{"id":206506,"date":"2025-04-01T06:11:03","date_gmt":"2025-04-01T06:11:03","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=206506"},"modified":"2025-04-01T06:11:05","modified_gmt":"2025-04-01T06:11:05","slug":"draw-the-structure-of-an-eight-carbon-alkene-that-would-yield-the-following-compound-and-no-others-after-treatment-with-ozone-followed-by-dimethyl-sulfide-9","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/04\/01\/draw-the-structure-of-an-eight-carbon-alkene-that-would-yield-the-following-compound-and-no-others-after-treatment-with-ozone-followed-by-dimethyl-sulfide-9\/","title":{"rendered":"Draw the structure of an eight-carbon alkene that would yield the following compound (and no others) after treatment with ozone followed by dimethyl sulfide"},"content":{"rendered":"\n

Draw the structure of an eight-carbon alkene that would yield the following compound (and no others) after treatment with ozone followed by dimethyl sulfide.<\/p>\n\n\n\n

The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

To solve this, we need to determine the structure of an eight-carbon alkene that, upon ozonolysis followed by reductive workup with dimethyl sulfide ((\\text{DMS})), produces only one specific product.<\/p>\n\n\n\n

Step 1: Understanding Ozonolysis<\/strong><\/h3>\n\n\n\n

Ozonolysis cleaves alkenes at the double bond, replacing each sp\u00b2 carbon with a carbonyl group (either aldehyde or ketone). The products depend on the structure of the initial alkene.<\/p>\n\n\n\n

Step 2: Identifying the Product<\/strong><\/h3>\n\n\n\n

The problem states that only one compound is formed. This suggests that the alkene is symmetrical or that both fragments of the alkene result in the same molecule.<\/p>\n\n\n\n

If an alkene is symmetrical and undergoes ozonolysis, it must have an identical substitution pattern on both sides. For an eight-carbon system, a likely candidate is 3,4-octadiene<\/strong>, where cleavage at the double bond results in two identical four-carbon fragments.<\/p>\n\n\n\n

Step 3: Drawing the Alkene<\/strong><\/h3>\n\n\n\n

The best alkene satisfying this condition is 3,4-octadiene<\/strong>:
[
\\text{CH}_3\\text{-CH}_2\\text{-CH=CH-CH=CH-CH}_2\\text{-CH}_3
]
After ozonolysis, this compound yields two identical molecules of butanedial (OHC-CH2-CH2-CHO)<\/strong>.<\/p>\n\n\n\n

Conclusion<\/strong><\/h3>\n\n\n\n

The correct alkene is 3,4-octadiene<\/strong>, ensuring that ozonolysis yields only one product.<\/p>\n","protected":false},"excerpt":{"rendered":"

Draw the structure of an eight-carbon alkene that would yield the following compound (and no others) after treatment with ozone followed by dimethyl sulfide. The correct answer and explanation is : To solve this, we need to determine the structure of an eight-carbon alkene that, upon ozonolysis followed by reductive workup with dimethyl sulfide ((\\text{DMS})), […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-206506","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/206506","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=206506"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/206506\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=206506"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=206506"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=206506"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}