{"id":204781,"date":"2025-03-22T15:01:04","date_gmt":"2025-03-22T15:01:04","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=204781"},"modified":"2025-03-22T15:01:06","modified_gmt":"2025-03-22T15:01:06","slug":"balance-the-following-equations-by-inserting-the-appropriate-coefficients","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/22\/balance-the-following-equations-by-inserting-the-appropriate-coefficients\/","title":{"rendered":"Balance the following equations by inserting the appropriate coefficients"},"content":{"rendered":"\n<p>Balance the following equations by inserting the appropriate coefficients.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>P<sub>4<\/sub>\u00a0+ O<sub>2<\/sub>\u00a0&#8212;&#8211;> P<sub>2<\/sub>O<sub>5<\/sub><\/li>\n\n\n\n<li>C<sub>2<\/sub>H<sub>6<\/sub>\u00a0+ O<sub>2<\/sub>\u00a0&#8212;&#8211;> CO<sub>2<\/sub>\u00a0+ H<sub>2<\/sub>O<\/li>\n<\/ul>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Balanced Equations:<\/h3>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Phosphorus and Oxygen Reaction<\/strong><br><strong>Unbalanced:<\/strong><br>[<br>P_4 + O_2 \\rightarrow P_2O_5<br>]<br><strong>Balanced:<\/strong><br>[<br>P_4 + 5O_2 \\rightarrow 2P_2O_5<br>]<\/li>\n\n\n\n<li><strong>Ethane Combustion<\/strong><br><strong>Unbalanced:<\/strong><br>[<br>C_2H_6 + O_2 \\rightarrow CO_2 + H_2O<br>]<br><strong>Balanced:<\/strong><br>[<br>2C_2H_6 + 7O_2 \\rightarrow 4CO_2 + 6H_2O<br>]<\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<p><strong>1. Balancing Phosphorus and Oxygen Reaction<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The given equation contains <strong>P\u2084<\/strong> (tetraphosphorus) and <strong>O\u2082<\/strong> (oxygen gas), producing <strong>P\u2082O\u2085<\/strong> (diphosphorus pentoxide).<\/li>\n\n\n\n<li>Since each <strong>P\u2082O\u2085<\/strong> molecule contains <strong>2 P atoms<\/strong>, we need <strong>2 molecules<\/strong> to account for all 4 phosphorus atoms in <strong>P\u2084<\/strong>.<\/li>\n\n\n\n<li>Oxygen balance: Each <strong>P\u2082O\u2085<\/strong> contains <strong>5 oxygen atoms<\/strong>, and <strong>2 molecules<\/strong> contribute <strong>10 oxygen atoms<\/strong> in total.<\/li>\n\n\n\n<li>Since <strong>O\u2082<\/strong> molecules each contain <strong>2 oxygen atoms<\/strong>, we need <strong>5 O\u2082 molecules<\/strong> to provide 10 oxygen atoms.<\/li>\n<\/ul>\n\n\n\n<p>Thus, the balanced equation is:<br>[<br>P_4 + 5O_2 \\rightarrow 2P_2O_5<br>]<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p><strong>2. Balancing the Combustion of Ethane<\/strong><\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Ethane (<strong>C\u2082H\u2086<\/strong>) reacts with oxygen (<strong>O\u2082<\/strong>) to form carbon dioxide (<strong>CO\u2082<\/strong>) and water (<strong>H\u2082O<\/strong>).<\/li>\n\n\n\n<li>Carbon: <strong>C\u2082H\u2086<\/strong> has <strong>2 carbon atoms<\/strong>, so we need <strong>2 CO\u2082<\/strong> molecules.<\/li>\n\n\n\n<li>Hydrogen: <strong>C\u2082H\u2086<\/strong> has <strong>6 hydrogen atoms<\/strong>, so we need <strong>3 H\u2082O<\/strong> molecules to balance the hydrogen.<\/li>\n\n\n\n<li>Oxygen: The right side contains <strong>4 oxygens<\/strong> from <strong>CO\u2082<\/strong> and <strong>3\u00d71 = 3 oxygens<\/strong> from <strong>H\u2082O<\/strong>, totaling <strong>7 oxygens<\/strong>.<\/li>\n\n\n\n<li>Since <strong>O\u2082<\/strong> molecules contribute <strong>2 oxygen atoms each<\/strong>, we need <strong>7 O\u2082 molecules<\/strong> to balance.<\/li>\n<\/ul>\n\n\n\n<p>Thus, the balanced equation is:<br>[<br>2C_2H_6 + 7O_2 \\rightarrow 4CO_2 + 6H_2O<br>]<\/p>\n\n\n\n<p>Balancing chemical equations ensures that the law of conservation of mass is satisfied, meaning atoms are neither created nor destroyed.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Balance the following equations by inserting the appropriate coefficients. The correct answer and explanation is : Balanced Equations: Explanation: 1. Balancing Phosphorus and Oxygen Reaction Thus, the balanced equation is:[P_4 + 5O_2 \\rightarrow 2P_2O_5] 2. Balancing the Combustion of Ethane Thus, the balanced equation is:[2C_2H_6 + 7O_2 \\rightarrow 4CO_2 + 6H_2O] Balancing chemical equations ensures [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-204781","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/204781","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=204781"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/204781\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=204781"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=204781"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=204781"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}