Write a chemical equation for Sr(OH)2(aq) showing how it is an acid or a base according to the Arrhenius definition.<\/p>\n\n\n\n
The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n [ Strontium hydroxide, Sr(OH)\u2082<\/strong>, is a classic example of a base<\/strong> under the Arrhenius definition<\/strong>. According to Svante Arrhenius<\/strong>, a base<\/strong> is a substance that increases the concentration of hydroxide ions (OH\u207b)<\/strong> when dissolved in water. Conversely, an Arrhenius acid<\/strong> increases the concentration of hydrogen ions (H\u207a), often represented as hydronium ions (H\u2083O\u207a) in aqueous solution.<\/p>\n\n\n\n When Sr(OH)\u2082<\/strong> dissolves in water, it completely dissociates<\/strong> into its ions: Sr\u00b2\u207a<\/strong> (a strontium ion) and 2 OH\u207b<\/strong> (hydroxide ions). The balanced chemical equation for this dissociation is:<\/p>\n\n\n\n [ This reaction demonstrates that Sr(OH)\u2082 acts as an Arrhenius base<\/strong> because it directly releases hydroxide ions into the solution, increasing their concentration. These OH\u207b ions make the solution basic<\/strong>, which can be confirmed by using indicators like litmus paper (which turns blue in basic solutions) or pH measurements (which would show a pH above 7).<\/p>\n\n\n\n Strontium hydroxide is a strong base<\/strong>, meaning it dissociates completely in aqueous solution. This complete dissociation is typical of Group 2 metal hydroxides such as Ca(OH)\u2082<\/strong> and Ba(OH)\u2082<\/strong>, although solubility can vary. Sr(OH)\u2082<\/strong> is moderately soluble in water, but even this partial solubility is enough to produce a strongly basic solution due to the complete dissociation of the dissolved portion.<\/p>\n\n\n\n In summary, Sr(OH)\u2082 fits the Arrhenius definition of a base<\/strong> because it increases the hydroxide ion concentration in aqueous solution. This property allows it to neutralize acids in reactions and explains its behavior in various chemical processes involving bases.<\/p>\n","protected":false},"excerpt":{"rendered":" Write a chemical equation for Sr(OH)2(aq) showing how it is an acid or a base according to the Arrhenius definition. The correct answer and explanation is : Chemical Equation: [\\text{Sr(OH)}_2(aq) \\rightarrow \\text{Sr}^{2+}(aq) + 2\\text{OH}^-(aq)] Explanation (300 words): Strontium hydroxide, Sr(OH)\u2082, is a classic example of a base under the Arrhenius definition. According to Svante Arrhenius, […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-207554","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/207554","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=207554"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/207554\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=207554"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=207554"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=207554"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}Chemical Equation:<\/h3>\n\n\n\n
\\text{Sr(OH)}_2(aq) \\rightarrow \\text{Sr}^{2+}(aq) + 2\\text{OH}^-(aq)
]<\/p>\n\n\n\nExplanation (300 words):<\/h3>\n\n\n\n
\\text{Sr(OH)}_2(aq) \\rightarrow \\text{Sr}^{2+}(aq) + 2\\text{OH}^-(aq)
]<\/p>\n\n\n\n