{"id":204936,"date":"2025-03-22T18:39:27","date_gmt":"2025-03-22T18:39:27","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=204936"},"modified":"2025-03-22T18:39:30","modified_gmt":"2025-03-22T18:39:30","slug":"show-the-lewis-structure-of-cpo2","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/22\/show-the-lewis-structure-of-cpo2\/","title":{"rendered":"Show the Lewis structure of CPo2"},"content":{"rendered":"\n

Show the Lewis structure of CPo2<\/sub>. Be sure to show lone pairs.<\/p>\n\n\n\n

The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n

The correct Lewis structure for CPo\u2082<\/strong> (carbon dipolonide) follows these steps:<\/p>\n\n\n\n

    \n
  1. Count Valence Electrons<\/strong>:<\/li>\n<\/ol>\n\n\n\n
      \n
    • Carbon (C) has 4<\/strong> valence electrons.<\/li>\n\n\n\n
    • Polonium (Po) belongs to Group 16 (like oxygen) and has 6<\/strong> valence electrons. Since there are two Po atoms, their total contribution is 6 \u00d7 2 = 12<\/strong> electrons.<\/li>\n\n\n\n
    • The total number of valence electrons is 4 + 12 = 16<\/strong>.<\/li>\n<\/ul>\n\n\n\n
        \n
      1. Determine the Central Atom<\/strong>:<\/li>\n<\/ol>\n\n\n\n
          \n
        • Carbon is the least electronegative, so it is the central atom<\/strong>. The two polonium atoms will be terminal atoms.<\/li>\n<\/ul>\n\n\n\n
            \n
          1. Connect Atoms with Single Bonds<\/strong>:<\/li>\n<\/ol>\n\n\n\n
              \n
            • Draw single bonds between C<\/strong> and each Po<\/strong>, using 2 electrons per bond<\/strong>. This initially uses up 4 electrons<\/strong>, leaving 12 electrons<\/strong>.<\/li>\n<\/ul>\n\n\n\n
                \n
              1. Distribute Lone Pairs<\/strong>:<\/li>\n<\/ol>\n\n\n\n
                  \n
                • Each polonium atom gets three lone pairs<\/strong> (6 electrons each) to satisfy the octet rule.<\/li>\n<\/ul>\n\n\n\n
                    \n
                  1. Check Octets<\/strong>:<\/li>\n<\/ol>\n\n\n\n
                      \n
                    • Carbon only has 4 electrons<\/strong> (from two single bonds), which is not a full octet.<\/li>\n\n\n\n
                    • To satisfy the octet rule for carbon, one lone pair from each Po must be shared to form double bonds<\/strong> with carbon.<\/li>\n<\/ul>\n\n\n\n
                        \n
                      1. Final Structure<\/strong>:<\/li>\n<\/ol>\n\n\n\n
                          \n
                        • Carbon forms two double bonds<\/strong> with polonium (C=Po=C), and each polonium still retains two lone pairs<\/strong>.<\/li>\n<\/ul>\n\n\n\n

                          Explanation<\/h3>\n\n\n\n
                            \n
                          • Octet Rule<\/strong>: Carbon now has 8 electrons<\/strong> (two double bonds). Each polonium also has 8 electrons<\/strong> (two bonds + two lone pairs).<\/li>\n\n\n\n
                          • Formal Charge Calculation<\/strong>:<\/li>\n\n\n\n
                          • Carbon: (4 – (4\/2) – 0 = 0)<\/li>\n\n\n\n
                          • Polonium: (6 – (4\/2) – 4 = 0)<\/li>\n\n\n\n
                          • Since all atoms have formal charges of zero<\/strong>, this is the most stable structure.<\/li>\n<\/ul>\n\n\n\n

                            Now, here\u2019s the Lewis structure<\/strong> representation:<\/p>\n\n\n\n

                            I’ll generate the image now.<\/p>\n\n\n\n

                            Here is the Lewis structure of CPo\u2082 (carbon dipolonide)<\/strong> with lone pairs clearly shown. Let me know if you need any modifications or further explanation!<\/p>\n","protected":false},"excerpt":{"rendered":"

                            Show the Lewis structure of CPo2. Be sure to show lone pairs. The correct answer and explanation is: The correct Lewis structure for CPo\u2082 (carbon dipolonide) follows these steps: Explanation Now, here\u2019s the Lewis structure representation: I’ll generate the image now. Here is the Lewis structure of CPo\u2082 (carbon dipolonide) with lone pairs clearly shown. […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-204936","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/204936","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=204936"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/204936\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=204936"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=204936"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=204936"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}