What will the following formula return? =INDEX(A5:H448,5,6)
The number of characters across the given array in row 5, column 6.
The value of the cell in row 5, column 6 across the given array.
The value of the cell in row 6, column 5 across the given array.
The number of occurrences of the value in row 6, column 5 across the given array.<\/p>\n\n\n\n
The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n The correct answer is:<\/p>\n\n\n\n The value of the cell in row 5, column 6 across the given array.<\/strong><\/p>\n\n\n\n The formula in question is:<\/p>\n\n\n\n To understand what this formula returns, let’s break it down:<\/p>\n\n\n\n The The general syntax is:<\/p>\n\n\n\n Therefore, the formula returns the value<\/strong> located at the intersection of the 5th row and 6th column within the array<\/strong> This means it’s fetching the value in cell F9<\/strong>, since:<\/p>\n\n\n\n The value of the cell in row 5, column 6 across the given array.<\/strong><\/p>\n","protected":false},"excerpt":{"rendered":" What will the following formula return? =INDEX(A5:H448,5,6)The number of characters across the given array in row 5, column 6.The value of the cell in row 5, column 6 across the given array.The value of the cell in row 6, column 5 across the given array.The number of occurrences of the value in row 6, column 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\n\n\n\nExplanation:<\/strong><\/h3>\n\n\n\n
=INDEX(A5:H448,5,6)\n<\/code><\/pre>\n\n\n\n
\n\n\n\n1. The
INDEX<\/code> Function:<\/strong><\/h3>\n\n\n\nINDEX<\/code> function in Excel is used to return the value of a cell<\/strong> at a specific row<\/strong> and column<\/strong> within a specified range or array.<\/p>\n\n\n\nINDEX(array, row_num, [column_num])\n<\/code><\/pre>\n\n\n\n\n
array<\/code><\/strong> \u2013 the range of cells from which to retrieve a value.<\/li>\n\n\n\nrow_num<\/code><\/strong> \u2013 the row number in the array from which to return a value.<\/li>\n\n\n\ncolumn_num<\/code><\/strong> \u2013 the column number in the array from which to return a value.<\/li>\n<\/ul>\n\n\n\n
\n\n\n\n2. Analyzing the Formula:<\/strong><\/h3>\n\n\n\n
\n
A5:H448<\/code>
This array spans from column A to H (8 columns) and from row 5 to 448 (444 rows total).<\/li>\n\n\n\n5<\/code>
This refers to the 5th row within<\/em> the specified array. Since the array starts at row 5 of the worksheet, row_num = 5<\/code> refers to row 9<\/strong> of the worksheet.<\/li>\n\n\n\n6<\/code>
This refers to the 6th column in the array. Since the array starts at column A, column 6 corresponds to column F<\/strong>.<\/li>\n<\/ul>\n\n\n\n
\n\n\n\n3. Result of the Formula:<\/strong><\/h3>\n\n\n\n
A5:H448<\/code>.<\/p>\n\n\n\n\n
\n\n\n\n4. Elimination of Other Options:<\/strong><\/h3>\n\n\n\n
\n
INDEX<\/code> does not count characters.<\/li>\n\n\n\nINDEX(A5:H448,6,5)<\/code>.<\/li>\n\n\n\nINDEX<\/code> does not count occurrences; COUNTIF<\/code> or COUNTIFS<\/code> would be used instead.<\/li>\n<\/ul>\n\n\n\n
\n\n\n\n\u2705 Final Answer:<\/h3>\n\n\n\n