{"id":207762,"date":"2025-04-25T07:26:42","date_gmt":"2025-04-25T07:26:42","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=207762"},"modified":"2025-04-25T07:26:45","modified_gmt":"2025-04-25T07:26:45","slug":"which-of-the-following-is-false-regarding-the-lewis-structure-for-pbr5","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/04\/25\/which-of-the-following-is-false-regarding-the-lewis-structure-for-pbr5\/","title":{"rendered":"Which of the following is FALSE regarding the Lewis structure for PBr5"},"content":{"rendered":"\n<p>Which of the following is FALSE regarding the Lewis structure for PBr5?<br>A The total number of valence electrons is 40.<br>B There are unpaired electrons on the central atom.<br>C There are 5 electron domains around the central atom.<br>D The formal charge on each atom is zero.<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>The **correct answer is:<br>**\ud83d\udc49 <strong>B. There are unpaired electrons on the central atom.<\/strong> <em>(This is FALSE)<\/em><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\ud83d\udd0d Explanation (300+ words):<\/h3>\n\n\n\n<p>To determine which statement is <strong>false<\/strong>, we must understand the <strong>Lewis structure<\/strong> of <strong>phosphorus pentabromide (PBr\u2085)<\/strong> and analyze each option step by step.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\ud83d\udd2c 1. <strong>Lewis Structure of PBr\u2085:<\/strong><\/h3>\n\n\n\n<p>Phosphorus (P) is the <strong>central atom<\/strong>, and it is bonded to <strong>five bromine (Br)<\/strong> atoms.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Phosphorus<\/strong> has <strong>5 valence electrons<\/strong> (group 15).<\/li>\n\n\n\n<li><strong>Each bromine<\/strong> atom has <strong>7 valence electrons<\/strong> (group 17).<\/li>\n<\/ul>\n\n\n\n<p>So, the <strong>total valence electrons<\/strong>:<br>= 5 (from P) + 5 \u00d7 7 (from 5 Br atoms)<br>= 5 + 35<br>= <strong>40 valence electrons<\/strong> \u2705<\/p>\n\n\n\n<p>Each Br atom forms a <strong>single bond<\/strong> with P, using <strong>2 electrons per bond<\/strong>, totaling <strong>10 electrons<\/strong> for bonding.<\/p>\n\n\n\n<p>The remaining <strong>30 electrons<\/strong> are distributed as <strong>lone pairs<\/strong> (3 lone pairs on each Br atom), and the <strong>phosphorus<\/strong> atom uses all its valence electrons in bonding.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 Option A: <strong>&#8220;The total number of valence electrons is 40.&#8221;<\/strong><\/h3>\n\n\n\n<p>\u2714\ufe0f <strong>True<\/strong> \u2013 We calculated this above.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u274c Option B: <strong>&#8220;There are unpaired electrons on the central atom.&#8221;<\/strong><\/h3>\n\n\n\n<p><strong>\u274c False<\/strong> \u2013 In the Lewis structure of PBr\u2085:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Phosphorus forms <strong>5 single bonds<\/strong> with each Br.<\/li>\n\n\n\n<li>That means it uses all <strong>5 valence electrons<\/strong> in bonding.<\/li>\n\n\n\n<li><strong>There are no unpaired electrons<\/strong> left on the central atom.<\/li>\n<\/ul>\n\n\n\n<p>\u2714\ufe0f So this statement is <strong>false<\/strong>, making it the <strong>correct choice<\/strong> for this question.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 Option C: <strong>&#8220;There are 5 electron domains around the central atom.&#8221;<\/strong><\/h3>\n\n\n\n<p>\u2714\ufe0f <strong>True<\/strong> \u2013 Each single bond with a Br counts as <strong>one electron domain<\/strong>.<br>So P has <strong>5 bonding domains<\/strong>, which gives it a <strong>trigonal bipyramidal<\/strong> geometry.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\u2705 Option D: <strong>&#8220;The formal charge on each atom is zero.&#8221;<\/strong><\/h3>\n\n\n\n<p>\u2714\ufe0f <strong>True<\/strong> \u2013 The formal charges are:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>P: 5 valence electrons \u2013 0 lone pair electrons \u2013 5 bonds = 0<\/li>\n\n\n\n<li>Br: 7 valence electrons \u2013 6 lone pair electrons \u2013 1 bond = 0<\/li>\n<\/ul>\n\n\n\n<p>So all atoms have a <strong>formal charge of zero<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">\ud83e\udde0 Conclusion:<\/h3>\n\n\n\n<p><strong>Option B is false<\/strong> because phosphorus in PBr\u2085 does <strong>not<\/strong> have any <strong>unpaired electrons<\/strong>\u2014it uses all of them to form bonds with the five bromine atoms.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Which of the following is FALSE regarding the Lewis structure for PBr5?A The total number of valence electrons is 40.B There are unpaired electrons on the central atom.C There are 5 electron domains around the central atom.D The formal charge on each atom is zero. The correct answer and explanation is : The **correct answer [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-207762","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/207762","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=207762"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/207762\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=207762"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=207762"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=207762"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}