{"id":205933,"date":"2025-03-26T05:42:24","date_gmt":"2025-03-26T05:42:24","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=205933"},"modified":"2025-03-26T05:42:26","modified_gmt":"2025-03-26T05:42:26","slug":"what-is-the-hybridization-of-xeo2-and-xeo3","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/26\/what-is-the-hybridization-of-xeo2-and-xeo3\/","title":{"rendered":"What is the hybridization of XeO2 and XeO3"},"content":{"rendered":"\n

What is the hybridization of XeO2 and XeO3?<\/p>\n\n\n\n

The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n

Hybridization of XeO\u2082 and XeO\u2083<\/strong><\/h3>\n\n\n\n
    \n
  • XeO\u2082 (Xenon Dioxide):<\/strong> The hybridization of Xe in XeO\u2082 is sp\u00b3<\/strong>.<\/li>\n\n\n\n
  • XeO\u2083 (Xenon Trioxide):<\/strong> The hybridization of Xe in XeO\u2083 is sp\u00b3<\/strong>.<\/li>\n<\/ul>\n\n\n\n

    Explanation<\/strong><\/h3>\n\n\n\n

    Xenon oxides are interesting compounds because xenon, a noble gas, forms bonds with oxygen despite having a full valence shell. The hybridization in these compounds depends on the number of bonding and lone pairs around the xenon atom.<\/p>\n\n\n\n

    1. Hybridization of Xe in XeO\u2082<\/strong><\/h4>\n\n\n\n
      \n
    • Xenon (Xe) has 8 valence electrons.<\/li>\n\n\n\n
    • Oxygen atoms form double bonds with xenon. Each double bond uses 2 electrons per bond<\/strong> (total of 4 electrons).<\/li>\n\n\n\n
    • Remaining 4 electrons<\/strong> (or 2 lone pairs<\/strong>) stay on Xe.<\/li>\n\n\n\n
    • The steric number (bonding regions + lone pairs) = 4<\/strong> (2 sigma bonds + 2 lone pairs).<\/li>\n\n\n\n
    • A steric number of 4<\/strong> corresponds to sp\u00b3 hybridization<\/strong>.<\/li>\n<\/ul>\n\n\n\n

      2. Hybridization of Xe in XeO\u2083<\/strong><\/h4>\n\n\n\n
        \n
      • Xenon has 8 valence electrons<\/strong>.<\/li>\n\n\n\n
      • Three oxygens form double bonds<\/strong> with xenon, utilizing 6 electrons<\/strong>.<\/li>\n\n\n\n
      • The remaining 2 electrons<\/strong> form one lone pair<\/strong> on Xe.<\/li>\n\n\n\n
      • The steric number = 4<\/strong> (3 sigma bonds + 1 lone pair).<\/li>\n\n\n\n
      • A steric number of 4<\/strong> means sp\u00b3 hybridization<\/strong>.<\/li>\n<\/ul>\n\n\n\n

        Molecular Geometry<\/strong><\/h3>\n\n\n\n
          \n
        • XeO\u2082<\/strong> has a bent (V-shaped) structure<\/strong> due to lone pair repulsions.<\/li>\n\n\n\n
        • XeO\u2083<\/strong> has a trigonal pyramidal shape<\/strong> because of its lone pair repulsion.<\/li>\n<\/ul>\n\n\n\n
          \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

          What is the hybridization of XeO2 and XeO3? The correct answer and explanation is : Hybridization of XeO\u2082 and XeO\u2083 Explanation Xenon oxides are interesting compounds because xenon, a noble gas, forms bonds with oxygen despite having a full valence shell. The hybridization in these compounds depends on the number of bonding and lone pairs […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-205933","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/205933","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=205933"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/205933\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=205933"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=205933"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=205933"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}