{"id":204301,"date":"2025-03-21T17:09:01","date_gmt":"2025-03-21T17:09:01","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=204301"},"modified":"2025-03-21T17:09:04","modified_gmt":"2025-03-21T17:09:04","slug":"the-formula-weight-of-iron-iii-carbonate","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/21\/the-formula-weight-of-iron-iii-carbonate\/","title":{"rendered":"The formula weight of Iron (III) carbonate"},"content":{"rendered":"\n

The formula weight of Iron (III) carbonate, Fe2(CO3)3 is <\/p>\n\n\n\n

a. 243.73 <\/p>\n\n\n\n

b. 291.73 <\/p>\n\n\n\n

c 115.85 <\/p>\n\n\n\n

d, 195 70<\/p>\n\n\n\n

e. 515.10<\/p>\n\n\n\n

The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n

The correct formula weight of Iron (III) carbonate, Fe\u2082(CO\u2083)\u2083<\/strong>, is 291.73 g\/mol<\/strong>. So, the correct answer is:<\/p>\n\n\n\n

b. 291.73<\/strong><\/p>\n\n\n\n

Explanation<\/h3>\n\n\n\n

The formula weight (also called molecular weight or molar mass) is the sum of the atomic masses of all the atoms in a chemical formula. Let\u2019s calculate the formula weight of Fe\u2082(CO\u2083)\u2083<\/strong> step by step.<\/p>\n\n\n\n

Step 1: Identify the Atomic Masses<\/strong><\/h4>\n\n\n\n

From the periodic table, the atomic masses are:<\/p>\n\n\n\n

    \n
  • Iron (Fe):<\/strong> 55.85 g\/mol<\/li>\n\n\n\n
  • Carbon (C):<\/strong> 12.01 g\/mol<\/li>\n\n\n\n
  • Oxygen (O):<\/strong> 16.00 g\/mol<\/li>\n<\/ul>\n\n\n\n

    Step 2: Multiply by the Number of Atoms<\/strong><\/h4>\n\n\n\n

    The molecular formula Fe\u2082(CO\u2083)\u2083<\/strong> contains:<\/p>\n\n\n\n

      \n
    • 2 Iron (Fe) atoms<\/strong> \u2192 2 \u00d7 55.85<\/strong> = 111.70 g\/mol<\/strong><\/li>\n\n\n\n
    • 3 Carbon (C) atoms<\/strong> \u2192 3 \u00d7 12.01<\/strong> = 36.03 g\/mol<\/strong><\/li>\n\n\n\n
    • 9 Oxygen (O) atoms<\/strong> \u2192 9 \u00d7 16.00<\/strong> = 144.00 g\/mol<\/strong><\/li>\n<\/ul>\n\n\n\n

      Step 3: Sum the Values<\/strong><\/h4>\n\n\n\n

      Now, add up all the contributions:<\/p>\n\n\n\n

      [
      111.70 + 36.03 + 144.00 = 291.73 \\text{ g\/mol}
      ]<\/p>\n\n\n\n

      Thus, the formula weight of Fe\u2082(CO\u2083)\u2083<\/strong> is 291.73 g\/mol<\/strong>.<\/p>\n\n\n\n

      Why is this Important?<\/strong><\/h3>\n\n\n\n
        \n
      • The formula weight is crucial in stoichiometry<\/strong>, where it helps in converting between grams and moles.<\/li>\n\n\n\n
      • It is used in chemical reactions<\/strong> to determine reactant-product relationships.<\/li>\n\n\n\n
      • It is necessary in solution preparation<\/strong>, especially in industries and laboratories.<\/li>\n<\/ul>\n\n\n\n

        Common Mistakes to Avoid<\/strong><\/h3>\n\n\n\n
          \n
        • Forgetting to multiply the atomic masses by the number of atoms.<\/li>\n\n\n\n
        • Miscounting the number of oxygen atoms<\/strong> (since each carbonate group (CO\u2083)<\/strong> has 3 oxygens, and there are 3 carbonate groups).<\/li>\n<\/ul>\n\n\n\n

          Thus, the correct answer remains 291.73 g\/mol (option b)<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"

          The formula weight of Iron (III) carbonate, Fe2(CO3)3 is a. 243.73 b. 291.73 c 115.85 d, 195 70 e. 515.10 The correct answer and explanation is : The correct formula weight of Iron (III) carbonate, Fe\u2082(CO\u2083)\u2083, is 291.73 g\/mol. So, the correct answer is: b. 291.73 Explanation The formula weight (also called molecular weight or […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-204301","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/204301","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=204301"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/204301\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=204301"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=204301"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=204301"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}