{"id":203406,"date":"2025-03-19T17:52:03","date_gmt":"2025-03-19T17:52:03","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=203406"},"modified":"2025-03-19T17:52:06","modified_gmt":"2025-03-19T17:52:06","slug":"draw-two-constitutional-isomers-of-molecular-formula-c4h8o2-that-contain-an-ester","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/19\/draw-two-constitutional-isomers-of-molecular-formula-c4h8o2-that-contain-an-ester\/","title":{"rendered":"Draw Two Constitutional Isomers Of Molecular Formula C4H8O2 That Contain An Ester"},"content":{"rendered":"\n<p>Draw Two Constitutional Isomers Of Molecular Formula C4H8O2 That Contain An Ester.<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Answer:<\/h3>\n\n\n\n<p>The two constitutional isomers of molecular formula <strong>C\u2084H\u2088O\u2082<\/strong> that contain an <strong>ester<\/strong> functional group are:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Methyl propanoate (Methyl propionate)<\/strong> \u2013 <strong>CH\u2083CH\u2082COOCH\u2083<\/strong><\/li>\n\n\n\n<li><strong>Ethyl ethanoate (Ethyl acetate)<\/strong> \u2013 <strong>CH\u2083COOCH\u2082CH\u2083<\/strong><\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<h4 class=\"wp-block-heading\">1. <strong>Understanding Constitutional Isomers<\/strong><\/h4>\n\n\n\n<p>Constitutional isomers (also known as structural isomers) have the <strong>same molecular formula<\/strong> but differ in the <strong>connectivity of atoms<\/strong>. Since the question specifies that the isomers must contain an <strong>ester functional group (-COO-),<\/strong> we focus on different ways to arrange the <strong>C, H, and O atoms<\/strong> while keeping the ester functionality.<\/p>\n\n\n\n<h4 class=\"wp-block-heading\">2. <strong>Molecular Formula Analysis<\/strong><\/h4>\n\n\n\n<p>The given molecular formula is <strong>C\u2084H\u2088O\u2082<\/strong>.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>This suggests that the molecule follows the <strong>general formula of esters, CnH\u2082nO\u2082<\/strong> (which matches with C\u2084H\u2088O\u2082).<\/li>\n\n\n\n<li>The presence of <strong>oxygen atoms<\/strong> suggests that the compound contains either a <strong>carboxyl (-COOH), ester (-COO-), or other oxygen-containing functional groups.<\/strong><\/li>\n\n\n\n<li>However, since the problem specifically requires <strong>esters<\/strong>, we exclude carboxylic acids.<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\">3. <strong>Drawing the Two Isomers<\/strong><\/h4>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Methyl Propanoate (Methyl Propionate) \u2013 CH\u2083CH\u2082COOCH\u2083<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>This ester is formed from <strong>propanoic acid (CH\u2083CH\u2082COOH)<\/strong> and <strong>methanol (CH\u2083OH)<\/strong>.<\/li>\n\n\n\n<li>The ester group <strong>(-COO-)<\/strong> is placed between a <strong>propyl (CH\u2083CH\u2082CO-)<\/strong> and a <strong>methyl (CH\u2083) group<\/strong>.<\/li>\n<\/ul>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Ethyl Ethanoate (Ethyl Acetate) \u2013 CH\u2083COOCH\u2082CH\u2083<\/strong><\/li>\n<\/ol>\n\n\n\n<ul class=\"wp-block-list\">\n<li>This ester is formed from <strong>acetic acid (CH\u2083COOH)<\/strong> and <strong>ethanol (CH\u2083CH\u2082OH)<\/strong>.<\/li>\n\n\n\n<li>The ester group <strong>(-COO-)<\/strong> is placed between an <strong>acetyl (CH\u2083CO-)<\/strong> and an <strong>ethyl (CH\u2082CH\u2083) group<\/strong>.<\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\">4. <strong>Differences Between the Isomers<\/strong><\/h4>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Different connectivity<\/strong>: Methyl propanoate has a <strong>propanoate (CH\u2083CH\u2082COO-)<\/strong> backbone, while ethyl acetate has an <strong>acetate (CH\u2083COO-)<\/strong> backbone.<\/li>\n\n\n\n<li><strong>Different chemical properties<\/strong>: Slightly different boiling points and solubility due to the molecular structure.<\/li>\n\n\n\n<li><strong>Different IUPAC names<\/strong>: Methyl propanoate vs. Ethyl acetate.<\/li>\n<\/ul>\n\n\n\n<p>Thus, the two valid constitutional isomers of <strong>C\u2084H\u2088O\u2082<\/strong> containing an <strong>ester<\/strong> group are <strong>methyl propanoate and ethyl acetate<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Draw Two Constitutional Isomers Of Molecular Formula C4H8O2 That Contain An Ester. The correct answer and explanation is : Answer: The two constitutional isomers of molecular formula C\u2084H\u2088O\u2082 that contain an ester functional group are: Explanation: 1. Understanding Constitutional Isomers Constitutional isomers (also known as structural isomers) have the same molecular formula but differ in [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-203406","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/203406","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=203406"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/203406\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=203406"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=203406"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=203406"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}