{"id":205441,"date":"2025-03-24T16:33:11","date_gmt":"2025-03-24T16:33:11","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=205441"},"modified":"2025-03-24T16:33:14","modified_gmt":"2025-03-24T16:33:14","slug":"calculate-the-molar-mass-of-fe2o3-to-one-decimal-point","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/24\/calculate-the-molar-mass-of-fe2o3-to-one-decimal-point\/","title":{"rendered":"calculate the molar mass of Fe2O3 to one decimal point"},"content":{"rendered":"\n<p>calculate the molar mass of Fe2O3 to one decimal point<\/p>\n\n\n\n<p><strong><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\">The correct answer and explanation is:<\/mark><\/strong><\/p>\n\n\n\n<p>The molar mass of iron(III) oxide (Fe2O3\\text{Fe}_2\\text{O}_3) is calculated as follows:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Iron (Fe)<\/strong>: Atomic mass = <strong>55.8 g\/mol<\/strong><br>Since there are <strong>2 Fe atoms<\/strong>, the total mass contribution from Fe is: 2\u00d755.8=111.6\u00a0g\/mol2 \\times 55.8 = 111.6 \\text{ g\/mol}<\/li>\n\n\n\n<li><strong>Oxygen (O)<\/strong>: Atomic mass = <strong>16.0 g\/mol<\/strong><br>Since there are <strong>3 O atoms<\/strong>, the total mass contribution from O is: 3\u00d716.0=48.0\u00a0g\/mol3 \\times 16.0 = 48.0 \\text{ g\/mol}<\/li>\n\n\n\n<li><strong>Total Molar Mass<\/strong>: 111.6+48.0=159.6\u00a0g\/mol111.6 + 48.0 = 159.6 \\text{ g\/mol}<\/li>\n<\/ul>\n\n\n\n<p><strong>Final Answer: 159.6 g\/mol<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation (300 words)<\/strong><\/h3>\n\n\n\n<p>Iron(III) oxide (Fe2O3\\text{Fe}_2\\text{O}_3) is a chemical compound consisting of iron and oxygen. It is commonly found in nature as hematite, an important iron ore. The molar mass of a compound is the sum of the atomic masses of all the atoms present in its molecular formula, expressed in grams per mole (g\/mol).<\/p>\n\n\n\n<p>To determine the molar mass of Fe2_2O3_3, we first look at the periodic table to find the atomic masses of iron (Fe) and oxygen (O). The atomic mass of iron is <strong>55.8 g\/mol<\/strong>, and the atomic mass of oxygen is <strong>16.0 g\/mol<\/strong>.<\/p>\n\n\n\n<p>Since the formula Fe2_2O3_3 contains <strong>two Fe atoms<\/strong> and <strong>three O atoms<\/strong>, we calculate their contributions separately:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Iron Contribution:<\/strong> 2\u00d755.8=111.62 \\times 55.8 = 111.6 g\/mol<\/li>\n\n\n\n<li><strong>Oxygen Contribution:<\/strong> 3\u00d716.0=48.03 \\times 16.0 = 48.0 g\/mol<\/li>\n<\/ul>\n\n\n\n<p>Adding these together, we get the total molar mass: 159.6&nbsp;g\/mol159.6 \\text{ g\/mol}<\/p>\n\n\n\n<p>Understanding molar mass is essential in chemistry for stoichiometric calculations, which help in determining the amounts of reactants and products in a chemical reaction. Fe2_2O3_3 is widely used in industries, including steel manufacturing and pigments. Its correct molar mass calculation is crucial for precise formulation and reaction balancing.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/03\/image-1305.png\" alt=\"\" class=\"wp-image-205442\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>calculate the molar mass of Fe2O3 to one decimal point The correct answer and explanation is: The molar mass of iron(III) oxide (Fe2O3\\text{Fe}_2\\text{O}_3) is calculated as follows: Final Answer: 159.6 g\/mol Explanation (300 words) Iron(III) oxide (Fe2O3\\text{Fe}_2\\text{O}_3) is a chemical compound consisting of iron and oxygen. It is commonly found in nature as hematite, an [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-205441","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/205441","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=205441"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/205441\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=205441"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=205441"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=205441"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}