{"id":205990,"date":"2025-03-26T06:24:04","date_gmt":"2025-03-26T06:24:04","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=205990"},"modified":"2025-03-26T06:24:06","modified_gmt":"2025-03-26T06:24:06","slug":"the-conjugate-base-of-hclo3-is","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/26\/the-conjugate-base-of-hclo3-is\/","title":{"rendered":"The conjugate base of HClO3 is"},"content":{"rendered":"\n

The conjugate base of HClO3 is<\/p>\n\n\n\n

A) HClO2.<\/p>\n\n\n\n

B) ClO3-.<\/p>\n\n\n\n

C) Cl(OH)2.<\/p>\n\n\n\n

D) ClO3.<\/p>\n\n\n\n

E) HClO.<\/p>\n\n\n\n

The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n

The correct answer is:
B) ClO\u2083\u207b (Chlorate ion).<\/strong><\/p>\n\n\n\n

Explanation:<\/h3>\n\n\n\n

To determine the conjugate base of HClO\u2083<\/strong> (chloric acid), we need to recall the Br\u00f8nsted-Lowry acid-base theory<\/strong>, which states that an acid donates a proton (H\u207a<\/strong>) and its conjugate base is what remains after the proton is removed.<\/p>\n\n\n\n

Step 1: Identify the Acid and Remove a Proton<\/strong><\/h4>\n\n\n\n

The given acid is HClO\u2083<\/strong>. When it donates a proton (H\u207a<\/strong>), we are left with:<\/p>\n\n\n\n

[
HClO\u2083 \\rightarrow H\u207a + ClO\u2083\u207b
]<\/p>\n\n\n\n

Thus, the conjugate base of HClO\u2083<\/strong> is ClO\u2083\u207b (chlorate ion).<\/strong><\/p>\n\n\n\n

Step 2: Eliminate Incorrect Choices<\/strong><\/h4>\n\n\n\n
    \n
  • (A) HClO\u2082<\/strong> \u2013 This is chlorous acid, not the conjugate base of chloric acid.<\/li>\n\n\n\n
  • (C) Cl(OH)\u2082<\/strong> \u2013 This is not a commonly known species in acid-base chemistry.<\/li>\n\n\n\n
  • (D) ClO\u2083<\/strong> \u2013 This represents the chlorate radical but lacks charge, whereas the correct conjugate base is ClO\u2083\u207b.<\/li>\n\n\n\n
  • (E) HClO<\/strong> \u2013 This is hypochlorous acid, not the conjugate base of chloric acid.<\/li>\n<\/ul>\n\n\n\n

    Thus, the correct answer is B) ClO\u2083\u207b<\/strong>.<\/p>\n\n\n\n

    Concept Recap:<\/strong><\/h3>\n\n\n\n
      \n
    • A conjugate base<\/strong> is formed when an acid loses a proton (H\u207a<\/strong>).<\/li>\n\n\n\n
    • The acid-base pair HClO\u2083 \/ ClO\u2083\u207b<\/strong> follows this principle.<\/li>\n\n\n\n
    • ClO\u2083\u207b<\/strong> is the remaining ion after H\u207a<\/strong> is removed from chloric acid.<\/li>\n<\/ul>\n\n\n\n
      \"\"<\/figure>\n","protected":false},"excerpt":{"rendered":"

      The conjugate base of HClO3 is A) HClO2. B) ClO3-. C) Cl(OH)2. D) ClO3. E) HClO. The correct answer and explanation is : The correct answer is:B) ClO\u2083\u207b (Chlorate ion). Explanation: To determine the conjugate base of HClO\u2083 (chloric acid), we need to recall the Br\u00f8nsted-Lowry acid-base theory, which states that an acid donates a […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-205990","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/205990","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=205990"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/205990\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=205990"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=205990"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=205990"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}