{"id":205536,"date":"2025-03-25T05:14:22","date_gmt":"2025-03-25T05:14:22","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=205536"},"modified":"2025-03-25T05:14:26","modified_gmt":"2025-03-25T05:14:26","slug":"a-solution-contains-10-0-by-mass-or-mass-mass-nabr-sodium-bromide-molar-mass-102-89-g-mol","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/25\/a-solution-contains-10-0-by-mass-or-mass-mass-nabr-sodium-bromide-molar-mass-102-89-g-mol\/","title":{"rendered":"A Solution Contains 10.0% (By Mass) Or (Mass\/Mass) NaBr (Sodium Bromide) (Molar Mass= 102 89 G\/Mol)"},"content":{"rendered":"\n<p>A Solution Contains 10.0% (By Mass) Or (Mass\/Mass) NaBr (Sodium Bromide) (Molar Mass= 102 89 G\/Mol). The Density Of The Solution Is 1 046 G\/Cm What Is The Molarity Of The NaBr Solution?<\/p>\n\n\n\n<p> A 0.610 <\/p>\n\n\n\n<p>B. 0.970 <\/p>\n\n\n\n<p>C 0.280 <\/p>\n\n\n\n<p>D. 1.02 M<\/p>\n\n\n\n<p>E. 0.583<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>To find the <strong>molarity (M)<\/strong> of the NaBr solution, follow these steps:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 1: Understand Given Data<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Mass percent of NaBr<\/strong> = 10.0% (which means 10.0 g of NaBr in 100 g of solution)<\/li>\n\n\n\n<li><strong>Molar mass of NaBr<\/strong> = 102.89 g\/mol<\/li>\n\n\n\n<li><strong>Density of the solution<\/strong> = 1.046 g\/cm\u00b3 (which is equivalent to 1.046 g\/mL)<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 2: Determine the Volume of the Solution<\/strong><\/h3>\n\n\n\n<p>We assume <strong>100 g<\/strong> of solution. Using density:<\/p>\n\n\n\n<p>[<br>\\text{Volume} = \\frac{\\text{Mass of solution}}{\\text{Density}}<br>]<\/p>\n\n\n\n<p>[<br>\\text{Volume} = \\frac{100 \\text{ g}}{1.046 \\text{ g\/mL}} = 95.60 \\text{ mL} = 0.0956 \\text{ L}<br>]<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 3: Find the Moles of NaBr<\/strong><\/h3>\n\n\n\n<p>Since <strong>10.0 g of NaBr<\/strong> is present:<\/p>\n\n\n\n<p>[<br>\\text{Moles of NaBr} = \\frac{\\text{Mass of NaBr}}{\\text{Molar mass of NaBr}}<br>]<\/p>\n\n\n\n<p>[<br>\\text{Moles of NaBr} = \\frac{10.0 \\text{ g}}{102.89 \\text{ g\/mol}} = 0.0972 \\text{ moles}<br>]<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 4: Calculate Molarity<\/strong><\/h3>\n\n\n\n<p>Molarity (M) is defined as:<\/p>\n\n\n\n<p>[<br>M = \\frac{\\text{Moles of solute}}{\\text{Liters of solution}}<br>]<\/p>\n\n\n\n<p>[<br>M = \\frac{0.0972}{0.0956} = 1.02 \\text{ M}<br>]<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Final Answer:<\/strong><\/h3>\n\n\n\n<p>The correct answer is <strong>D. 1.02 M<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation (300 words)<\/strong><\/h3>\n\n\n\n<p>Molarity (M) represents the concentration of a solution, measured as moles of solute per liter of solution. In this problem, we were given a <strong>10.0% NaBr solution by mass<\/strong>, meaning that for every <strong>100 g of solution, 10.0 g is NaBr<\/strong>. The <strong>density of the solution is 1.046 g\/mL<\/strong>, allowing us to determine the volume of 100 g of solution.<\/p>\n\n\n\n<p>To find the <strong>molarity<\/strong>, we first calculated the volume of 100 g of solution using the density formula, giving <strong>95.60 mL (or 0.0956 L)<\/strong>. Then, we calculated the <strong>moles of NaBr<\/strong> using its molar mass (<strong>102.89 g\/mol<\/strong>), resulting in <strong>0.0972 moles<\/strong>.<\/p>\n\n\n\n<p>Finally, dividing the <strong>moles of NaBr (0.0972 moles)<\/strong> by the <strong>volume in liters (0.0956 L)<\/strong> gave us the molarity:<\/p>\n\n\n\n<p>[<br>M = \\frac{0.0972}{0.0956} = 1.02 M<br>]<\/p>\n\n\n\n<p>This means that the solution has <strong>1.02 moles of NaBr per liter<\/strong>, making the correct answer <strong>option D (1.02 M).<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/03\/image-1337.png\" alt=\"\" class=\"wp-image-205537\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>A Solution Contains 10.0% (By Mass) Or (Mass\/Mass) NaBr (Sodium Bromide) (Molar Mass= 102 89 G\/Mol). The Density Of The Solution Is 1 046 G\/Cm What Is The Molarity Of The NaBr Solution? A 0.610 B. 0.970 C 0.280 D. 1.02 M E. 0.583 The correct answer and explanation is : To find the molarity [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-205536","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/205536","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=205536"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/205536\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=205536"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=205536"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=205536"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}