\n<p><strong>Reaction:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Hydrogenation<\/strong> of a <strong>carbonyl compound<\/strong> or <strong>double bond<\/strong> using <strong>hydrogen gas (H2)<\/strong> and <strong>Raney nickel (Ni)<\/strong> as a catalyst.<\/li>\n<\/ul>\n\n\n\n<p><strong>Major Product:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The <strong>hydrogenation<\/strong> reaction would typically reduce a <strong>carbonyl compound (such as an aldehyde or ketone)<\/strong> or <strong>alkene<\/strong> to the corresponding <strong>alcohol<\/strong> or <strong>alkane<\/strong>.<\/li>\n\n\n\n<li>If the starting compound is a <strong>carbonyl compound<\/strong>, it would be reduced to an alcohol.<\/li>\n\n\n\n<li>If it&#8217;s an <strong>alkene<\/strong>, the reaction would saturate the double bond, yielding a <strong>saturated alkane<\/strong>.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">45) <strong>Major Organic Product(s) of the Reaction: NaBH4, CH3OH<\/strong><\/h3>\n\n\n\n<p><strong>Reagents:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Sodium borohydride (NaBH4)<\/strong> in <strong>methanol (CH3OH)<\/strong>.<\/li>\n<\/ul>\n\n\n\n<p><strong>Major Product:<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>NaBH4<\/strong> is a selective reducing agent that can reduce <strong>carbonyl compounds<\/strong> such as aldehydes and ketones to <strong>alcohols<\/strong>.<\/li>\n\n\n\n<li>In methanol (CH3OH) as a solvent, the <strong>methanol<\/strong> might also participate in the reaction under specific conditions, especially if the aldehyde or ketone is reactive.<\/li>\n<\/ul>\n\n\n\n<p>If the reaction involves a <strong>ketone<\/strong> such as <strong>acetone (CH3COCH3)<\/strong>, the product would be <strong>isopropyl alcohol (CH3CHOHCH3)<\/strong>. If it involves an <strong>aldehyde<\/strong>, the product would be the corresponding <strong>primary alco<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Provide the reagents necessary to accomplish the following transformation.\u00a0 The correct answer and explanation is: Let&#8217;s break down the requested transformations and reactions step by step: 42) Reagents for the transformation from methyl benzoate (PhCO2CH3) to benzyl alcohol (PhCH2OH) The transformation of methyl benzoate (PhCO2CH3) to benzyl alcohol (PhCH2OH) involves the reduction of the ester [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-203078","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/203078","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=203078"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/203078\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=203078"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=203078"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=203078"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}