{"id":203196,"date":"2025-03-18T19:13:03","date_gmt":"2025-03-18T19:13:03","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=203196"},"modified":"2025-03-18T19:13:05","modified_gmt":"2025-03-18T19:13:05","slug":"the-chemical-reaction-of-2-butene-and-hcl-yields-what-product","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/18\/the-chemical-reaction-of-2-butene-and-hcl-yields-what-product\/","title":{"rendered":"The chemical reaction of 2 butene and HCl yields what product"},"content":{"rendered":"\n<p>The chemical reaction of 2 butene and HCl yields what product? \u25ba View Available Hint(s)<\/p>\n\n\n\n<p>Submit Part B<\/p>\n\n\n\n<p>In an addition reaction of water (HOH) to an unsymmetrical alkene, the hydrogen adds to the carbon in the double bond:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>that has the smaller number of hydrogen atoms attached<\/li>\n\n\n\n<li>that has the greater number of hydrogen atoms attached<\/li>\n\n\n\n<li>that has the smaller number of carbon atoms attached<\/li>\n<\/ul>\n\n\n\n<p>Submit Part C<\/p>\n\n\n\n<p>The major product of the reaction of methyl-2-pentene with HCl is:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>4-chloro-3-methylpentane<\/li>\n\n\n\n<li>1-chloro-3-methylpentane<\/li>\n\n\n\n<li>3-chloro-3-methylpentane<\/li>\n\n\n\n<li>2-chloro-3-methylpentane<\/li>\n<\/ul>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\">The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Answers:<\/h3>\n\n\n\n<p><strong>Part A:<\/strong> The reaction of <strong>2-butene<\/strong> with <strong>HCl<\/strong> yields <strong>2-chlorobutane<\/strong> as the major product.<br><strong>Part B:<\/strong> In the addition reaction of <strong>water (HOH) to an unsymmetrical alkene<\/strong>, the <strong>hydrogen adds to the carbon in the double bond that has the greater number of hydrogen atoms attached<\/strong>. (This follows <strong>Markovnikov\u2019s rule<\/strong>.)<br><strong>Part C:<\/strong> The major product of the reaction of <strong>methyl-2-pentene with HCl<\/strong> is <strong>3-chloro-3-methylpentane<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation (300 words):<\/strong><\/h3>\n\n\n\n<p>The reaction of <strong>2-butene<\/strong> with <strong>hydrogen chloride (HCl)<\/strong> follows an <strong>electrophilic addition<\/strong> mechanism. Since 2-butene is symmetrical (i.e., the double bond is between carbon-2 and carbon-3), HCl adds across the double bond according to <strong>Markovnikov\u2019s rule<\/strong>. This rule states that the <strong>hydrogen atom (H\u207a) adds to the carbon that already has more hydrogen atoms<\/strong>, while the <strong>chloride ion (Cl\u207b) attaches to the more substituted carbon<\/strong>. As a result, <strong>2-chlorobutane<\/strong> is the major product.<\/p>\n\n\n\n<p>For the <strong>addition of water (HOH) to an unsymmetrical alkene<\/strong>, <strong>Markovnikov\u2019s rule<\/strong> applies again. The hydrogen from the water molecule will add to the carbon with <strong>more hydrogens<\/strong>, while the hydroxyl group (<strong>\u2013OH<\/strong>) will attach to the more substituted carbon. This stabilizes the <strong>carbocation intermediate<\/strong>, making the reaction more favorable.<\/p>\n\n\n\n<p>In the reaction of <strong>methyl-2-pentene<\/strong> with <strong>HCl<\/strong>, we first identify the most stable <strong>carbocation intermediate<\/strong>. When H\u207a adds to the double bond, it creates a <strong>tertiary carbocation<\/strong>, which is the most stable. The chloride ion (<strong>Cl\u207b<\/strong>) then attacks the carbocation, leading to the formation of <strong>3-chloro-3-methylpentane<\/strong>, which is the <strong>major product<\/strong>.<\/p>\n\n\n\n<p>Thus, these reactions follow predictable patterns based on <strong>carbocation stability<\/strong> and <strong>Markovnikov\u2019s rule<\/strong>, ensuring the most stable product forms.<\/p>\n\n\n\n<p>Now, let&#8217;s generate an image illustrating the <strong>reaction mechanisms<\/strong> for these transformations.<\/p>\n\n\n\n<p>Here is an image illustrating the electrophilic addition reactions of <strong>2-butene with HCl<\/strong> and <strong>methyl-2-pentene with HCl<\/strong>, showing the formation of <strong>2-chlorobutane<\/strong> and <strong>3-chloro-3-methylpentane<\/strong>, respectively. The diagram includes stepwise mechanisms with labeled molecular structures and electron movement arrows. Let me know if you need any modifications!<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/03\/image-1062.png\" alt=\"\" class=\"wp-image-203209\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>The chemical reaction of 2 butene and HCl yields what product? \u25ba View Available Hint(s) Submit Part B In an addition reaction of water (HOH) to an unsymmetrical alkene, the hydrogen adds to the carbon in the double bond: Submit Part C The major product of the reaction of methyl-2-pentene with HCl is: The correct [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-203196","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/203196","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=203196"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/203196\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=203196"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=203196"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=203196"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}