{"id":203587,"date":"2025-03-20T09:50:44","date_gmt":"2025-03-20T09:50:44","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=203587"},"modified":"2025-03-20T09:50:46","modified_gmt":"2025-03-20T09:50:46","slug":"write-structural-formulas-or-build-molecular-models-and-give-the-iupac-names-for-all-the-alkenes-of-molecular-formula-c6h12-that-contain-a-trisubstituted-double-bond","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/20\/write-structural-formulas-or-build-molecular-models-and-give-the-iupac-names-for-all-the-alkenes-of-molecular-formula-c6h12-that-contain-a-trisubstituted-double-bond\/","title":{"rendered":"Write structural formulas or build molecular models and give the IUPAC names for all the alkenes of molecular formula C6H12 that contain a trisubstituted double bond"},"content":{"rendered":"\n<p>Write structural formulas or build molecular models and give the IUPAC names for all the alkenes of molecular formula C6H12 that contain a trisubstituted double bond. (Don\u2019t forget to include stereoisomers.)<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Structural Formulas and IUPAC Names for Trisubstituted Alkenes (C\u2086H\u2081\u2082)<\/strong><\/h3>\n\n\n\n<p>The molecular formula <strong>C\u2086H\u2081\u2082<\/strong> corresponds to <strong>alkenes (CnH\u2082n)<\/strong> with one double bond. A <strong>trisubstituted alkene<\/strong> has a double bond where three carbon atoms are directly attached to the sp\u00b2 hybridized carbons.<\/p>\n\n\n\n<p>Here are all the possible <strong>trisubstituted alkenes<\/strong> for C\u2086H\u2081\u2082, including their structural formulas and <strong>IUPAC names<\/strong>:<\/p>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>1. 2-Methylpent-2-ene<\/strong><\/h4>\n\n\n\n<p><strong>Structural Formula:<\/strong><\/p>\n\n\n\n<pre class=\"wp-block-code\"><code>      CH3  \n       |  \nCH3-CH=C-CH2-CH3<\/code><\/pre>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>IUPAC Name:<\/strong> <strong>2-Methylpent-2-ene<\/strong><\/li>\n\n\n\n<li>Has <strong>E\/Z isomers<\/strong> due to different groups attached to the double bond:<\/li>\n\n\n\n<li><strong>(E)-2-Methylpent-2-ene<\/strong><\/li>\n\n\n\n<li><strong>(Z)-2-Methylpent-2-ene<\/strong><\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>2. 3-Methylpent-2-ene<\/strong><\/h4>\n\n\n\n<p><strong>Structural Formula:<\/strong><\/p>\n\n\n\n<pre class=\"wp-block-code\"><code>      CH3  \n       |  \nCH3-CH=C-CH-CH3  \n         |  \n        CH3  <\/code><\/pre>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>IUPAC Name:<\/strong> <strong>3-Methylpent-2-ene<\/strong><\/li>\n\n\n\n<li>Has <strong>E\/Z isomers<\/strong>:<\/li>\n\n\n\n<li><strong>(E)-3-Methylpent-2-ene<\/strong><\/li>\n\n\n\n<li><strong>(Z)-3-Methylpent-2-ene<\/strong><\/li>\n<\/ul>\n\n\n\n<h4 class=\"wp-block-heading\"><strong>3. 2,3-Dimethylbut-2-ene<\/strong><\/h4>\n\n\n\n<p><strong>Structural Formula:<\/strong><\/p>\n\n\n\n<pre class=\"wp-block-code\"><code>    CH3     CH3  \n      \\     \/  \n       C=C  \n      \/     \\  \n    CH3     CH3  <\/code><\/pre>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>IUPAC Name:<\/strong> <strong>2,3-Dimethylbut-2-ene<\/strong><\/li>\n\n\n\n<li><strong>No E\/Z isomerism<\/strong> because both sides of the double bond have identical groups.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation (300 words)<\/strong><\/h3>\n\n\n\n<p>A <strong>trisubstituted alkene<\/strong> has three carbon groups attached to the doubly bonded carbons. For C\u2086H\u2081\u2082, we must systematically find structures that satisfy this criterion.<\/p>\n\n\n\n<p><strong>Step 1: Identify the Carbon Skeleton<\/strong><br>Since C\u2086H\u2081\u2082 has <strong>six carbons<\/strong> and <strong>one double bond<\/strong>, we consider various straight-chain and branched structures while ensuring three carbon groups are attached to the alkene carbon atoms.<\/p>\n\n\n\n<p><strong>Step 2: Positioning the Double Bond<\/strong><br>By placing the <strong>C=C bond<\/strong> at different positions in the <strong>pentane and butane skeletons<\/strong>, we identify potential <strong>trisubstituted configurations<\/strong>:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Pentane backbone:<\/strong> 2-Methylpent-2-ene, 3-Methylpent-2-ene<\/li>\n\n\n\n<li><strong>Butane backbone:<\/strong> 2,3-Dimethylbut-2-ene<\/li>\n<\/ul>\n\n\n\n<p><strong>Step 3: Stereoisomerism Consideration<\/strong><br>Alkenes with different <strong>substituents on each double-bonded carbon<\/strong> exhibit <strong>E\/Z (cis-trans) isomerism<\/strong> due to restricted rotation around the double bond.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>2-Methylpent-2-ene<\/strong> and <strong>3-Methylpent-2-ene<\/strong> each have <strong>E\/Z isomers<\/strong> because of distinct groups on both sp\u00b2 carbons.<\/li>\n\n\n\n<li><strong>2,3-Dimethylbut-2-ene<\/strong> does not have E\/Z isomerism since both sp\u00b2 carbons have identical groups.<\/li>\n<\/ul>\n\n\n\n<p>Thus, the <strong>final answer<\/strong> includes <strong>five unique structures<\/strong>: three base structures and two E\/Z isomers for two of them.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Write structural formulas or build molecular models and give the IUPAC names for all the alkenes of molecular formula C6H12 that contain a trisubstituted double bond. (Don\u2019t forget to include stereoisomers.) The correct answer and explanation is : Structural Formulas and IUPAC Names for Trisubstituted Alkenes (C\u2086H\u2081\u2082) The molecular formula C\u2086H\u2081\u2082 corresponds to alkenes (CnH\u2082n) [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-203587","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/203587","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=203587"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/203587\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=203587"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=203587"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=203587"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}