Predict whether Cu(NO3)2 should be soluble or insoluble in water and explain why. Select one:<\/p>\n\n\n\n
a. Cu(NO3)2 is soluble because Cu-containing compounds are always soluble.
b. Cu(NO3)2 is insoluble because Cu-containing compounds are always insoluble.
c. Cu(NO3)2 is soluble because NO3-containing compounds are always soluble.
d. Cu(NO3)2 is insoluble because NO3-containing compounds are always insoluble.<\/p>\n\n\n\n
The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n The correct answer is:<\/p>\n\n\n\n c. Cu(NO3)2 is soluble because NO3-containing compounds are always soluble.<\/strong><\/p>\n\n\n\n Copper(II) nitrate, Cu(NO\u2083)\u2082<\/strong>, is soluble in water<\/strong> because it contains the nitrate (NO\u2083\u207b<\/strong>) ion. In general, solubility rules help predict whether an ionic compound will dissolve in water. One of the key solubility rules states that all nitrates (NO\u2083\u207b) are soluble in water<\/strong>, regardless of which metal cation they are paired with.<\/p>\n\n\n\n The nitrate ion is a highly soluble anion<\/strong> due to its ability to form strong ion-dipole interactions with water molecules. The presence of multiple oxygen atoms allows it to easily stabilize in an aqueous solution, leading to high solubility for all nitrate salts<\/strong>.<\/p>\n\n\n\n Copper compounds can sometimes be insoluble depending on the anion they are paired with (e.g., Cu(OH)\u2082<\/strong> and CuS<\/strong> are insoluble). However, when copper(II) is bonded to nitrate, the strong solubility rule of nitrate overrides any potential insolubility of copper(II)<\/strong>, making Cu(NO\u2083)\u2082 soluble<\/strong> in water.<\/p>\n\n\n\n Since Cu(NO\u2083)\u2082 follows the nitrate solubility rule<\/strong>, it dissolves completely in water, forming Cu\u00b2\u207a and NO\u2083\u207b ions<\/strong> in solution. Therefore, option (c) is correct<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":" Predict whether Cu(NO3)2 should be soluble or insoluble in water and explain why. Select one: a. Cu(NO3)2 is soluble because Cu-containing compounds are always soluble.b. Cu(NO3)2 is insoluble because Cu-containing compounds are always insoluble.c. Cu(NO3)2 is soluble because NO3-containing compounds are always soluble.d. Cu(NO3)2 is insoluble because NO3-containing compounds are always insoluble. The correct answer […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-204263","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/204263","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=204263"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/204263\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=204263"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=204263"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=204263"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}Explanation:<\/h3>\n\n\n\n
1. Nitrate Ion (NO\u2083\u207b) and Its Solubility Rule<\/strong><\/h4>\n\n\n\n
2. Copper(II) Ion (Cu\u00b2\u207a) and Solubility<\/strong><\/h4>\n\n\n\n
3. General Solubility Trend of Nitrate Salts<\/strong><\/h4>\n\n\n\n
\n
Conclusion:<\/strong><\/h3>\n\n\n\n