{"id":203983,"date":"2025-03-21T08:01:14","date_gmt":"2025-03-21T08:01:14","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=203983"},"modified":"2025-03-21T08:01:16","modified_gmt":"2025-03-21T08:01:16","slug":"if-a-compound-is-reduced-what-is-the-result-2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/21\/if-a-compound-is-reduced-what-is-the-result-2\/","title":{"rendered":"If a compound is reduced, what is the result"},"content":{"rendered":"\n

If a compound is reduced, what is the result?<\/p>\n\n\n\n

Fewer C-H bonds
Increased number of C-H bonds
Fewer C-Z bonds
Both increased number of C-H bonds and fewer C-Z bonds<\/p>\n\n\n\n

The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n

Correct Answer:<\/h3>\n\n\n\n

Both increased number of C-H bonds and fewer C-Z bonds<\/strong><\/p>\n\n\n\n

Explanation:<\/h3>\n\n\n\n

Reduction in organic chemistry refers to the gain of electrons by a molecule, which often corresponds to an increase in the number of hydrogen (H) atoms or a decrease in the number of bonds to more electronegative atoms (such as oxygen, nitrogen, or halogens, represented as Z).<\/p>\n\n\n\n

    \n
  1. Increase in C-H Bonds<\/strong><\/li>\n<\/ol>\n\n\n\n
      \n
    • Reduction commonly involves the addition of hydrogen atoms to a carbon framework.<\/li>\n\n\n\n
    • For example, the reduction of an alkene (C=C) to an alkane (C-C) using hydrogen gas and a catalyst (e.g., H\u2082\/Pd) results in an increase in the number of C-H bonds.<\/li>\n\n\n\n
    • Similarly, the reduction of a ketone (C=O) to an alcohol (C-OH) involves the addition of hydrogen, increasing the number of C-H bonds on the formerly carbonyl carbon.<\/li>\n<\/ul>\n\n\n\n
        \n
      1. Decrease in C-Z Bonds<\/strong><\/li>\n<\/ol>\n\n\n\n
          \n
        • Reduction also decreases the number of bonds between carbon and more electronegative atoms (Z), such as oxygen, nitrogen, or halogens.<\/li>\n\n\n\n
        • For example, the reduction of a carboxylic acid (R-COOH) to an aldehyde (R-CHO) or an alcohol (R-CH\u2082OH) removes C=O bonds, replacing them with C-H or C-OH bonds.<\/li>\n\n\n\n
        • The same concept applies to halogenated compounds where reduction (e.g., Zn\/HCl) removes halogen atoms, leading to fewer C-Z bonds.<\/li>\n<\/ul>\n\n\n\n

          Thus, reduction generally leads to both an increase in C-H bonds and a decrease in C-Z bonds<\/strong>, making the correct answer “Both increased number of C-H bonds and fewer C-Z bonds.”<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"

          If a compound is reduced, what is the result? Fewer C-H bondsIncreased number of C-H bondsFewer C-Z bondsBoth increased number of C-H bonds and fewer C-Z bonds The correct answer and explanation is : Correct Answer: Both increased number of C-H bonds and fewer C-Z bonds Explanation: Reduction in organic chemistry refers to the gain […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-203983","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/203983","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=203983"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/203983\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=203983"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=203983"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=203983"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}