{"id":205996,"date":"2025-03-26T06:43:24","date_gmt":"2025-03-26T06:43:24","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=205996"},"modified":"2025-03-26T06:43:26","modified_gmt":"2025-03-26T06:43:26","slug":"what-is-the-ph-ofa-6-50-x-10-3-m-koh-solution","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/03\/26\/what-is-the-ph-ofa-6-50-x-10-3-m-koh-solution\/","title":{"rendered":"What is the pH ofa 6.50 x 10-3 M KOH solution"},"content":{"rendered":"\n<p>What is the pH ofa 6.50 x 10-3 M KOH solution?(Hint: this is a basic solution\u2013 concentration is of OH-)<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>To determine the pH of a <strong>6.50 \u00d7 10\u207b\u00b3 M KOH<\/strong> solution, follow these steps:<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 1: Identify Key Information<\/strong><\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>KOH<\/strong> is a strong base, meaning it dissociates completely in water:<br>[<br>\\text{KOH} \\rightarrow \\text{K}^+ + \\text{OH}^-<br>]<\/li>\n\n\n\n<li>The concentration of hydroxide ions (\\text{OH}^-) is equal to the given concentration of KOH:<br>[<br>[\\text{OH}^-] = 6.50 \\times 10^{-3} M<br>]<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 2: Calculate pOH<\/strong><\/h3>\n\n\n\n<p>The pOH is calculated using the formula:<br>[<br>\\text{pOH} = -\\log [\\text{OH}^-]<br>]<br>[<br>\\text{pOH} = -\\log (6.50 \\times 10^{-3})<br>]<br>Using a calculator:<br>[<br>\\text{pOH} \\approx 2.19<br>]<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Step 3: Determine pH<\/strong><\/h3>\n\n\n\n<p>Since the relationship between <strong>pH<\/strong> and <strong>pOH<\/strong> is:<br>[<br>\\text{pH} + \\text{pOH} = 14<br>]<br>[<br>\\text{pH} = 14 &#8211; 2.19<br>]<br>[<br>\\text{pH} \\approx 11.81<br>]<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Final Answer:<\/strong><\/h3>\n\n\n\n<p>The pH of the <strong>6.50 \u00d7 10\u207b\u00b3 M KOH<\/strong> solution is <strong>11.81<\/strong>, confirming it is a basic solution.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Explanation (300 Words)<\/strong><\/h3>\n\n\n\n<p>The pH scale ranges from 0 to 14, where values <strong>below 7<\/strong> are acidic, <strong>above 7<\/strong> are basic, and <strong>exactly 7<\/strong> is neutral. Since potassium hydroxide (KOH) is a strong base, it dissociates completely in water to release hydroxide ions (<strong>OH\u207b<\/strong>), making the solution basic.<\/p>\n\n\n\n<p>To find the pH, we first determine the <strong>pOH<\/strong> using the formula <strong>pOH = -log[OH\u207b]<\/strong>. Plugging in the concentration <strong>6.50 \u00d7 10\u207b\u00b3 M<\/strong>, we obtain <strong>pOH \u2248 2.19<\/strong>. Since pH and pOH are related by the equation <strong>pH + pOH = 14<\/strong>, solving for pH gives <strong>pH \u2248 11.81<\/strong>.<\/p>\n\n\n\n<p>A pH of <strong>11.81<\/strong> confirms the solution is basic because it is significantly higher than 7. This makes sense because KOH is a strong base and contributes a relatively high concentration of hydroxide ions to the solution.<\/p>\n\n\n\n<p>In practical applications, knowing the pH of a solution is important in chemistry, medicine, and environmental science. For example, alkaline solutions like KOH are used in soap-making, cleaning agents, and industrial processes where strong bases are needed.<\/p>\n\n\n\n<p>This problem reinforces the importance of understanding logarithmic functions in pH calculations and highlights how strong bases completely dissociate in aqueous solutions.<\/p>\n\n\n\n<figure class=\"wp-block-image size-full\"><img decoding=\"async\" src=\"https:\/\/learnexams.com\/blog\/wp-content\/uploads\/2025\/03\/image-1480.png\" alt=\"\" class=\"wp-image-205997\"\/><\/figure>\n","protected":false},"excerpt":{"rendered":"<p>What is the pH ofa 6.50 x 10-3 M KOH solution?(Hint: this is a basic solution\u2013 concentration is of OH-) The correct answer and explanation is : To determine the pH of a 6.50 \u00d7 10\u207b\u00b3 M KOH solution, follow these steps: Step 1: Identify Key Information Step 2: Calculate pOH The pOH is calculated [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-205996","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/205996","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=205996"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/205996\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=205996"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=205996"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=205996"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}