{"id":208481,"date":"2025-04-27T11:30:19","date_gmt":"2025-04-27T11:30:19","guid":{"rendered":"https:\/\/learnexams.com\/blog\/?p=208481"},"modified":"2025-04-27T11:30:21","modified_gmt":"2025-04-27T11:30:21","slug":"given-the-following-acid-with-ka-values","status":"publish","type":"post","link":"https:\/\/www.learnexams.com\/blog\/2025\/04\/27\/given-the-following-acid-with-ka-values\/","title":{"rendered":"Given the following acid with Ka values"},"content":{"rendered":"\n<p>Given the following acid with Ka values.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>HClO4 1&#215;10<sup>7<\/sup><\/li>\n\n\n\n<li>HOAc 1.76&#215;10<sup>-5<\/sup><\/li>\n\n\n\n<li>HCN 4.93&#215;10<sup>-10<\/sup><\/li>\n\n\n\n<li>HF 3.53&#215;10<sup>-4<\/sup><\/li>\n<\/ul>\n\n\n\n<p>What is the order of increasing base strength?<\/p>\n\n\n\n<p>Can someone explain how they solved this problem?<\/p>\n\n\n\n<p><mark style=\"background-color:rgba(0, 0, 0, 0)\" class=\"has-inline-color has-ast-global-color-6-color\"><strong>The correct answer and explanation is :<\/strong><\/mark><\/p>\n\n\n\n<p>To determine the order of increasing base strength based on the provided (K_a) values, we first need to understand the relationship between the acid strength and base strength.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Key Concept:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The <strong>acid dissociation constant (Ka)<\/strong> measures how strong an acid is. The higher the (K_a), the stronger the acid.<\/li>\n\n\n\n<li>The <strong>base dissociation constant (Kb)<\/strong> measures the strength of the conjugate base of an acid. It is related to the acid dissociation constant by the equation:<br>[<br>K_b = \\frac{K_w}{K_a}<br>]<br>where (K_w) is the ionization constant for water, (K_w = 1 \\times 10^{-14}) at 25\u00b0C.<\/li>\n\n\n\n<li>The <strong>stronger the acid<\/strong>, the weaker the conjugate base. This means that acids with higher (K_a) values will have weaker conjugate bases (lower (K_b) values), and vice versa.<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Step-by-step Explanation:<\/h3>\n\n\n\n<p>We are given the following acids and their respective (K_a) values:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>Perchloric acid (HClO4):<\/strong> (K_a = 1 \\times 10^7)<\/li>\n\n\n\n<li><strong>Acetic acid (HOAc):<\/strong> (K_a = 1.76 \\times 10^{-5})<\/li>\n\n\n\n<li><strong>Hydrocyanic acid (HCN):<\/strong> (K_a = 4.93 \\times 10^{-10})<\/li>\n\n\n\n<li><strong>Hydrofluoric acid (HF):<\/strong> (K_a = 3.53 \\times 10^{-4})<\/li>\n<\/ol>\n\n\n\n<p>To find the order of increasing base strength, we calculate (K_b) for each conjugate base using the formula (K_b = \\frac{K_w}{K_a}):<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li><strong>For HClO4:<\/strong><br>[<br>K_b = \\frac{1 \\times 10^{-14}}{1 \\times 10^7} = 1 \\times 10^{-21}<br>]<\/li>\n\n\n\n<li><strong>For HOAc:<\/strong><br>[<br>K_b = \\frac{1 \\times 10^{-14}}{1.76 \\times 10^{-5}} \\approx 5.68 \\times 10^{-10}<br>]<\/li>\n\n\n\n<li><strong>For HCN:<\/strong><br>[<br>K_b = \\frac{1 \\times 10^{-14}}{4.93 \\times 10^{-10}} \\approx 2.03 \\times 10^{-5}<br>]<\/li>\n\n\n\n<li><strong>For HF:<\/strong><br>[<br>K_b = \\frac{1 \\times 10^{-14}}{3.53 \\times 10^{-4}} \\approx 2.83 \\times 10^{-11}<br>]<\/li>\n<\/ol>\n\n\n\n<p>Now, we arrange the (K_b) values in order of increasing size (because higher (K_b) values correspond to stronger bases):<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>(K_b) for HClO4 = (1 \\times 10^{-21}) (weakest base)<\/li>\n\n\n\n<li>(K_b) for HF = (2.83 \\times 10^{-11})<\/li>\n\n\n\n<li>(K_b) for HOAc = (5.68 \\times 10^{-10})<\/li>\n\n\n\n<li>(K_b) for HCN = (2.03 \\times 10^{-5}) (strongest base)<\/li>\n<\/ul>\n\n\n\n<h3 class=\"wp-block-heading\">Final Answer:<\/h3>\n\n\n\n<p>The order of increasing base strength is:<br><strong>HClO4 &lt; HF &lt; HOAc &lt; HCN<\/strong><\/p>\n\n\n\n<h3 class=\"wp-block-heading\">Explanation:<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>HClO4<\/strong> is the strongest acid (highest (K_a)), so its conjugate base is the weakest.<\/li>\n\n\n\n<li><strong>HCN<\/strong> is the weakest acid (lowest (K_a)), so its conjugate base is the strongest.<\/li>\n\n\n\n<li>The base strength increases as the (K_a) value decreases, following the inverse relationship between acid strength and base strength.<\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>Given the following acid with Ka values. What is the order of increasing base strength? Can someone explain how they solved this problem? The correct answer and explanation is : To determine the order of increasing base strength based on the provided (K_a) values, we first need to understand the relationship between the acid strength [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"default","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","ast-disable-related-posts":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-opacity":"","overlay-gradient":""}},"footnotes":""},"categories":[25],"tags":[],"class_list":["post-208481","post","type-post","status-publish","format-standard","hentry","category-exams-certification"],"_links":{"self":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/208481","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/comments?post=208481"}],"version-history":[{"count":0,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/posts\/208481\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/media?parent=208481"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/categories?post=208481"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.learnexams.com\/blog\/wp-json\/wp\/v2\/tags?post=208481"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}