{"id":204198,"date":"2025-03-21T15:50:43","date_gmt":"2025-03-21T15:50:43","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=204198"},"modified":"2025-03-21T15:50:46","modified_gmt":"2025-03-21T15:50:46","slug":"determine-the-empirical-formulas-for-the-following-compounds","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/21\/determine-the-empirical-formulas-for-the-following-compounds\/","title":{"rendered":"Determine the empirical formulas for the following compounds"},"content":{"rendered":"\n<p>Determine the empirical formulas for the following compounds:<\/p>\n\n\n\n<p>caffeine, C8H10N4O2<br>fructose, C12H22O11<br>hydrogen peroxide, H2O2<br>glucose, C6H12O6<br>ascorbic acid (vitamin C), C6H8O6<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>To determine the empirical formula of a compound, we need to find the simplest whole-number ratio of the elements present in the compound. The empirical formula represents the smallest ratio of the atoms of each element in the compound.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">1. <strong>Caffeine, C\u2088H\u2081\u2080N\u2084O\u2082<\/strong><\/h3>\n\n\n\n<p>The molecular formula of caffeine is given as <strong>C\u2088H\u2081\u2080N\u2084O\u2082<\/strong>. To find the empirical formula, we divide each subscript by the greatest common divisor (GCD) of the subscripts.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Carbon (C) = 8<\/li>\n\n\n\n<li>Hydrogen (H) = 10<\/li>\n\n\n\n<li>Nitrogen (N) = 4<\/li>\n\n\n\n<li>Oxygen (O) = 2<\/li>\n<\/ul>\n\n\n\n<p>The greatest common divisor of 8, 10, 4, and 2 is 2. Dividing each by 2:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>C: 8 \u00f7 2 = 4<\/li>\n\n\n\n<li>H: 10 \u00f7 2 = 5<\/li>\n\n\n\n<li>N: 4 \u00f7 2 = 2<\/li>\n\n\n\n<li>O: 2 \u00f7 2 = 1<\/li>\n<\/ul>\n\n\n\n<p>So, the empirical formula for caffeine is <strong>C\u2084H\u2085N\u2082O<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">2. <strong>Fructose, C\u2081\u2082H\u2082\u2082O\u2081\u2081<\/strong><\/h3>\n\n\n\n<p>The molecular formula of fructose is <strong>C\u2081\u2082H\u2082\u2082O\u2081\u2081<\/strong>. To find the empirical formula, we again divide each subscript by the GCD.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Carbon (C) = 12<\/li>\n\n\n\n<li>Hydrogen (H) = 22<\/li>\n\n\n\n<li>Oxygen (O) = 11<\/li>\n<\/ul>\n\n\n\n<p>The greatest common divisor of 12, 22, and 11 is 1, meaning the formula is already in its simplest form. Therefore, the empirical formula for fructose is <strong>C\u2081\u2082H\u2082\u2082O\u2081\u2081<\/strong> (same as the molecular formula).<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">3. <strong>Hydrogen Peroxide, H\u2082O\u2082<\/strong><\/h3>\n\n\n\n<p>The molecular formula of hydrogen peroxide is <strong>H\u2082O\u2082<\/strong>. The subscripts for hydrogen (H) and oxygen (O) are both 2.<\/p>\n\n\n\n<p>Dividing both by 2:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>H: 2 \u00f7 2 = 1<\/li>\n\n\n\n<li>O: 2 \u00f7 2 = 1<\/li>\n<\/ul>\n\n\n\n<p>Thus, the empirical formula for hydrogen peroxide is <strong>HO<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">4. <strong>Glucose, C\u2086H\u2081\u2082O\u2086<\/strong><\/h3>\n\n\n\n<p>The molecular formula of glucose is <strong>C\u2086H\u2081\u2082O\u2086<\/strong>. To find the empirical formula, we divide each subscript by the GCD of 6, 12, and 6.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Carbon (C) = 6<\/li>\n\n\n\n<li>Hydrogen (H) = 12<\/li>\n\n\n\n<li>Oxygen (O) = 6<\/li>\n<\/ul>\n\n\n\n<p>The greatest common divisor of 6, 12, and 6 is 6. Dividing each by 6:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>C: 6 \u00f7 6 = 1<\/li>\n\n\n\n<li>H: 12 \u00f7 6 = 2<\/li>\n\n\n\n<li>O: 6 \u00f7 6 = 1<\/li>\n<\/ul>\n\n\n\n<p>So, the empirical formula for glucose is <strong>CH\u2082O<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">5. <strong>Ascorbic Acid (Vitamin C), C\u2086H\u2088O\u2086<\/strong><\/h3>\n\n\n\n<p>The molecular formula of ascorbic acid is <strong>C\u2086H\u2088O\u2086<\/strong>. We divide each subscript by the GCD of 6, 8, and 6.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Carbon (C) = 6<\/li>\n\n\n\n<li>Hydrogen (H) = 8<\/li>\n\n\n\n<li>Oxygen (O) = 6<\/li>\n<\/ul>\n\n\n\n<p>The greatest common divisor of 6, 8, and 6 is 2. Dividing each by 2:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>C: 6 \u00f7 2 = 3<\/li>\n\n\n\n<li>H: 8 \u00f7 2 = 4<\/li>\n\n\n\n<li>O: 6 \u00f7 2 = 3<\/li>\n<\/ul>\n\n\n\n<p>Thus, the empirical formula for ascorbic acid is <strong>C\u2083H\u2084O\u2083<\/strong>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Summary of Empirical Formulas:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Caffeine<\/strong>: <strong>C\u2084H\u2085N\u2082O<\/strong><\/li>\n\n\n\n<li><strong>Fructose<\/strong>: <strong>C\u2081\u2082H\u2082\u2082O\u2081\u2081<\/strong> (same as molecular formula)<\/li>\n\n\n\n<li><strong>Hydrogen Peroxide<\/strong>: <strong>HO<\/strong><\/li>\n\n\n\n<li><strong>Glucose<\/strong>: <strong>CH\u2082O<\/strong><\/li>\n\n\n\n<li><strong>Ascorbic Acid<\/strong>: <strong>C\u2083H\u2084O\u2083<\/strong><\/li>\n<\/ul>\n\n\n\n<p>The empirical formula helps us understand the simplest ratio of elements in a compound, but it does not provide the actual number of atoms in the molecule as the molecular formula does.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Determine the empirical formulas for the following compounds: caffeine, C8H10N4O2fructose, C12H22O11hydrogen peroxide, H2O2glucose, C6H12O6ascorbic acid (vitamin C), C6H8O6 The correct answer and explanation is : To determine the empirical formula of a compound, we need to find the simplest whole-number ratio of the elements present in the compound. The empirical formula represents the smallest ratio [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-204198","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/204198","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=204198"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/204198\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=204198"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=204198"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=204198"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}