One feature of the SN1 type of reaction? <\/p>\n\n\n\n
a) Racemization <\/p>\n\n\n\n
b) Dehydration <\/p>\n\n\n\n
c) Planarization <\/p>\n\n\n\n
d) Elimination <\/p>\n\n\n\n
e) a and c<\/p>\n\n\n\n
The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n The SN1 (Substitution Nucleophilic Unimolecular)<\/strong> reaction is a two-step process involving the formation of a carbocation intermediate. The key features of an SN1 reaction include:<\/p>\n\n\n\n The two key features of the SN1 mechanism are planarization<\/strong> due to carbocation formation and racemization<\/strong> of chiral substrates. Hence, the correct answer is (e) a and c<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":" One feature of the SN1 type of reaction? a) Racemization b) Dehydration c) Planarization d) Elimination e) a and c The correct answer and explanation is : Correct Answer: (e) a and c (Racemization and Planarization) The SN1 (Substitution Nucleophilic Unimolecular) reaction is a two-step process involving the formation of a carbocation intermediate. The key […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-203952","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/203952","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=203952"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/203952\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=203952"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=203952"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=203952"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}Correct Answer: (e) a and c (Racemization and Planarization)<\/strong><\/h3>\n\n\n\n
\n
In the first step, the leaving group departs, forming a positively charged carbocation<\/strong>. This intermediate has a trigonal planar geometry<\/strong> due to the sp\u00b2 hybridization<\/strong> of the central carbon. This planar structure is crucial because it allows the nucleophile to attack from either side of the molecule, leading to racemization<\/strong> if the substrate is chiral.<\/li>\n\n\n\n
Since the carbocation intermediate is planar<\/strong>, the incoming nucleophile can attack from either the front or the back<\/strong> with equal probability. If the starting material is chiral, this results in a mixture of retention and inversion<\/strong> of configuration. However, in most cases, a slight preference for inversion is observed due to the partial shielding effect of the departing leaving group. Nevertheless, the overall product is a racemic mixture<\/strong>.<\/li>\n\n\n\n\n
Conclusion<\/h3>\n\n\n\n