{"id":207822,"date":"2025-04-25T12:59:52","date_gmt":"2025-04-25T12:59:52","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=207822"},"modified":"2025-04-25T12:59:54","modified_gmt":"2025-04-25T12:59:54","slug":"what-is-the-oxidation-number-of-sulfur-s-in-al2so33","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/04\/25\/what-is-the-oxidation-number-of-sulfur-s-in-al2so33\/","title":{"rendered":"What is the oxidation number of sulfur (S) in Al2(SO3)3"},"content":{"rendered":"\n<p>What is the oxidation number of sulfur (S) in Al2(SO3)3?<br>0-2<br>0-6<br>O-4<br>+4<br>+6<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>The correct answer is: <strong>+4<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation (300+ words):<\/h3>\n\n\n\n<p>To determine the <strong>oxidation number of sulfur (S)<\/strong> in <strong>Al\u2082(SO\u2083)\u2083<\/strong>, we need to break down the compound and apply some basic rules of oxidation numbers.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 1: Understand the compound<\/h3>\n\n\n\n<p>The compound <strong>Al\u2082(SO\u2083)\u2083<\/strong> is aluminum sulfite. It contains:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Aluminum ions (Al\u00b3\u207a)<\/strong><\/li>\n\n\n\n<li><strong>Sulfite ions (SO\u2083\u00b2\u207b)<\/strong><\/li>\n<\/ul>\n\n\n\n<p>There are <strong>2 aluminum atoms<\/strong> and <strong>3 sulfite ions<\/strong> in one formula unit.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 2: Rules of oxidation numbers<\/h3>\n\n\n\n<p>Here are the key oxidation number rules we&#8217;ll use:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li>The oxidation number of <strong>Aluminum (Al)<\/strong> in a compound is <strong>+3<\/strong>.<\/li>\n\n\n\n<li>The oxidation number of <strong>Oxygen (O)<\/strong> is usually <strong>-2<\/strong>.<\/li>\n\n\n\n<li>The <strong>sum of oxidation numbers<\/strong> in a <strong>polyatomic ion<\/strong> is equal to the charge of the ion.<\/li>\n\n\n\n<li>In a <strong>neutral compound<\/strong>, the sum of all oxidation numbers must equal <strong>zero<\/strong>.<\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 3: Focus on the SO\u2083\u00b2\u207b ion<\/h3>\n\n\n\n<p>We&#8217;re interested in the oxidation number of sulfur (S) in the <strong>sulfite ion (SO\u2083\u00b2\u207b)<\/strong>.<\/p>\n\n\n\n<p>Let the oxidation number of sulfur be <strong>x<\/strong>.<\/p>\n\n\n\n<p>Each oxygen contributes <strong>-2<\/strong>, and there are <strong>3 oxygen atoms<\/strong>:<br>[<br>x + 3(-2) = -2<br>]<br>[<br>x &#8211; 6 = -2<br>]<br>[<br>x = +4<br>]<\/p>\n\n\n\n<p>So, the oxidation number of <strong>sulfur in SO\u2083\u00b2\u207b is +4<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Step 4: Confirm with the entire compound<\/h3>\n\n\n\n<p>In <strong>Al\u2082(SO\u2083)\u2083<\/strong>:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>2 aluminum atoms = 2(+3) = +6<\/li>\n\n\n\n<li>3 sulfite ions = 3(\u20132) = \u20136<\/li>\n<\/ul>\n\n\n\n<p>Total charge: +6 (from Al) + (\u20136) (from sulfite) = <strong>0<\/strong>, as expected for a neutral compound.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\">Summary:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The oxidation number of sulfur in the <strong>sulfite ion (SO\u2083\u00b2\u207b)<\/strong> is <strong>+4<\/strong>.<\/li>\n\n\n\n<li>Therefore, in <strong>Al\u2082(SO\u2083)\u2083<\/strong>, sulfur has an oxidation number of <strong>+4<\/strong>.<\/li>\n\n\n\n<li>Correct answer: <strong>+4<\/strong> \u2705<\/li>\n<\/ul>\n\n\n\n<p>This process helps ensure we understand redox chemistry, ionic charges, and oxidation states within polyatomic ions and complex compounds.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>What is the oxidation number of sulfur (S) in Al2(SO3)3?0-20-6O-4+4+6 The correct answer and explanation is : The correct answer is: +4 Explanation (300+ words): To determine the oxidation number of sulfur (S) in Al\u2082(SO\u2083)\u2083, we need to break down the compound and apply some basic rules of oxidation numbers. Step 1: Understand the compound [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-207822","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/207822","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=207822"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/207822\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=207822"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=207822"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=207822"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}