{"id":203892,"date":"2025-03-21T02:36:45","date_gmt":"2025-03-21T02:36:45","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=203892"},"modified":"2025-03-21T02:36:48","modified_gmt":"2025-03-21T02:36:48","slug":"draw-energy-lewis-structure-for-hsip","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/21\/draw-energy-lewis-structure-for-hsip\/","title":{"rendered":"Draw energy Lewis Structure for HSiP"},"content":{"rendered":"\n<p>1) Draw energy Lewis Structure for HSiP. (Si is the central atom.)<\/p>\n\n\n\n<p>Which the following is true?<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Overall, there are three unshared electron pairs, and two double bonds.<\/li>\n\n\n\n<li>There are all single bonds in this molecule.<\/li>\n\n\n\n<li>Overall, there is one unshared electron pair, one single bond, and one triple bond.<\/li>\n\n\n\n<li>There are three unshared electron pairs and a double bond.<\/li>\n\n\n\n<li>Overall, there are two double bonds and one unshared electron pair.<\/li>\n<\/ul>\n\n\n\n<p>2) Select any of the following that are NOT&nbsp;<strong>elements.<\/strong>&nbsp;There may or may not be more than one.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>osmium<\/li>\n\n\n\n<li>hydrogen peroxide<\/li>\n\n\n\n<li>cadmium<\/li>\n\n\n\n<li>bronze<\/li>\n\n\n\n<li>strontium<\/li>\n<\/ul>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\">The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">1) Lewis Structure of HSiP<\/h3>\n\n\n\n<p>To draw the Lewis structure of HSiP with silicon (Si) as the central atom, follow these steps:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Determine the valence electrons<\/strong>\n<ul class=\"wp-block-list\">\n<li>Hydrogen (H) = 1 valence electron<\/li>\n\n\n\n<li>Silicon (Si) = 4 valence electrons<\/li>\n\n\n\n<li>Phosphorus (P) = 5 valence electrons<\/li>\n\n\n\n<li>Total = 1 + 4 + 5 = 10 valence electrons<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Arrange the atoms<\/strong>\n<ul class=\"wp-block-list\">\n<li>Silicon is the central atom. Hydrogen and phosphorus are bonded to silicon.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Distribute electrons to satisfy the octet rule<\/strong>\n<ul class=\"wp-block-list\">\n<li>Hydrogen needs only 2 electrons (single bond with Si).<\/li>\n\n\n\n<li>Phosphorus typically forms three bonds but can form a <strong>triple bond<\/strong> with Si.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li><strong>Check the bonding and lone pairs<\/strong>\n<ul class=\"wp-block-list\">\n<li>A <strong>single bond<\/strong> exists between Si and H.<\/li>\n\n\n\n<li>A <strong>triple bond<\/strong> exists between Si and P.<\/li>\n\n\n\n<li>Silicon has <strong>no lone pairs<\/strong>, while phosphorus has <strong>one lone pair<\/strong>.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n<p>Thus, the correct answer is:<br>\u2705 <strong>&#8220;Overall, there is one unshared electron pair, one single bond, and one triple bond.&#8221;<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">2) Identifying Non-Elements<\/h3>\n\n\n\n<p>Elements are pure substances that consist of only one type of atom. Compounds and mixtures are <strong>not<\/strong> elements. Let&#8217;s analyze the given options:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Osmium (Os)<\/strong> \u2013 An element, atomic number <strong>76<\/strong>. \u2705 (Element)<\/li>\n\n\n\n<li><strong>Hydrogen peroxide (H\u2082O\u2082)<\/strong> \u2013 A <strong>compound<\/strong> (made of hydrogen and oxygen). \u274c <strong>(Not an element)<\/strong><\/li>\n\n\n\n<li><strong>Cadmium (Cd)<\/strong> \u2013 An element, atomic number <strong>48<\/strong>. \u2705 (Element)<\/li>\n\n\n\n<li><strong>Bronze<\/strong> \u2013 A <strong>mixture<\/strong> of copper and tin. \u274c <strong>(Not an element)<\/strong><\/li>\n\n\n\n<li><strong>Strontium (Sr)<\/strong> \u2013 An element, atomic number <strong>38<\/strong>. \u2705 (Element)<\/li>\n<\/ol>\n\n\n\n<p>Thus, the correct answers are:<br>\u2705 <strong>Hydrogen peroxide<\/strong><br>\u2705 <strong>Bronze<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation<\/h3>\n\n\n\n<p>An element is a pure substance that cannot be broken down into simpler substances by chemical means. Each element consists of only one type of atom, defined by its atomic number. Examples include <strong>osmium (Os), cadmium (Cd), and strontium (Sr)<\/strong>, all of which appear on the periodic table.<\/p>\n\n\n\n<p><strong>Hydrogen peroxide (H\u2082O\u2082)<\/strong> is not an element because it consists of two different atoms, <strong>hydrogen (H) and oxygen (O)<\/strong>, chemically bonded. This makes it a <strong>compound<\/strong> rather than a single-element substance.<\/p>\n\n\n\n<p><strong>Bronze<\/strong> is a <strong>mixture<\/strong>, not an element. It is primarily composed of <strong>copper (Cu) and tin (Sn)<\/strong>, sometimes with other metals added for strength. Since mixtures can be separated into their components by physical means, they are not elements.<\/p>\n\n\n\n<p>On the other hand, <strong>osmium, cadmium, and strontium<\/strong> are pure elements with specific atomic structures and properties, making them fundamental building blocks in chemistry.<\/p>\n\n\n\n<p>In summary, <strong>hydrogen peroxide and bronze are NOT elements<\/strong> because one is a compound, and the other is a mixture. However, <strong>osmium, cadmium, and strontium are elements<\/strong> because they consist of only one type of atom.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p>Now, I&#8217;ll generate an image of the <strong>Lewis structure of HSiP<\/strong>.<\/p>\n\n\n\n<p>Here is the Lewis structure of <strong>HSiP<\/strong>, showing the <strong>single bond<\/strong> between Si and H, the <strong>triple bond<\/strong> between Si and P, and the <strong>lone pair on P<\/strong>. Let me know if you need any modifications!<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/03\/image-1125.png\" alt=\"\" class=\"wp-image-203893\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>1) Draw energy Lewis Structure for HSiP. (Si is the central atom.) Which the following is true? 2) Select any of the following that are NOT&nbsp;elements.&nbsp;There may or may not be more than one. The correct answer and explanation is: 1) Lewis Structure of HSiP To draw the Lewis structure of HSiP with silicon (Si) [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-203892","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/203892","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=203892"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/203892\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=203892"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=203892"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=203892"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}