{"id":208088,"date":"2025-04-26T07:34:45","date_gmt":"2025-04-26T07:34:45","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=208088"},"modified":"2025-04-26T07:34:46","modified_gmt":"2025-04-26T07:34:46","slug":"the-ph-of-a-solution-in-which-oh-3-1x10-4m","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/04\/26\/the-ph-of-a-solution-in-which-oh-3-1x10-4m\/","title":{"rendered":"The pH of a solution in which [OH-]=3.1&#215;10^-4M"},"content":{"rendered":"\n<p class=\"wp-block-paragraph\">The pH of a solution in which [OH-]=3.1&#215;10^-4M<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Alright, let&#8217;s dive into this carefully:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">First, to find the <strong>pH<\/strong> from a given hydroxide ion concentration ([OH^-]), we use the following steps:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Find the pOH<\/strong> using the formula:<br>[<br>\\text{pOH} = -\\log [\\text{OH}^-]<br>]<\/li>\n\n\n\n<li><strong>Find the pH<\/strong> using the relation:<br>[<br>\\text{pH} + \\text{pOH} = 14<br>]<\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p class=\"wp-block-paragraph\">Given:<br>[<br>[\\text{OH}^-] = 3.1 \\times 10^{-4} \\, \\text{M}<br>]<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">First, calculate the pOH:<br>[<br>\\text{pOH} = -\\log (3.1 \\times 10^{-4})<br>]<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Using log rules:<br>[<br>\\log (3.1 \\times 10^{-4}) = \\log(3.1) + \\log(10^{-4})<br>]<br>[<br>= \\log(3.1) &#8211; 4<br>]<br>[<br>\\log(3.1) \\approx 0.491<br>]<br>Thus,<br>[<br>\\text{pOH} = -(0.491 &#8211; 4) = 3.509<br>]<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Now, use the relationship between pH and pOH:<br>[<br>\\text{pH} = 14 &#8211; \\text{pOH}<br>]<br>[<br>\\text{pH} = 14 &#8211; 3.509<br>]<br>[<br>\\text{pH} = 10.491<br>]<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Thus, <strong>the pH is approximately 10.49<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>300-word explanation<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Understanding the pH of a solution is crucial in chemistry as it tells us how acidic or basic a solution is. In this question, we were given the concentration of hydroxide ions, ([OH^-]), which directly relates to the basicity of the solution.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">The pOH is the negative logarithm (base 10) of the hydroxide ion concentration. The &#8220;p&#8221; in pOH or pH stands for &#8220;power,&#8221; reflecting the exponent in the scientific notation of the concentration. Calculating the pOH first is necessary because the relationship between pH and pOH is straightforward: their sum is always 14 at 25\u00b0C. This relationship is derived from the ion-product constant for water, (K_w = [H^+][OH^-] = 1.0 \\times 10^{-14}).<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">In this case, we took the ([OH^-]) concentration, (3.1 \\times 10^{-4}), and found its negative logarithm to get the pOH, which turned out to be approximately 3.509. Afterward, we used the key formula ( \\text{pH} + \\text{pOH} = 14 ) to solve for pH, resulting in a pH of about 10.49.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Since the pH is greater than 7, the solution is basic, which makes sense given the high ([OH^-]) concentration. Generally, pH values below 7 indicate acidity, a pH of 7 is neutral (like pure water), and pH values above 7 show basicity.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">This process is fundamental in fields like biochemistry, environmental science, and medicine, where the pH of solutions can influence chemical reactions, biological activity, and environmental conditions.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n","protected":false},"excerpt":{"rendered":"<p>The pH of a solution in which [OH-]=3.1&#215;10^-4M The correct answer and explanation is : Alright, let&#8217;s dive into this carefully: First, to find the pH from a given hydroxide ion concentration ([OH^-]), we use the following steps: Given:[[\\text{OH}^-] = 3.1 \\times 10^{-4} \\, \\text{M}] First, calculate the pOH:[\\text{pOH} = -\\log (3.1 \\times 10^{-4})] Using [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-208088","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/208088","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=208088"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/208088\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=208088"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=208088"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=208088"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}